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    The Gurukul Practice Center Nerul
    Review by Sheetal

    ""I convey my sincere gratitude to TGPC due to which I was able to become a 'Rank Holder' in Final exam. The teaching at TJPC was not only educative but their interactive session made us very well versed as to how to appear for the exams. This made us confident for appearing for such tough exams with..."

    T
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    The Gurukul Practice Center Nerul
    Review by Shweta

    "Excellence of teaching which eliminates the fear of the subject .The good environment and teaching methodology overwhelms the joy of learning."

    P
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    Pushkar S.
    Review by Pushkar

    "very good teacher and moral boosting person."

    M
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    Mane Sir S.
    Review by Mane Sir

    "i learnt from Rajiv Sir Xii (Chemistry)... At present i think he is the best Chemistry Tutor in Navi Mumbai. He is specialized in ORGANIC CHEMISTRY... Anybody who is really interested in IIT-JEE, AI-EEE, XII BOARD exams, then he is really worth in teaching the mentioned blocks... I am very much thankful..."

  • R
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    Ravi Kumar S.
    Review by Subnam

    ""He is awesome teacher.His teaching methodology is quite good.He understands his student's needs.His attention to detail is amazing""

    R
    review star review star review star review star review star

    Ravi Kumar S.
    Review by Subnam

    ""He is awesome teacher.His teaching methodology is quite good.He understands his student's needs.His attention to detail is amazing""

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Related Lessons

Concept of transistor

Introduction to transistor Transistor is basic of modern electronics. We have two types of transistors. Bipolar junction transistor Unipolar junction transistor Transistor is a device made of two words. Transfer + resistor. So it means it is a device...

Solution to a integration problem

∫ x^4 / ( x² + 1 ) dx As the degree of numerator is higher than that of the denominator, let's divide x^4 by ( x² + 1 ). = ∫ x² - 1 + 1/(x² + 1 ) dx = ∫ x² dx - ∫1•dx + 1/ ( 1 + x² ) dx = [ ( x³ / 3 ) - ( x ) + tan‾1 ( x ) + C ]

Differentiating 2(x^2) using first principle

Differentiate 2x² using first principle We know from first principle that dy/dx f(x) = lim δx→0 [ f( x + δx ) - f (x) ] /δx Here f(x) = 2 x² substituting 2x² in place of x in the equation above lim δx →...

Problem on limits

Find lim x→0 ( sin 4x )/( x ) To use standard trig formula on limits, lim x→0 (sin x )/( x ) = 1 let us multiply numerator and denominator by 4. = lim x→0 ( sin 4x ) • ( 4 ) / ( 4 • x ) = lim x→0 ( 4 ) • ( sin 4x...

Integration by partial fraction.

∫ ( 5x + 4 )/( x + 2 ) ( x - 4 ) dx Let's try solving this particular problem using partial fraction method of integration. In partial fraction, we have to rewrite this function in the form [A/( x + 2 ) + B/( x - 4 )] and then split each rational...

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