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The objects move together after the collision and have a common velocity. So it's a perfectly inelastic collision. To find the velocity we use Law of conservation of linear momentum. Given velocity v1= 36kmph = 36*5/18 = 10m/s M1v1 + m2 v2 = (m1+m2)v 9000*10 + 0 = (9000+9000)v V = 5m/s

read more The objects move together after the collision and have a common velocity. So it's a perfectly inelastic collision.

To find the velocity we use Law of conservation of linear momentum.

Given velocity v1= 36kmph = 36*5/18 = 10m/s

M1v1 + m2 v2 = (m1+m2)v

9000*10 + 0 = (9000+9000)v

V = 5m/s

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Comments

Use conservation Law of linear momentum , Pi = Pf Pi = initial momentum = mV Pf = final momentum = ( m + m) V1 so, mV = ( m + m )V1 V1 = V/2 = 36/2 = 18 km/h speed after collision = 18 km/h this is an example of enelastic collision in this collision , energy not conserved , eg loss

read more Use conservation Law of linear momentum ,

Pi = Pf

Pi = initial momentum = mV

Pf = final momentum = ( m + m) V1

so, mV = ( m + m )V1

V1 = V/2 = 36/2 = 18 km/h

speed after collision = 18 km/h

this is an example of enelastic collision in this collision , energy not conserved , e

g loss

1

Comments

Using Principle of Conservation of Momentum, P1=P2, ie, M1V1=M2V2=> (9000+0)*36 = (9000+9000)*V2=> 18 = V2Therefore, Velocity of joint carriage after the collision is 18 kmph. The objects move together after the collision and have a common velocity. So it's a perfectly inelastic collision.

read more Using Principle of Conservation of Momentum, P1=P2, ie, M1V1=M2V2

=> (9000+0)*36 = (9000+9000)*V2

=> 18 = V2

Therefore, Velocity of joint carriage after the collision is 18 kmph.

The objects move together after the collision and have a common velocity. So it's a perfectly inelastic collision.

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Comments

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