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Q8.36:
In the organic compound $CH_2 = CH – CH_2 – CH_2 – C \equiv CH$, the pair of hydridised orbitals involved in the formation of: $C_2 – C_3$ bond is:

Solution :

Step 1: Structural Representation and Carbon Numbering

To determine the hybridization of the atoms involved in the $C_2-C_3$ bond, we first expand the condensed formula of the molecule $CH_2=CH-CH_2-CH_2-C \equiv CH$ to assign numbering according to IUPAC nomenclature rules, ensuring the multiple bonds receive the lowest possible locants.

The structure is as follows:

C1 C2 C3 C4 C5 C6

Step 2: Determining Hybridization State of C2 and C3

We apply the Valence Shell Electron Pair Repulsion (VSEPR) theory to identify the hybridization state [Per the Hybridization Theory]:

  • Carbon 2 ($C_2$): The carbon is bonded to one hydrogen (not shown in backbone), one $C_1$ (double bond), and one $C_3$ (single bond). It participates in one $\pi$ bond and three $\sigma$ bonds. Therefore, $C_2$ is $sp^2$ hybridized.
  • Carbon 3 ($C_3$): The carbon is bonded to two hydrogens and two carbons ($C_2$ and $C_4$) via single bonds. It participates in four $\sigma$ bonds. Therefore, $C_3$ is $sp^3$ hybridized.

Step 3: Analyzing the C2–C3 Bond Orbital Overlap

The chemical bond between $C_2$ and $C_3$ is a $\sigma$ bond formed by the axial overlap of hybrid orbitals from each carbon atom.

Atom Hybridization Orbital Involved
$C_2$ $sp^2$ $sp^2$ hybrid orbital
$C_3$ $sp^3$ $sp^3$ hybrid orbital

The formation of the $C_2-C_3$ bond is the result of the head-on overlap between an $sp^2$ hybrid orbital from Carbon-2 and an $sp^3$ hybrid orbital from Carbon-3 [By Linear Combination of Atomic Orbitals (LCAO)].

Final Solution: The pair of hybridized orbitals involved in the formation of the $C_2–C_3$ bond is $sp^2–sp^3$.


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