Find the best tutors and institutes for Class 12 Tuition

Find Best Class 12 Tuition

Please select a Category.

Please select a Locality.

No matching category found.

No matching Locality found.

Outside India?

Search for topics

A photon of wavelength 4.0 x m strikes on metal surface, the work function of the metal being 2.13 eV. Calculate:

i. The energy of the photon (eV).

ii. The kinetic energy of the emission.

Iii. The velocity of the photoelectron.

Asked by Last Modified  

CBSE/Class 11/Science/Physics Tuition/Class IX-X Tuition

Follow 21
Answer

21 Answers

Please enter your answer

Great Place To Be Learn

Comments

Tutor

I) E = hv/wavelength =(6.626*10^-34)(3*10^8)/4*10^-7 = 4.9695*10^-19J ii)K.E=4.9695*10^-19/1.60*10^-19 =3.105eV
Comments

1. 4.97 ×10-19 / 1.602 ×10-19 eV 2. 0.97eV 3. 5084×105 ms-1
Comments

Tutor

Energy of photon= hc/λ h=plank constant = 6.63* h*c= 1240 eV λ= wavelength of light E= / J E=3.102 eV 2.)Kinetic energy of emission= energy of photon- work function =3.102-2.13 eV = 0.972 eV 3.) kinetic energy of... read more

Energy of photon= hc/λ

h=plank constant = 6.63*

h*c= 1240 eV

λ= wavelength of light

E= / J

E=3.102 eV

2.)Kinetic energy of emission= energy of photon- work function

                                      =3.102-2.13 eV

                                      = 0.972 eV

3.) kinetic energy of electron = 1/2*m* = 0.972 eV

                                                   v=

                                                      =5.84 m/s

read less
Comments

Tutor

Comments

Tutor

I) E = hv/wavelength =(6.626*10^-34)(3*10^8)/4*10^-7 = 4.969*10^-19 J
Comments

Home Tutor

Energy of photon= hc/λ h=plank constant = 6.63* c=speed of light=3* h*c= 1240 eV λ= wavelength of light E= / joule E=3.102 eV 2.)Kinetic energy of emission= energy of photon- work function =3.102-2.13 eV ... read more

Energy of photon= hc/λ

h=plank constant = 6.63*

c=speed of light=3*

h*c= 1240 eV

λ= wavelength of light

E= / joule

E=3.102 eV

2.)Kinetic energy of emission= energy of photon- work function

                                      =3.102-2.13 eV

                                      = 0.972 eV

3.)Velocity of free Electrons 

kinetic energy of electron = 1/2*m* = 0.972 eV

                                                   v=

                                                      =5.84 m/s

 

read less
Comments

Tutor

E=hc/wavelength=3.10ev K.E. of photoelectron = (KE of incident photon) - (Work Function of Metal)=3.10-2.13=0.87ev Velocity of photoelctron={2*k.E/m}^{0.5}=30um/sec
Comments

Tutor

(1) Energy of the photon (E) = hν = hc/λ = (6.626×10-34 Js×3.0×108 ms-1)/4×10-7 m = 4.97×10-19 J= 4.97×10-19/1.602×10-19 eV (2) Kinetic energy of emission (1/2 mv2) = hν- hνo = 3.10-2.13 = 0.97 eV (3) 1/2 mv2 = 0.97 eV = 0.97×1.602×10-19... read more

(1) Energy of the photon (E) = hν = hc/λ = (6.626×10-34 Js×3.0×10ms-1)/4×10-7 m = 4.97×10-19 J
= 4.97×10-19/1.602×10-19 eV


(2) Kinetic energy of emission (1/2 mv2) = hν- hνo = 3.10-2.13 = 0.97 eV


(3) 1/2 mv= 0.97 eV = 0.97×1.602×10-19 J
⇒ 1/2×(9.11×10-31 kg)×v= 0.97×1.602×10-19 J
⇒ v= 0.341×1012 = 34.1×1010
⇒ v = 5.84×10ms-1

read less
Comments

First of all we have to find the enenry(E) of Photon by using the Formula E=hc/λ here 'h' is the Plank's constant. 'c' is the Speed of light and λ is the wavelength Now we have to think what is the term "WORK FUNCTION" used in the Question WORK FUNCTION is the MINIMUM amount of... read more

First of all we have to find the enenry(E) of Photon by using the Formula

E=hc/λ

here 'h' is the Plank's constant. 

'c' is the Speed of light

and λ is the wavelength

 

Now we have to think what is the term "WORK FUNCTION" used in the Question

WORK FUNCTION is the MINIMUM amount of energy required to release a ELECTRON from the Metal

It is given in the Question

 

Now we are able to give the answer of the 2nd part of the Question

i.e Kinetic energy of emission== Total energy of photon- Energy required for emission(work function)

 

Now the question is WHAT IS THE VELOCITY OF PHOTOELECTRON??

From 2nd part of Question We know the Kinetic Energy of Photoelectron.

Use the formula,

K.E= ½*mass*(velocity)²

for the value of "mass of electron" , "plank's constant" and "velocity of light "use your book.

 

THANK YOU

read less
Comments

View 19 more Answers

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons

Let's check your brain
Define static electricity. Define Eddy current. What is the difference between displacement and distance?
A

Ashim Rana | 09 Oct

0 0
0

Kinematics Equation for 1 - D Motion with constant acceleration
1.3 EQUATIONS FOR RECTILINEAR MOTION If a particle changes its velocity from u to v in time t, with uniform acceleration a and undergoes a displacement S in that time, then (a) v = u +...

Hans Kumar | 21 Sep

0 0
0

Kinematics Parameters
1.1 SOME DEFINITIONS (a) Distance: Distance between two points is the length of actual path travelled by the particle. It is a scalar quantity. Unit : m(metre) (b) Displacement: Displacement...

Hans Kumar | 21 Sep

0 0
0

Recommended Articles

It is very common for a child to complain that they are bored. Elders remain engrossed in their hectic schedule and children are the most affected ones. When in school, though they keep a busy schedule, but what next? After coming home, today s generation spends maximum time with nannies or caretakers. While the latter...

Read full article >

With the current trend of the world going digital, electronic renaissance is a new movement that is welcomed by the new generation as it helps makes the lives of millions of people easier and convenient. Along with this rapidly changing movement and gaining popularity of Internet, e-Learning is a new tool that emerging...

Read full article >

With the mushrooming of international and private schools, it may seem that the education system of India is healthy. In reality, only 29% of children are sent to the private schools, while the remaining head for government or state funded education. So, to check the reality of Indian education system it is better to look...

Read full article >

If the internet has made it s way to all aspects of human life, no far stands classrooms from it. The boons of internet have entered the classrooms in the form of devices and this penetration of technology in the academic system is termed as e-learning. E-learning is a kind of teaching where computers with internet connection...

Read full article >

Looking for Class 12 Tuition ?

Find best Class 12 Tuition in your locality on UrbanPro.

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you

Find Best Class 12 Tuition ?

Find Now »

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 25 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 6.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more