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Class 11 Tuition > Class 11 Tuition in Pune > Class 11 Tuition in Dhanori > Gurukul education center

Gurukul Education Center Class 11 Tuition institute in Pune

Gurukul Education Center

locationImg Dhanori, Pune
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Off. No no. 203, 2nd floor, L square building, survey no. 283, behind Orchid Hopital, Porwal road

Dhanori, Pune, India - 411015

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Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Board

State, CBSE, ISC/ICSE

Subjects taught

Mathematics, Physics, Chemistry

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Board

State, CBSE, ISC/ICSE

Subjects taught

Mathematics, Physics, Chemistry

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Board

CBSE, State, ICSE

Subjects taught

Biology, Physics, Chemistry, Mathematics, Science

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Board

CBSE, State, ICSE

Subjects taught

Physics, Biology, Science, Chemistry, Mathematics

Engineering Entrance Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Engineering Entrance Exams

IIT JEE Coaching Classes

Type of class

Regular Classes

IIT JEE Coaching

IIT JEE Advanced Coaching, IIT JEE Mains Coaching, IIT JEE Foundation Course

IIT-JEE Subjects

Physics , Chemistry , Maths

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Answers by Gurukul Education Center (23)

Answered on 24/12/2017 +1

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The perimeter of one face of a wooden cube is 20 cm. Find its weight if 1 cm3 of wood weighs 8.25 g.

Perimeter of a cube with side a = 12 *a = 20cm Therefore , a = 5/3 cm Now , volume of cube = a^3 = (5/3)^3 = 125/27 cm3 If weight of 1cm3 is 8.25g Then weight of 125/27 cm3 will be = 8.25 * 125/27 gm = 38.19gm (ans)
Answers 6 Comments
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Answered on 10/12/2017 +1

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Factorise: 14x6 – 45x3y3 – 14y6

14x6 - 45x3y3-14y6 = 14x6-49x3y3+4x3y3-14y6 = 7x3 (2x3-7y3)+2y3(2x3-7y3) = (7x3+2y3)(2x3-7y3)
Answers 11 Comments
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Answered on 10/12/2017 +1

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If the numbers a, b, c, d and e form an A.P., then find the value of a – 4b + 6c – 4d + e.

Let a = A-2D b = A-D c = A d = A+D e = A+2D a-4b+6c-4d+e = A-2D-4(A-D)+6A-4(A+D)+A+2D = 0
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Had Ravita scored 10 more marks in her Mathematics test out of 30 marks, 9 times these marks would have... ...more
Had Ravita scored 10 more marks in her Mathematics test out of 30 marks, 9 times these marks would have...

Let the marks scored in Mathematics be x. As given, 9( x+10 ) = x2 x2-9x-90 = 0 x2-15x+6x-90 =0 x(x-15)+6(x-15) = 0 (x+6)(x-15) = 0 Therefore, x = 15 ( x = -6 is ignored)
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Answered on 10/12/2017 +1

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A motor boat whose speed is 18 km/h in still water takes 1 hour more to go 24 km upstream than to return... ...more
A motor boat whose speed is 18 km/h in still water takes 1 hour more to go 24 km upstream than to return...

Let the speed of stream by x kmph. then speed of boat in water upstream = (18-x) kmph Speed of boat in water downstream = (18+x) kmph Now time = Distance / speed Time taken to go upstream - time taken to go downstream = 1 hr 24/(18-x) - 24/(18+x) = 1 24( 18+x-18+x ) = (18^2 - x2) 48x = 324... ...more
Let the speed of stream by x kmph. then speed of boat in water upstream = (18-x) kmph Speed of boat in water downstream = (18+x) kmph Now time = Distance / speed Time taken to go upstream - time taken to go downstream = 1 hr 24/(18-x) - 24/(18+x) = 1 24( 18+x-18+x ) = (18^2 - x2) 48x = 324 - x2 x2+48x-324 = 0 x2+54x-6x-324 = 0 x(x+54)-6(x+54) = 0 (x-6)(x+54) = 0 therefore, speed of stream (x) = 6kmph
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Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Board

