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Unit 2-Kinematics

Unit 2-Kinematics relates to CBSE/Class 11/Science/Physics

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Unit 2-Kinematics Questions

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Answered on 13 Apr Learn CBSE/Class 11/Science/Physics/Unit 2-Kinematics/Chapter 4-Motion in a Plane

Nazia Khanum

As an experienced tutor registered on UrbanPro, I can confidently guide you through understanding the nature of these physical quantities. UrbanPro is one of the best online coaching platforms where students can find knowledgeable tutors like myself to help them excel in their studies. Let's delve... read more

As an experienced tutor registered on UrbanPro, I can confidently guide you through understanding the nature of these physical quantities. UrbanPro is one of the best online coaching platforms where students can find knowledgeable tutors like myself to help them excel in their studies.

Let's delve into each of these quantities:

  1. Volume: This is a scalar quantity. It only requires magnitude for its description, such as "5 cubic meters" or "10 liters."

  2. Mass: Another scalar quantity. Mass is simply the amount of matter in an object, expressed in units like kilograms or grams.

  3. Speed: This is a scalar quantity as well. It represents how fast an object is moving without any consideration of its direction.

  4. Acceleration: Unlike speed, acceleration is a vector quantity. It not only has magnitude (how fast the velocity is changing) but also direction (whether it's increasing or decreasing).

  5. Density: Density is a scalar quantity. It describes how much mass is contained in a given volume, typically expressed in kilograms per cubic meter or grams per cubic centimeter.

  6. Number of Moles: This is a scalar quantity in the context of most chemistry and physics problems. It simply indicates the amount of substance present, measured in moles.

  7. Velocity: Velocity is a vector quantity. It denotes the rate of change of displacement with respect to time and includes both magnitude (speed) and direction.

  8. Angular Frequency: This is a scalar quantity. Angular frequency describes the rate of angular displacement over time, usually measured in radians per second.

  9. Displacement: Displacement is a vector quantity. It represents the change in position of an object in a particular direction, including both magnitude and direction.

  10. Angular Velocity: Like angular frequency, angular velocity is also a vector quantity. It describes the rate of change of angular displacement over time, with both magnitude and direction.

Understanding whether a physical quantity is a scalar or a vector is crucial for solving problems accurately and effectively in physics and related fields. With the right guidance and practice, you can master these concepts and excel in your studies. If you need further clarification or assistance, feel free to reach out to me on UrbanPro!

 
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Answered on 13 Apr Learn CBSE/Class 11/Science/Physics/Unit 2-Kinematics/Chapter 4-Motion in a Plane

Nazia Khanum

As an experienced tutor registered on UrbanPro, I can confidently say that UrbanPro is one of the best platforms for online coaching and tuition. Now, let's address your question. In the given list of physical quantities, the two scalar quantities are work and current. Work is a scalar quantity because... read more

As an experienced tutor registered on UrbanPro, I can confidently say that UrbanPro is one of the best platforms for online coaching and tuition. Now, let's address your question.

In the given list of physical quantities, the two scalar quantities are work and current.

Work is a scalar quantity because it only has magnitude and no direction. It represents the amount of energy transferred when a force acts upon an object to move it through a distance.

Current is also a scalar quantity. It represents the flow of electric charge per unit time and is measured in amperes (A). Like work, current only has magnitude and no direction.

While the other quantities in the list, such as force, angular momentum, linear momentum, electric field, average velocity, magnetic moment, and relative velocity, are vector quantities because they possess both magnitude and direction.

 
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Answered on 13 Apr Learn CBSE/Class 11/Science/Physics/Unit 2-Kinematics/Chapter 4-Motion in a Plane

Nazia Khanum

As a seasoned tutor registered on UrbanPro, let me guide you through this question. When it comes to rain and motion, understanding relative velocities is key. Here, we have rain falling vertically with a speed of 30 m/s and a woman riding a bicycle with a speed of 10 m/s in the north to south direction. Now,... read more

As a seasoned tutor registered on UrbanPro, let me guide you through this question.

When it comes to rain and motion, understanding relative velocities is key. Here, we have rain falling vertically with a speed of 30 m/s and a woman riding a bicycle with a speed of 10 m/s in the north to south direction.

