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Class 10 > The perimeter of one face of a wooden cube is 20 cm....
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The perimeter of one face of a wooden cube is 20 cm. Find its weight if 1 cm3 of wood weighs 8.25 g.

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Let a be the side of cube,Perimeter of a wooden cube=20cm=4aWe know, Perimeter of a cube = 4a Therefore, 4a = 20cm a = 5cm=
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Let abe theside of cube,Perimeterof a wooden cube=20cm=4aWe know, Perimeterof a cube = 4a Therefore, 4a = 20cm a = 5cm= read less
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Perimeter of one face of the cube = 20 cm So, each edge of the cube = 20/4= 5 cm So, volume of cube = 5^3 = 125 cc. So, weight of tge cube = 125*8.25 = 1031.25 gm
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Given perimeter of one face of a wooden cube is 20cm 4×side(s)=20cm Side=20/4=5cm Now volume of wooden cube is s×s×s=5×5×5=125cm^3 Weight of wooden cube is 125×8.25=1031.25 cm^3
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Perimeter of one face of wooden cube=20cm. Therefore measure of each side of the cube 20/4 = 5cm. Therefore the volume of wooden cube =5^3 (five cube) =125 cc. So, weight of the wooden cube = 125 X 8.25 = 1031.25 gm = 1.03125 kg
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Perimeter of one face of wooden cube=20cm. [formula: measure of each side of square = perimeter / 4] Therefore measure of each side of the cube 20/4 = 5cm. [formula of volume of a cube = side ^3] Therefore the volume of wooden cube =5^3 (five cube) =125 cc. [formula: total weight = weight per cc. X volume of cube] So, weight of the wooden cube = 125 X 8.25 = 1031.25 gm = 1.03125 kg read less
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Perimeter of a cube with side a = 12 *a = 20cm Therefore , a = 5/3 cm Now , volume of cube = a^3 = (5/3)^3 = 125/27 cm3 If weight of 1cm3 is 8.25g Then weight of 125/27 cm3 will be = 8.25 * 125/27 gm = 38.19gm (ans)
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