A person of mass 50 kg stands on a weighing scale on a lift. If the lift is descending with a downward acceleration of 9 m/s2 . What would be the reading of weighing scale?

Asked by Last Modified  

4 Answers

Learn Physics

Follow 3
Answer

Please enter your answer

A Retired Physics Teacher for NEET JEE, Board

Mg-N = Ma N=M(g-a) Where N= apparent weight or the reading on the weighing machine N= 50(9.8-9) =50×.,8 newton = 40/9.8 kg = 12newton
Comments

Mg(downward) - ma(pseudo force upward ) =weighing machine reading 50N-45N =5N( answer)
1 Comments

Tutor

Mass of the person, m = 50 kgDescending acceleration, a = 9 m/${{s}^{2}}$Acceleration due to gravity, g = 10 m/${{s}^{2}}$ Apparent weight of the person,R = m(g-a) =50(10-9) = 50N .’. Reading of the weighing scale =R/g =50/10 = 5 kg
Comments

Awarded as a Best Physics Teacher from IIT

Since lift is descendin so the downward force (i.e.weight) is greater than upward reactionary force so mg-R=m a R=m(g-a) R=50(9.8-9) R=50(0.8) R=40 N So the reading of weighing scale is =40/9.8 =4.08kg
read more
Since lift is descendin so the downward force (i.e.weight) is greater than upward reactionary force so mg-R=m a R=m(g-a) R=50(9.8-9) R=50(0.8) R=40 N So the reading of weighing scale is =40/9.8 =4.08kg read less
Comments

View 2 more Answers

Related Questions

Why is only the speed of light constant in all frames of reference?
The only thing that affects the speed of light is the refractive index of the medium through which it moves, and for space, this number is 1.000000 and gives you the maximum possible speed of light.
Souradeep
What is the difference between position vector and displacement vector?
Change in position vector is displacement.
Rahul Srivastava
What is the gravitatioal SI unit of work done?
It's joule .for all type of work done and energy .
Samrat
What is the Young's modulus for a perfect rigid body?
We know that Young's Modulus is the ratio of stress and strain. But, for a perfectly rigid body, the strain is zero, since there are no change in dimensions. Hence, for a perfectly rigid body, the Young's...
Praseem
0 0
5

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons


Cross product of vectors
Vector or Cross product of vectors It is defined as product of magnitude of the vectors and sine of the angle between them it is a vector quantity. For two vectors A and B A × B = |A||B| SinTn...



All about entropy
Entropy, the measure of a system’s thermal energy per unit temperaturethat is unavailable for doing useful work. Because work is obtained from ordered molecular motion, the amount of entropy is also a...

Recommended Articles

While schools provide formal education to the children, the home is where they start learning about things informally. Parents think that schools will take the initiative to educate their children. Well, this is partially true, as parents also play an essential role in bringing up their child. For the development of particular...

Read full article >

E-learning is not just about delivering lessons online. It has a much broader scope that goes beyond manual paper or PowerPoint Presentations. To understand the reach of E-learning and how the whole process works in developing the Educational system, we will discuss a few points here. Let us find out how this new learning...

Read full article >

With the current trend of the world going digital, electronic renaissance is a new movement that is welcomed by the new generation as it helps makes the lives of millions of people easier and convenient. Along with this rapidly changing movement and gaining popularity of Internet, e-Learning is a new tool that emerging...

Read full article >

Appearing for exams could be stressful for students. Even though they might have prepared well, they could suffer from anxiety, tension etc. These are not good for their health and mind. However, following a few exam preparation tips can save them from all these and help them to score good marks. Let’s find out all...

Read full article >

Looking for Class 11 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you