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# A railway carriage of mass 9000 kg moving with a speed of 36 kmph collides with stationary carriage of the same mass. After the collision, the carriages get coupled and moved together. What is their common speed after collision? What type of collision is this?

Teacher!

The objects move together after the collision and have a common velocity. So it's a perfectly inelastic collision. To find the velocity we use Law of conservation of linear momentum. Given velocity v1= 36kmph = 36*5/18 = 10m/s M1v1 + m2 v2 = (m1+m2)v 9000*10 + 0 = (9000+9000)v V = 5m/s

The objects move together after the collision and have a common velocity. So it's a perfectly inelastic collision.

To find the velocity we use Law of conservation of linear momentum.

Given velocity v1= 36kmph = 36*5/18 = 10m/s

M1v1 + m2 v2 = (m1+m2)v

9000*10 + 0 = (9000+9000)v

V = 5m/s

Special faculty for Maths and Physics

Use conservation Law of linear momentum , Pi = Pf Pi = initial momentum = mV Pf = final momentum = ( m + m) V1 so, mV = ( m + m )V1 V1 = V/2 = 36/2 = 18 km/h speed after collision = 18 km/h this is an example of enelastic collision in this collision , energy not conserved , eg loss

Use conservation Law of linear momentum ,
Pi = Pf

Pi = initial momentum = mV
Pf = final momentum = ( m + m) V1

so, mV = ( m + m )V1
V1 = V/2 = 36/2 = 18 km/h
speed after collision = 18 km/h

this is an example of enelastic collision in this collision , energy not conserved , e
g loss

Physics teacher for Neet /Jee and Cbse board exam

5m/s

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It is perfectly in elastic collision .by momentum conservation theorem we can find out final velocity .

It is perfectly in elastic collision .by momentum conservation theorem we can find out final velocity .$Mv=2MV&space;where&space;v&space;is&space;initial&space;velocity&space;and&space;V&space;is&space;final&space;velocity&space;.final&space;velocity&space;will&space;be&space;equal&space;to&space;18&space;km/h$

Convert 36km/ h in m/s i.e 10 m/s. 9000(10)+9000(0)= (9000+9000)×u 90000+0= 18000u u = 90000/18000 U= 5 m/s Perfectly inelastic collision

Using Principle of Conservation of Momentum, P1=P2, ie, M1V1=M2V2=> (9000+0)*36 = (9000+9000)*V2=> 18 = V2Therefore, Velocity of joint carriage after the collision is 18 kmph. The objects move together after the collision and have a common velocity. So it's a perfectly inelastic collision.

Using Principle of Conservation of Momentum, P1=P2, ie, M1V1=M2V2
=> (9000+0)*36 = (9000+9000)*V2
=> 18 = V2
Therefore, Velocity of joint carriage after the collision is 18 kmph.

The objects move together after the collision and have a common velocity. So it's a perfectly inelastic collision.

Computer Science, Maths & Language Teacher

Common speed = 4.85 m/s This is an inelastic collision

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