Gwalior

Subhankar replied | 1 day ago

The cell cycle consists of two main phases: interphase and M phase (mitotic phase). Interphase is further divided into G1, S, and G2 phases, while M phase includes mitosis (prophase, metaphase, anaphase, and telophase) and cytokinesis. 

Md Razi Ahmad replied | 1 day ago

The cell cycle consists of two main phases: Interphase and M Phase (Mitotic Phase).

Interphase is the longest phase where the cell grows and prepares for division. It has three sub-phases:

1. G₁ Phase (Gap 1) – The cell grows, synthesizes proteins, and performs normal functions.

2. S Phase (Synthesis) – DNA replication occurs; each chromosome forms two sister chromatids.

3. G₂ Phase (Gap 2) – The cell prepares for mitosis by producing organelles and enzymes needed for division.

After interphase, the cell enters the M Phase, which includes mitosis and cytokinesis. Mitosis has four stages:

1. Prophase – Chromosomes condense and become visible, spindle fibers form, and the nuclear envelope breaks down.

2. Metaphase – Chromosomes align at the cell's equator, attached to spindle fibers at the centromeres.

3. Anaphase – Sister chromatids separate and move to opposite poles of the cell.

4. Telophase – Chromatids reach poles, nuclear envelopes re-form around each set, an

d chromosomes decondense.

Krishnendu Gorai replied | 23 hrs ago

THE VALENCY OF CARBON IS 4.CATENATION PROPERTY OF CARBON LEADS TO FORMING LONG CHAIN COMPOUNDS.

Minhaj Hashim replied | 19 hrs ago

Valency of Carbon is 4. The key property that leads to form long chain compound is Catenation. Catenation is the ability of carbon to form strong covalent bonds with other carbon atoms, resulting in the formation of long chains, branched chains, and rings.

Reasons for Catenation in Carbon:

• Strong C–C bond strength (carbon-carbon single bond is stable).

• Tetravalency allows bonding with four other atoms, including carbon itself.

• Small atomic size leads to stable and strong covalent bonds

Hope it is clear!!

Sadiq replied | 5 days ago

Diameter of the circular tabletop = 1.6 m Radius of the circular tabletop = 1.6 m / 2 = 0.8 m Area of circular tabletop = πr 2 = 3.14 × 0.8 m × 0.8 m = 2.0096 m2 Since, the cost of 1m2 polishing = ₹ 15 The cost of polishing 2.0096 m2 = ₹ 15 × 2.0096 = ₹ 30.144 Thus, the cost of polishing a circular tabletop is ₹ 30.144.

Rajesh Kumar N replied | 2 days ago

Radius = 1.6 ÷ 2 = 0.8 m

Area = πr² = 3.14 × 0.8² = 3.14 × 0.64 = 2.0096 m²

Cost = 2.0096 × ₹15 ≈ ₹30.14

Answer: ₹30

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