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Patpar Ganj, Delhi Details verified of Nitesh Rai✕
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HNB University 2015
Master of Science (M.Sc.)
APTECH 2012
ADSE
Patpar Ganj, Delhi, India - 110092
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Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 6 Tuition
1
Board
ICSE, CBSE, State
Subjects taught
Physics, Chemistry, Mathematics, Science
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 7 Tuition
1
Board
ICSE, CBSE, State
Subjects taught
Mathematics, Chemistry, Physics, Science
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
1
Board
ICSE, CBSE, State
Subjects taught
Physics, Science, Chemistry, Mathematics
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
1
Board
ISC/ICSE, CBSE, State
Subjects taught
Physics, Mathematics
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
ISC/ICSE, CBSE, State
Subjects taught
Physics, Mathematics
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in BSc Tuition
1
BSc Physics Subjects
Electricity and Magnetism, Digital Electronics, Mathematics, Solid State Physics, Mathematical Physics, Numerical Analysis, Electromagnetic Theory
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions, Group Classes
Taught in School or College
Yes
BSc Branch
BSc Physics
Answered on 24/03/2018 Learn CBSE - Class 11/Physics
Ask a Question
Post a Lesson
A.Energy of the photon (E) = hν = hc/λ = (6.626×10-34 Js×3.0×108 ms-1)/
= 4.97×10-19/1.602×10-19 eV
B.Kinetic energy of emission (1/2 mv2) = hν- hνo = 3.10-2.13 = 0.97 eV
C.1/2 mv2 = 0.97 eV = 0.97×1.602×10-19 J
⇒ 1/2×(9.11×10-31 kg)×v2 = 0.97×1.602×10-19 J
⇒ v2 = 0.341×1012 = 34.1×1010
⇒ v = 5.84×105 ms-1
Like 0 
Answers 26 
Comments Answered on 23/03/2018 Learn CBSE - Class 11/Physics
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Like 0 Answers 9 Comments Answered on 23/03/2018 Learn CBSE - Class 11/Physics
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Like 0 Answers 13 Comments Answered on 23/03/2018 Learn CBSE - Class 11/Physics
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Like 0 Answers 20 Comments Answered on 20/03/2018 Learn CBSE - Class 11/Physics
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Like 1 Answers 9 Comments Ask a Question
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Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 6 Tuition
1
Board
ICSE, CBSE, State
Subjects taught
Physics, Chemistry, Mathematics, Science
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 7 Tuition
1
Board
ICSE, CBSE, State
Subjects taught
Mathematics, Chemistry, Physics, Science
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
1
Board
ICSE, CBSE, State
Subjects taught
Physics, Science, Chemistry, Mathematics
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
1
Board
ISC/ICSE, CBSE, State
Subjects taught
Physics, Mathematics
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
ISC/ICSE, CBSE, State
Subjects taught
Physics, Mathematics
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in BSc Tuition
1
BSc Physics Subjects
Electricity and Magnetism, Digital Electronics, Mathematics, Solid State Physics, Mathematical Physics, Numerical Analysis, Electromagnetic Theory
Type of class
Regular Classes
Class strength catered to
One on one/ Private Tutions, Group Classes
Taught in School or College
Yes
BSc Branch
BSc Physics
Answered on 24/03/2018 Learn CBSE - Class 11/Physics
Ask a Question
Post a Lesson
A.Energy of the photon (E) = hν = hc/λ = (6.626×10-34 Js×3.0×108 ms-1)/
= 4.97×10-19/1.602×10-19 eV
B.Kinetic energy of emission (1/2 mv2) = hν- hνo = 3.10-2.13 = 0.97 eV
C.1/2 mv2 = 0.97 eV = 0.97×1.602×10-19 J
⇒ 1/2×(9.11×10-31 kg)×v2 = 0.97×1.602×10-19 J
⇒ v2 = 0.341×1012 = 34.1×1010
⇒ v = 5.84×105 ms-1
Like 0 Answers 26 Comments Answered on 23/03/2018 Learn CBSE - Class 11/Physics
Ask a Question
Post a Lesson
Like 0 Answers 9 Comments Answered on 23/03/2018 Learn CBSE - Class 11/Physics
Ask a Question
Post a Lesson
Like 0 Answers 13 Comments Answered on 23/03/2018 Learn CBSE - Class 11/Physics
Ask a Question
Post a Lesson
Like 0 Answers 20 Comments Answered on 20/03/2018 Learn CBSE - Class 11/Physics
Ask a Question
Post a Lesson
Like 1 Answers 9 Comments Ask a Question
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