https://www.urbanpro.com/pune/gurukul-education-center-dhanori/9071076 # Gurukul Education Center

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## Answers by Gurukul Education Center (23)

Perimeter of a cube with side a = 12 *a = 20cm Therefore , a = 5/3 cm Now , volume of cube = a^3 = (5/3)^3 = 125/27 cm3 If weight of 1cm3 is 8.25g Then weight of 125/27 cm3 will be = 8.25 * 125/27 gm = 38.19gm (ans) Let the marks scored in Mathematics be x. As given, 9( x+10 ) = x2 x2-9x-90 = 0 x2-15x+6x-90 =0 x(x-15)+6(x-15) = 0 (x+6)(x-15) = 0 Therefore, x = 15 ( x = -6 is ignored) ### Learn More

Dhanori, Pune, India - 411015

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Off. No no. 203, 2nd floor, L square building, survey no. 283, behind Orchid Hopital, Porwal road

Dhanori, Pune, India - 411015

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Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Board

CBSE, ISC/ICSE, State

ISC/ICSE Subjects taught

Physics, Mathematics, Chemistry

CBSE Subjects taught

Physics, Chemistry, Mathematics

State Syllabus Subjects taught

Chemistry, Physics, Mathematics

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1. Which school boards of of Class 11 do you teach for?

CBSE, ISC/ICSE, State

2. Which classes do you teach?

We teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 9 Tuition and Engineering Entrance Coaching Classes

3. Do you provide a demo class?

Yes, We provide a free demo class.

4. Where are you located?

We are located in Dhanori, Pune.

Answered on 24/12/2017 Learn CBSE/Class 10/Mathematics

Perimeter of a cube with side a = 12 *a = 20cm Therefore , a = 5/3 cm Now , volume of cube = a^3 = (5/3)^3 = 125/27 cm3 If weight of 1cm3 is 8.25g Then weight of 125/27 cm3 will be = 8.25 * 125/27 gm = 38.19gm (ans)

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Answers 5 Comments Answered on 10/12/2017 Learn CBSE/Class 9/Mathematics

14x6 - 45x3y3-14y6 = 14x6-49x3y3+4x3y3-14y6 = 7x3 (2x3-7y3)+2y3(2x3-7y3) = (7x3+2y3)(2x3-7y3)

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Answers 11 Comments Answered on 10/12/2017 Learn CBSE/Class 10/Mathematics

Let a = A-2D b = A-D c = A d = A+D e = A+2D a-4b+6c-4d+e = A-2D-4(A-D)+6A-4(A+D)+A+2D = 0

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Answers 11 Comments Answered on 10/12/2017 Learn CBSE/Class 10/Mathematics

Let the marks scored in Mathematics be x. As given, 9( x+10 ) = x2 x2-9x-90 = 0 x2-15x+6x-90 =0 x(x-15)+6(x-15) = 0 (x+6)(x-15) = 0 Therefore, x = 15 ( x = -6 is ignored)

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Answers 6 Comments Answered on 10/12/2017 Learn CBSE/Class 10/Mathematics

Let the speed of stream by x kmph. then speed of boat in water upstream = (18-x) kmph Speed of boat in water downstream = (18+x) kmph Now time = Distance / speed Time taken to go upstream - time taken to go downstream = 1 hr 24/(18-x) - 24/(18+x) = 1 24( 18+x-18+x ) = (18^2 - x2) 48x = 324... ...more

Let the speed of stream by x kmph. then speed of boat in water upstream = (18-x) kmph Speed of boat in water downstream = (18+x) kmph Now time = Distance / speed Time taken to go upstream - time taken to go downstream = 1 hr 24/(18-x) - 24/(18+x) = 1 24( 18+x-18+x ) = (18^2 - x2) 48x = 324 - x2 x2+48x-324 = 0 x2+54x-6x-324 = 0 x(x+54)-6(x+54) = 0 (x-6)(x+54) = 0 therefore, speed of stream (x) = 6kmph

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Answers 5 Comments Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Board

CBSE, ISC/ICSE, State

ISC/ICSE Subjects taught

Physics, Mathematics, Chemistry

CBSE Subjects taught

Physics, Chemistry, Mathematics

State Syllabus Subjects taught

Chemistry, Physics, Mathematics

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Board

CBSE, ISC/ICSE, State

ISC/ICSE Subjects taught

Physics, Mathematics, Chemistry

CBSE Subjects taught

Physics, Chemistry, Mathematics

State Syllabus Subjects taught

Chemistry, Physics, Mathematics

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Board

ICSE, CBSE, State

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Chemistry, Biology, Mathematics, Physics

State Syllabus Subjects taught

Science, Mathematics

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Board

ICSE, CBSE, State

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Chemistry, Biology, Mathematics, Physics

State Syllabus Subjects taught

Science, Mathematics

Engineering Entrance Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Engineering Entrance Exams

IIT JEE Coaching Classes

Type of class

Regular Classes

IIT JEE Coaching

IIT JEE Advanced Coaching, IIT JEE Mains Coaching, IIT JEE Foundation Course

IIT-JEE Subjects

Physics , Chemistry , Maths

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Answered on 24/12/2017 Learn CBSE/Class 10/Mathematics

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Answers 5 Comments Answered on 10/12/2017 Learn CBSE/Class 9/Mathematics

14x6 - 45x3y3-14y6 = 14x6-49x3y3+4x3y3-14y6 = 7x3 (2x3-7y3)+2y3(2x3-7y3) = (7x3+2y3)(2x3-7y3)

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Answers 11 Comments Answered on 10/12/2017 Learn CBSE/Class 10/Mathematics

Let a = A-2D b = A-D c = A d = A+D e = A+2D a-4b+6c-4d+e = A-2D-4(A-D)+6A-4(A+D)+A+2D = 0

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Answers 11 Comments Answered on 10/12/2017 Learn CBSE/Class 10/Mathematics

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Answers 6 Comments Answered on 10/12/2017 Learn CBSE/Class 10/Mathematics

Let the speed of stream by x kmph. then speed of boat in water upstream = (18-x) kmph Speed of boat in water downstream = (18+x) kmph Now time = Distance / speed Time taken to go upstream - time taken to go downstream = 1 hr 24/(18-x) - 24/(18+x) = 1 24( 18+x-18+x ) = (18^2 - x2) 48x = 324... ...more

Let the speed of stream by x kmph. then speed of boat in water upstream = (18-x) kmph Speed of boat in water downstream = (18+x) kmph Now time = Distance / speed Time taken to go upstream - time taken to go downstream = 1 hr 24/(18-x) - 24/(18+x) = 1 24( 18+x-18+x ) = (18^2 - x2) 48x = 324 - x2 x2+48x-324 = 0 x2+54x-6x-324 = 0 x(x+54)-6(x+54) = 0 (x-6)(x+54) = 0 therefore, speed of stream (x) = 6kmph

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