A person of mass 50 kg stands on a weighing scale on a lift. If the lift is descending with a downward acceleration of 9 m/s2 . What would be the reading of weighing scale?

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Dr nandi .

A Retired Physics Teacher for NEET JEE, Board

Mg-N = Ma N=M(g-a) Where N= apparent weight or the reading on the weighing machine N= 50(9.8-9) =50×.,8 newton = 40/9.8 kg = 12newton
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Mg(downward) - ma(pseudo force upward ) =weighing machine reading 50N-45N =5N( answer)
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Mass of the person, m = 50 kgDescending acceleration, a = 9 m/${{s}^{2}}$Acceleration due to gravity, g = 10 m/${{s}^{2}}$ Apparent weight of the person,R = m(g-a) =50(10-9) = 50N .’. Reading of the weighing scale =R/g =50/10 = 5 kg
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Since lift is descendin so the downward force (i.e.weight) is greater than upward reactionary force so mg-R=m a R=m(g-a) R=50(9.8-9) R=50(0.8) R=40 N So the reading of weighing scale is =40/9.8 =4.08kg
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Since lift is descendin so the downward force (i.e.weight) is greater than upward reactionary force so mg-R=m a R=m(g-a) R=50(9.8-9) R=50(0.8) R=40 N So the reading of weighing scale is =40/9.8 =4.08kg read less
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