Find the cost of polishing a circular table-top of diameter 1.6 m, if the rate of polishing is ` 15/m2. (Take (π) = 3.14)

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Saurav

M.SC MATHS from JAMIA MILLIA ISLAMIA, NEW DELHI, 6+Years of Teaching Experience.

Diameter=1.6m Radius r=1.6÷2=0.8m Rate of polishing= 15/m² Area of table=πr²=3.14×0.8×0.8=2.0096m² Now Cost=2.0096×15=₹30.14
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M.SC MATHS from JAMIA MILLIA ISLAMIA, NEW DELHI, 6+Years of Teaching Experience.

Diameter of the table = 1.6m Radius r=0.8m Rate of polishing = ₹15/m² Area of table =𝜋𝑟²=3.14×(0.8)²=3.14× 0.64=2.0096m²   Cost 2.0096×15=₹30.14 approx
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Diameter of the circular tabletop = 1.6 m Radius of the circular tabletop = 1.6 m / 2 = 0.8 m Area of circular tabletop = πr 2 = 3.14 × 0.8 m × 0.8 m = 2.0096 m2 Since, the cost of 1m2 polishing = 15 The cost of polishing 2.0096 m2 = 15 × 2.0096 = ₹ 30.144
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Diameter of the circular tabletop = 1.6 m Radius of the circular tabletop = 1.6 m / 2 = 0.8 m Area of circular tabletop = πr 2 = 3.14 × 0.8 m × 0.8 m = 2.0096 m2 Since, the cost of 1m2 polishing = 15 The cost of polishing 2.0096 m2 = 15 × 2.0096 = ₹ 30.144 read less
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C language Faculty (online Classes )

Diameter of the circular tabletop = 1.6 m Radius of the circular tabletop = 1.6 m / 2 = 0.8 m Area of circular tabletop = πr 2 = 3.14 × 0.8 m × 0.8 m = 2.0096 m2 Since, the cost of 1m2 polishing = ₹ 15 The cost of polishing 2.0096 m2 = ₹ 15 × 2.0096 = ₹ 30.144 Thus, the cost of...
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Diameter of the circular tabletop = 1.6 m Radius of the circular tabletop = 1.6 m / 2 = 0.8 m Area of circular tabletop = πr 2 = 3.14 × 0.8 m × 0.8 m = 2.0096 m2 Since, the cost of 1m2 polishing = ₹ 15 The cost of polishing 2.0096 m2 = ₹ 15 × 2.0096 = ₹ 30.144 Thus, the cost of polishing a circular tabletop is ₹ 30.144. read less
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"Rajesh Kumar N: Guiding Young Minds from 1 to 12 with Expertise and Care"

Radius = 1.6 ÷ 2 = 0.8 m Area = πr² = 3.14 × 0.8² = 3.14 × 0.64 = 2.0096 m² Cost = 2.0096 × ₹15 ≈ ₹30.14 Answer: ₹30 .14
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