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Ganesh Wadkar

Dhanori, Pune, India - 411015

Ganesh Wadkar Class 8 Tuition trainer in Pune

Ganesh Wadkar

Tutor

Dhanori, Pune, India - 411015.

2 Students taught

5.0

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Overview

I am an experienced, qualified tutor with over 5 years of experience in teaching physics and maths.passionate about teaching physics concepts and maths numericals. I have good experience of competitive examinations like NDA, CDSE.

Languages Spoken

Marathi Mother Tongue (Native)

English Proficient

Hindi Proficient

Education

fergusson 2013

Bachelor of Science (B.Sc.)

pune university 2015

Master of Science (M.Sc.)

Address

Dhanori, Pune, India - 411015

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Demo Class

Yes, charged

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Class 8 Tuition Overview

Class 8 Tuition

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 8 Tuition

4

Board

State, ICSE, CBSE

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Physics

Experience in School or College

I have done my internship from reputed school and it was good experience. I am associated with coaching institute where I am teaching Physics for 11th and 12th std from last 4 years.

Taught in School or College

Yes

State Syllabus Subjects taught

Science, Mathematics

Reviews

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FAQs

1. Which school boards of of Class 8 do you teach for?

State, ICSE and CBSE

2. Have you ever taught in any School or College?

Yes

3. Which classes do you teach?

I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 7 Tuition, Class 8 Tuition, Class 9 Tuition and UPSC Exams Coaching Classes.

4. Do you provide a demo class?

Yes, I provide a paid demo class.

5. How many years of experience do you have?

I have been teaching for 4 years.

Answers by Ganesh Wadkar (4)

Answered on 20/08/2019 CBSE Tuition CBSE/Class 10/Mathematics

You can guess the square root with simple logic. For example 81. - sq root is 9 361 is sq root of number whose unit = 1 or 9 Square of 20 is 400 .so u can it's square root of either 11 or 19. If you compare sq of 20 u can easily guess it sq root of 19. If last digit is 4 then it's square root of... ...more

You can guess the square root with simple logic.

For example

81.   - sq root is 9

361 is sq root of number whose unit = 1 or 9

Square of 20 is 400 .so u can it's square root of either 11 or 19.

If you compare sq of 20 u can easily guess it sq root of 19.

 

If last digit is 4 then it's square root of either 2 or 8

If last digit is 9 then it's square root of either 7 or 3

If last digit is 6 then it's square root of either 4 or 6

And if it's 5 then 5

 

Answers 72 Comments
Dislike Bookmark

Answered on 18/08/2019 CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.7

given h = 15 cm volume of cone = 1570 to find- radius (r) formula- volume of cone = 1570 = 3.14 * * 15 /3 1570 *3 = 3.14 * 15 * = 1570 * 3 / 3.14 * 15 =100 taking square roots on both sides , we get r = 10 cm ...more

given 

h = 15 cm

volume of cone = 1570

to find- radius (r)

formula- 

volume of cone = 

           1570     = 3.14 *  * 15 /3

     1570 *3 =  3.14 * 15 * 

                =   1570 * 3 / 3.14 * 15 

                   =100

taking square roots on both sides , we get 

     r = 10 cm

Answers 6 Comments
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Answered on 18/08/2019 CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.7

Diameter of the conical pit = 3.5m radius= 1.75m height=12m volume of cone= π h /3 = 3.14 * 1.75^2 * 12 /3 =115.39/3 = 38.46 volume of cone = 38.46 m^3 1= 1000 L = 1 kilolitre hence , 38.5 = 38.5 kilolitrs ...more

Diameter of the conical pit = 3.5m 

radius= 1.75m

height=12m

volume of cone= π h /3

                      = 3.14 * 1.75^2 * 12  /3

                      =115.39/3

                      = 38.46

volume of cone = 38.46 m^3

1= 1000 L = 1 kilolitre

hence ,

38.5  = 38.5 kilolitrs

Answers 3 Comments
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Answered on 17/08/2019 CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.7

1. L^2 = h^2 + r^2 L = slant height h= height r= radius 25^2 = h^2 + 7^2 h^2 = 625 - 49 = 576 after taking square root h = 24 volume of cone = L^2 = h^2 + r^2 = 1/3 * 3.14 *7^2 *... ...more

        1.    L^2 = h^2 + r^2              L = slant height   h= height  r= radius

            25^2 = h^2 + 7^2

            h^2 = 625 - 49 = 576

                  after taking square root

h = 24 

volume of cone =                               L^2 = h^2 + r^2

                       = 1/3 * 3.14 *7^2 * 24

                       =3692.64/3

 volume of cone  =1230 cm^3

 

1L = 1000cm^3

therefore answer is 1.230 L

Answers 3 Comments
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Class 8 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 8 Tuition

4

Board

State, ICSE, CBSE

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Physics

Experience in School or College

I have done my internship from reputed school and it was good experience. I am associated with coaching institute where I am teaching Physics for 11th and 12th std from last 4 years.

