Solve : x + y = 18; y + z = 12; z + x = 16

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Balaji Puppala

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Let x+y=18---(1), y+z=12---(2),z+x=16---(3) Solving (2)-(3) we get y+z-z-x=12-16 y-x=-4--(4) Solving (4)+(5) we get x+y+y-x=18-4 2y=14 y=14/2=7 Substitute y value in (1) x+7=18 x=18-7=11 Substitute x value in (3) z+11=16 z=16-11=5 x=11, y=7, z=5
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(X+y)+(y+z)+(z+x)=46 2(x+y+z)=46 X+y+z=23 ...................we know x+y=18 18+z=23 we get z=5 .................
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Put x =11,y=7,z=5
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z=5,y=7,x=11
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x+y +y+z+z+x=18+12+16 or,2(x+y+z)=46 or x+y+z=23....x=11,y=7,z=5
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