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Class 10 > Find the area of an isoscles triangle with two equal...
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Find the area of an isoscles triangle with two equal sides as 5 cm each and the third side as 8 cm.

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atics pecialise in mba / economics students of all levels

20 Cms =area of isoceles triangle..
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Mathematics Professor

Let?ABC be required triangle AB=AC=5cm BC=8 cm Let AD be the altitude We know that perpendicular drawn from vertex bisect the base. Therefore BD=4 cm Using Pythagoras theorem we get AD= 3 cm Area of ?ABC=1/2 × base×height =1/2×8×3=12 cm2
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Let?ABC be required triangle AB=AC=5cm BC=8 cm Let AD be the altitude We know that perpendicular drawn from vertex bisect the base. Therefore BD=4 cm Using Pythagoras theorem we get AD= 3 cm Area of ?ABC=1/2 × base×height =1/2×8×3=12 cm2 read less
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Maths Magacian

Perpendicular on base of isoceles triangle bisect the third side. So using pythagoras we get height = 3 cm Now area of triangle= 1/2 *height *base =1/2*8*3=12 sq cm
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Maths Magacian

Perpendicular on base of isoceles triangle bisect the third side. So using pythagoras we get height = 3 cm Now area of triangle= 1/2 *height *base =1/2*8*3=12 sq cm
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Maths Magacian

Perpendicular on base of isoceles triangle bisect the third side. So using pythagoras we get height = 3 cm Now area of triangle= 1/2 *height *base =1/2*8*3=12 sq cm
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