Taught in School or College

Yes

State Syllabus Subjects taught

Science, Mathematics

Class 9 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 9 Tuition

4

Board

CBSE, ICSE, State

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Physics

Taught in School or College

No

State Syllabus Subjects taught

Science, Mathematics

Class 10 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 10 Tuition

4

Board

CBSE, ICSE, State

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Physics

Taught in School or College

No

State Syllabus Subjects taught

Science, Mathematics

Class 7 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 7 Tuition

4

Board

State, ICSE, CBSE

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Physics

Taught in School or College

No

State Syllabus Subjects taught

Science, Mathematics

Class 11 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 11 Tuition

5

Board

CBSE, ISC/ICSE, State

ISC/ICSE Subjects taught

Physics, Mathematics

CBSE Subjects taught

Mathematics, Physics

Taught in School or College

No

State Syllabus Subjects taught

Physics, History, Mathematics, Geography

Class 12 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 12 Tuition

4

Board

CBSE, ISC/ICSE, State

ISC/ICSE Subjects taught

Physics

CBSE Subjects taught

Physics

Taught in School or College

No

State Syllabus Subjects taught

Physics, Mathematics

UPSC Exams Coaching classes 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in UPSC Exams Coaching classes

4

Gives

NDA (National Defence Acadamy and Naval Acadamy) Exam Coaching, CDS (Combined Defence Service) Exam Coaching

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Answers by Ganesh Wadkar (4)

Answered on 20/08/2019 CBSE Tuition CBSE/Class 10/Mathematics

You can guess the square root with simple logic. For example 81. - sq root is 9 361 is sq root of number whose unit = 1 or 9 Square of 20 is 400 .so u can it's square root of either 11 or 19. If you compare sq of 20 u can easily guess it sq root of 19. If last digit is 4 then it's square root of... ...more

You can guess the square root with simple logic.

For example

81.   - sq root is 9

361 is sq root of number whose unit = 1 or 9

Square of 20 is 400 .so u can it's square root of either 11 or 19.

If you compare sq of 20 u can easily guess it sq root of 19.

 

If last digit is 4 then it's square root of either 2 or 8

If last digit is 9 then it's square root of either 7 or 3

If last digit is 6 then it's square root of either 4 or 6

And if it's 5 then 5

 

Answers 72 Comments
Dislike Bookmark

Answered on 18/08/2019 CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.7

given h = 15 cm volume of cone = 1570 to find- radius (r) formula- volume of cone = 1570 = 3.14 * * 15 /3 1570 *3 = 3.14 * 15 * = 1570 * 3 / 3.14 * 15 =100 taking square roots on both sides , we get r = 10 cm ...more

given 

h = 15 cm

volume of cone = 1570

to find- radius (r)

formula- 

volume of cone = 

           1570     = 3.14 *  * 15 /3

     1570 *3 =  3.14 * 15 * 

                =   1570 * 3 / 3.14 * 15 

                   =100

taking square roots on both sides , we get 

     r = 10 cm

Answers 6 Comments
Dislike Bookmark

Answered on 18/08/2019 CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.7

Diameter of the conical pit = 3.5m radius= 1.75m height=12m volume of cone= π h /3 = 3.14 * 1.75^2 * 12 /3 =115.39/3 = 38.46 volume of cone = 38.46 m^3 1= 1000 L = 1 kilolitre hence , 38.5 = 38.5 kilolitrs ...more

Diameter of the conical pit = 3.5m 

radius= 1.75m

height=12m

volume of cone= π h /3

                      = 3.14 * 1.75^2 * 12  /3

                      =115.39/3

                      = 38.46

volume of cone = 38.46 m^3

1= 1000 L = 1 kilolitre

hence ,

38.5  = 38.5 kilolitrs

Answers 3 Comments
Dislike Bookmark

Answered on 17/08/2019 CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.7

1. L^2 = h^2 + r^2 L = slant height h= height r= radius 25^2 = h^2 + 7^2 h^2 = 625 - 49 = 576 after taking square root h = 24 volume of cone = L^2 = h^2 + r^2 = 1/3 * 3.14 *7^2 *... ...more

        1.    L^2 = h^2 + r^2              L = slant height   h= height  r= radius

            25^2 = h^2 + 7^2

            h^2 = 625 - 49 = 576

                  after taking square root

h = 24 

volume of cone =                               L^2 = h^2 + r^2

                       = 1/3 * 3.14 *7^2 * 24

                       =3692.64/3

 volume of cone  =1230 cm^3

 

1L = 1000cm^3

therefore answer is 1.230 L

Answers 3 Comments
Dislike Bookmark

Ganesh Wadkar describes himself as Tutor. He conducts classes in Class 10 Tuition, Class 11 Tuition and Class 12 Tuition. Ganesh is located in Dhanori, Pune. Ganesh takes at students Home and Regular Classes- at his Home. He has 5 years of teaching experience . Ganesh has completed Bachelor of Science (B.Sc.) from fergusson in 2013 and Master of Science (M.Sc.) from pune university in 2015. HeĀ is well versed in English, Hindi and Marathi.

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