An elevator weighs 3000kg. What is its acceleration when the in the tension supporting cable is 33000N. Given that g = 9.8m/s2.

Asked by Last Modified  

Follow 10
Answer

Please enter your answer

Tutor

M = 3000 kg g = 9.8 m/s² T = 33000 a = ? Ma = Mg - T 3000 * a = 3000 * 9.8 - 33000 3000a = 29400 - 33000 3000a = - 3600 a = - 1.2 m/s².
Comments

Life Skills Trainer

Mg - T = Ma 3000 * 9.8 - 33000 = 3000* a 29400 - 33000 = 3000 * a -3600/3000 = a a = - 1.2 m/s2
Comments

Given, Weight, M = 3000kg Tension, T = 33000N g = 9.8m/s^2 a= ? We have, Mg - T = Ma ie, (3000*9.8) - 33000 = 3000 * a a = ((3000*9.8) - 33000)/3000 = -1.2m/s^2 therefore the elevator is moving up with an acceleration of 1.2m/s^2
Comments

Physics Teacher

a=(33000-3000*9.8)/3000 m/s^2
Comments

Excellence Award Winner ( 7 times )

M = 3000 kg g = 9.8 m/s² T = 33000 a = ? Ma = Mg - T 3000 * a = 3000 * 9.8 - 33000 3000a = 29400 - 33000 3000a = - 3600 a = - 1.2 m/s² Therefore, the elevator will move up with an acceleration of 1.2 m/s²
Comments

Tutor.

F=m(a+g) a=11-9.8 1.2 m/s2
Comments

Mentor/ Tutor

33000-3000*9.8=3000*a 33000-29400=3000*a 3600/3000=a
Comments

33000-g.3000 = a.3000 With usual meaning of symbols. a negative means movement is downward & vice versa.
Comments

Physics - The Science Cube

Equate F (net) = ma Then T - mg = ma (assume all vectors in + Y direction as positive) 33000 - 3000 X 9.8 = 3000 a a = 1.2 m/s² This essentially means that the net force on the elevator is making it move up with an acceleration of 1.2 m/s² See my lecture notes for...
read more
Equate F (net) = ma Then T - mg = ma (assume all vectors in + Y direction as positive) 33000 - 3000 X 9.8 = 3000 a a = 1.2 m/s² This essentially means that the net force on the elevator is making it move up with an acceleration of 1.2 m/s² See my lecture notes for a better understanding read less
Comments

Tutor

M = 3000 kg, g = 9.8 m/s ,T = 33000 a = ? Ma = Mg - T 3000 * a = 3000 * 9.8 - 33000 3000a = 29400 - 33000 3000a = - 3600 a = - 1.2 m/s Therefore, the elevator will move up with an acceleration of 1.2 m/s.
Comments

View 8 more Answers

Related Questions

Why sky appears to be blue?
The phenomenon of scattering of light helps to explain the blue color of sky Scattering of light takes place when size of the scattering object (such as air molecules) is very very small as compared to...
Rohit Singh
What is the Young's modulus for a perfect rigid body?
We know that Young's Modulus is the ratio of stress and strain. But, for a perfectly rigid body, the strain is zero, since there are no change in dimensions. Hence, for a perfectly rigid body, the Young's...
Praseem
0 0
5

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons

Calculate the radii of (i) the third orbit of He+ ion and (ii) the second orbit of Li2+ ion.
QUESTION The radius of first Bohr orbit of hydrogen atom is 0.529 A. Calculate the radii of (i) the third orbit of He+ ion and (ii) the second orbit of Li2+ ion. ANSWER

A Brief Review of Atomic Models
Models of atom Definition: A model is a simplified representation of anything under consideration, to see how it should look like. In a similar manner, to comprehend...
A

Amandeep

0 0
0

NEET 2018 Solutions
This video gives explanatory solution to NEET 2018 Q.1 For physics section

Electrostatics
Electrostatics made of two words Electrostatics= Electro + statics Electro means Electron (charge) statics means in rest position so we can say that Electrostatics is the branch of Physics in which...

Oscillations Overview
https://vz-3ad30922-ba4.b-cdn.net/36e661e0-11b1-4bfb-9628-5f8fdf69b952/play_480p.mp4

Recommended Articles

Appearing for exams could be stressful for students. Even though they might have prepared well, they could suffer from anxiety, tension etc. These are not good for their health and mind. However, following a few exam preparation tips can save them from all these and help them to score good marks. Let’s find out all...

Read full article >

Quality education does not only help children to get a successful career and life, but it also hugely contributes to society. The formal education of every child starts from school. Although there are numerous schools, parents find it challenging to choose the right one that would fit their child. It is difficult for them...

Read full article >

Learning for every child starts from a very young age. While the formal methods include school curriculums and private lessons, the informal methods include dancing, music, drawing, and various fun-filling activities. Playing games and practising these types of activities helps the children get out of boredom and...

Read full article >

Once over with the tenth board exams, a heavy percentage of students remain confused between the three academic streams they have to choose from - science, arts or commerce. Some are confident enough to take a call on this much in advance. But there is no worry if as a student you take time to make choice between - science,...

Read full article >

Looking for Class 11 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you