State, CBSE, ISC/ICSE

Subjects taught

Mathematics, Physics, Chemistry

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Board

State, CBSE, ISC/ICSE

Subjects taught

Mathematics, Physics, Chemistry

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Board

CBSE, State, ICSE

Subjects taught

Biology, Physics, Chemistry, Mathematics, Science

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Board

CBSE, State, ICSE

Subjects taught

Physics, Biology, Science, Chemistry, Mathematics

Engineering Entrance Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Engineering Entrance Exams

IIT JEE Coaching Classes

Type of class

Regular Classes

IIT JEE Coaching

IIT JEE Advanced Coaching, IIT JEE Mains Coaching, IIT JEE Foundation Course

IIT-JEE Subjects

Physics , Chemistry , Maths

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Answers by Gurukul Education Center

Answered on 24/12/2017 +1

Ask a Question

Post a Lesson

The perimeter of one face of a wooden cube is 20 cm. Find its weight if 1 cm3 of wood weighs 8.25 g.

Perimeter of a cube with side a = 12 *a = 20cm Therefore , a = 5/3 cm Now , volume of cube = a^3 = (5/3)^3 = 125/27 cm3 If weight of 1cm3 is 8.25g Then weight of 125/27 cm3 will be = 8.25 * 125/27 gm = 38.19gm (ans)
Answers 6 Comments
Dislike Bookmark

Answered on 10/12/2017 +1

Ask a Question

Post a Lesson

Factorise: 14x6 – 45x3y3 – 14y6

14x6 - 45x3y3-14y6 = 14x6-49x3y3+4x3y3-14y6 = 7x3 (2x3-7y3)+2y3(2x3-7y3) = (7x3+2y3)(2x3-7y3)
Answers 11 Comments
Dislike Bookmark

Answered on 10/12/2017 +1

Ask a Question

Post a Lesson

If the numbers a, b, c, d and e form an A.P., then find the value of a – 4b + 6c – 4d + e.

Let a = A-2D b = A-D c = A d = A+D e = A+2D a-4b+6c-4d+e = A-2D-4(A-D)+6A-4(A+D)+A+2D = 0
Answers 11 Comments
Dislike Bookmark

Answered on 10/12/2017 +1

Ask a Question

Post a Lesson

Had Ravita scored 10 more marks in her Mathematics test out of 30 marks, 9 times these marks would have... ...more
Had Ravita scored 10 more marks in her Mathematics test out of 30 marks, 9 times these marks would have...

Let the marks scored in Mathematics be x. As given, 9( x+10 ) = x2 x2-9x-90 = 0 x2-15x+6x-90 =0 x(x-15)+6(x-15) = 0 (x+6)(x-15) = 0 Therefore, x = 15 ( x = -6 is ignored)
Answers 8 Comments
Dislike Bookmark

Answered on 10/12/2017 +1

Ask a Question

Post a Lesson

A motor boat whose speed is 18 km/h in still water takes 1 hour more to go 24 km upstream than to return... ...more
A motor boat whose speed is 18 km/h in still water takes 1 hour more to go 24 km upstream than to return...

Let the speed of stream by x kmph. then speed of boat in water upstream = (18-x) kmph Speed of boat in water downstream = (18+x) kmph Now time = Distance / speed Time taken to go upstream - time taken to go downstream = 1 hr 24/(18-x) - 24/(18+x) = 1 24( 18+x-18+x ) = (18^2 - x2) 48x = 324... ...more
Let the speed of stream by x kmph. then speed of boat in water upstream = (18-x) kmph Speed of boat in water downstream = (18+x) kmph Now time = Distance / speed Time taken to go upstream - time taken to go downstream = 1 hr 24/(18-x) - 24/(18+x) = 1 24( 18+x-18+x ) = (18^2 - x2) 48x = 324 - x2 x2+48x-324 = 0 x2+54x-6x-324 = 0 x(x+54)-6(x+54) = 0 (x-6)(x+54) = 0 therefore, speed of stream (x) = 6kmph
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