An elevator weighs 3000kg. What is its acceleration when the in the tension supporting cable is 33000N. Given that g = 9.8m/s2.

Asked by Last Modified  

10 Answers

Learn Physics +1

Follow 10
Answer

Please enter your answer

Ravi Kumar Singh

Tutor

M = 3000 kg g = 9.8 m/s² T = 33000 a = ? Ma = Mg - T 3000 * a = 3000 * 9.8 - 33000 3000a = 29400 - 33000 3000a = - 3600 a = - 1.2 m/s².
Comments
Dislike Bookmark

Life Skills Trainer

Mg - T = Ma 3000 * 9.8 - 33000 = 3000* a 29400 - 33000 = 3000 * a -3600/3000 = a a = - 1.2 m/s2
Comments
Dislike Bookmark

Given, Weight, M = 3000kg Tension, T = 33000N g = 9.8m/s^2 a= ? We have, Mg - T = Ma ie, (3000*9.8) - 33000 = 3000 * a a = ((3000*9.8) - 33000)/3000 = -1.2m/s^2 therefore the elevator is moving up with an acceleration of 1.2m/s^2
Comments
Dislike Bookmark

Physics Teacher

a=(33000-3000*9.8)/3000 m/s^2
Comments
Dislike Bookmark

Excellence Award Winner ( 7 times )

M = 3000 kg g = 9.8 m/s² T = 33000 a = ? Ma = Mg - T 3000 * a = 3000 * 9.8 - 33000 3000a = 29400 - 33000 3000a = - 3600 a = - 1.2 m/s² Therefore, the elevator will move up with an acceleration of 1.2 m/s²
Comments
Dislike Bookmark

Tutor.

F=m(a+g) a=11-9.8 1.2 m/s2
Comments
Dislike Bookmark

Mentor/ Tutor

33000-3000*9.8=3000*a 33000-29400=3000*a 3600/3000=a
Comments
Dislike Bookmark

33000-g.3000 = a.3000 With usual meaning of symbols. a negative means movement is downward & vice versa.
Comments
Dislike Bookmark

Physics - The Science Cube

Equate F (net) = ma Then T - mg = ma (assume all vectors in + Y direction as positive) 33000 - 3000 X 9.8 = 3000 a a = 1.2 m/s² This essentially means that the net force on the elevator is making it move up with an acceleration of 1.2 m/s² See my lecture notes for...
read more
Equate F (net) = ma Then T - mg = ma (assume all vectors in + Y direction as positive) 33000 - 3000 X 9.8 = 3000 a a = 1.2 m/s² This essentially means that the net force on the elevator is making it move up with an acceleration of 1.2 m/s² See my lecture notes for a better understanding read less
Comments
Dislike Bookmark

Tutor

M = 3000 kg, g = 9.8 m/s ,T = 33000 a = ? Ma = Mg - T 3000 * a = 3000 * 9.8 - 33000 3000a = 29400 - 33000 3000a = - 3600 a = - 1.2 m/s Therefore, the elevator will move up with an acceleration of 1.2 m/s.
Comments
Dislike Bookmark

View 8 more Answers

Related Questions

What is the correct definition and formula of ohms law.?
At a constant temperature, the potential difference across A conductor is directly proportional to the Current passing through it. V ∝I, V=IR. V/I=R
Ajay Singh
What is the gravitatioal SI unit of work done?
It's joule .for all type of work done and energy .
Samrat
Sameer went on his bike from Delhi to Gurgaon at a speed of 60km/hr and came back at a speed of 40km/hr. What is his average speed for entire journey?
To find the average speed, you need to know the formula of average speed. The avg speed 0= 2 d / (t1+ t2) = 2 v1.v2/(V1 + V2). Just substitute the value.
Gowre
What are vectors?
https://vz-3ad30922-ba4.b-cdn.net/db7918fa-2411-444b-99eb-6fb412b9d10f/play_480p.mp4
Suryansh
Sun: Largest source of energy is made up of?
Organic molecules.hydrocarbons.fossil fuels.hydrogen and carbon mainly.
Deepika T.

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons

Introduction to motion in a plane : Position Vector, Velocity Vector, Acceleration Vector and two questions based on it.

Sunil Yadav

2 0
View Comments0
Thermal Properties of Matter Overview
https://vz-3ad30922-ba4.b-cdn.net/55e910f5-ad25-4b96-a398-dcfc3ef8709d/play_480p.mp4

Sahil Kalra

0 0
View Comments0
Ohm's law.
Ohm's law: "The potential difference (voltage) across an ideal conductor is directly proportional to the current through it." The constant of proportionality is called resistance'R'. Ohm's law is given...

Sashank

0 0
View Comments0
The Hidden Force Resisting Every Motion

Rakesh Nair

0 0
View Comments0
Vernier calipers and screw gauge Overview

Sahil Kalra

0 0
View Comments0

Recommended Articles

6 Exam Hall Tips To Follow, For Every Good Student

Appearing for exams could be stressful for students. Even though they might have prepared well, they could suffer from anxiety, tension etc. These are not good for their health and mind. However, following a few exam preparation tips can save them from all these and help them to score good marks. Let’s find out all...

Read full article >

How To Choose The Right School For Children?

Quality education does not only help children to get a successful career and life, but it also hugely contributes to society. The formal education of every child starts from school. Although there are numerous schools, parents find it challenging to choose the right one that would fit their child. It is difficult for them...

Read full article >

5 Engaging Activities For Children To Get...

Learning for every child starts from a very young age. While the formal methods include school curriculums and private lessons, the informal methods include dancing, music, drawing, and various fun-filling activities. Playing games and practising these types of activities helps the children get out of boredom and...

Read full article >

Science, Arts Or Commerce - Which One To Go For?

Once over with the tenth board exams, a heavy percentage of students remain confused between the three academic streams they have to choose from - science, arts or commerce. Some are confident enough to take a call on this much in advance. But there is no worry if as a student you take time to make choice between - science,...

Read full article >

Find Grade 11 Tuition near you
Grade 11 Tuition in Delhi
Grade 11 Tuition in Bangalore
Grade 11 Tuition in Hyderabad
Grade 11 Tuition in Mumbai
Grade 11 Tuition in Kolkata
Grade 11 Tuition in Chennai
Grade 11 Tuition in Pune
Grade 11 Tuition in Gurgaon
Grade 11 Tuition in Noida
Grade 11 Tuition in Jaipur

Looking for Class 11 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you