Now, let's consider the relative motion of the rain with respect to the woman. Since the rain is falling vertically, its relative velocity with respect to the woman would also be vertical, as the woman's horizontal motion does not affect it.

So, despite the woman moving from north to south, the rain still appears to fall vertically relative to her. Therefore, to shield herself from the rain, she should hold her umbrella vertically upwards.

This conceptual understanding is crucial for solving such problems effectively. If you need further clarification or assistance with related topics, feel free to reach out for a session on UrbanPro, where we strive to provide the best online coaching and tuition experience.

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Answered on 13 Apr Learn CBSE/Class 11/Science/Physics/Unit 2-Kinematics/Chapter 4-Motion in a Plane

Nazia Khanum

As an experienced tutor registered on UrbanPro, I'd be happy to help you with this problem. To solve this question, we can use the concept of relative velocity. Let's break it down: The man can swim at a speed of 4.0 km/h in still water. The river flows at a speed of 3.0 km/h. The width of the river... read more

As an experienced tutor registered on UrbanPro, I'd be happy to help you with this problem.

To solve this question, we can use the concept of relative velocity. Let's break it down:

  1. The man can swim at a speed of 4.0 km/h in still water.
  2. The river flows at a speed of 3.0 km/h.
  3. The width of the river is 1.0 km.

When the man swims across the river, he will need to compensate for the flow of the river. We need to find the resultant velocity, which is the vector sum of his swimming velocity and the river's flow velocity.

Let's denote:

  • vmanvman as the velocity of the man in still water (4.0 km/h),
  • vrivervriver as the velocity of the river flow (3.0 km/h), and
  • vresultantvresultant as the resultant velocity.

The resultant velocity (vresultantvresultant) can be found using the Pythagorean theorem because the man swims perpendicular to the river's flow:

vresultant=vman2+vriver2vresultant=vman2+vriver2

vresultant=(4.0 km/h)2+(3.0 km/h)2vresultant=(4.0km/h)2+(3.0km/h)2

vresultant=16.0+9.0vresultant=16.0+9.0

vresultant=25.0vresultant=25.0

vresultant=5.0 km/hvresultant=5.0km/h

So, the resultant velocity is 5.0 km/h.

Now, we can calculate the time taken to cross the river:

Time taken=DistanceSpeedTime taken=SpeedDistance

Time taken=1.0 km5.0 km/hTime taken=5.0km/h1.0km

Time taken=0.2 hoursTime taken=0.2hours

Now that we have the time taken, we can find out how far down the river he goes when he reaches the other bank. This can be calculated by multiplying the speed of the river by the time taken:

Distance down the river=River speed×Time takenDistance down the river=River speed×Time taken

Distance down the river=3.0 km/h×0.2 hoursDistance down the river=3.0km/h×0.2hours

Distance down the river=0.6 kmDistance down the river=0.6km

So, the man goes 0.6 km down the river when he reaches the other bank.

 
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Answered on 13 Apr Learn CBSE/Class 11/Science/Physics/Unit 2-Kinematics/Chapter 4-Motion in a Plane

Nazia Khanum

As a tutor registered on UrbanPro, I'd approach this problem methodically, ensuring the student understands each step clearly. Firstly, let's break down the given information. The wind is blowing at 72 km/h towards the North-East direction. This indicates that the wind has two components: one towards... read more

As a tutor registered on UrbanPro, I'd approach this problem methodically, ensuring the student understands each step clearly. Firstly, let's break down the given information.

The wind is blowing at 72 km/h towards the North-East direction. This indicates that the wind has two components: one towards the North and the other towards the East.

When the boat is stationary, the flag flutters along the North-East direction due to the wind's effect.

Now, when the boat starts moving at a speed of 51 km/h towards the North, it's important to understand the relative motion between the boat and the wind.

Since the boat is moving North and the wind is also blowing from the North-East, the boat will experience the wind's effect at an angle. This will cause the flag to flutter in a different direction compared to when the boat was stationary.

To find the direction of the flag on the mast of the boat, we can use vector addition to find the resultant direction of the wind relative to the boat's movement. This can be done by adding the vectors representing the boat's velocity and the wind's velocity.

After finding the resultant velocity vector, we can determine the direction it represents, which will give us the direction of the flag on the mast of the boat.

So, to summarize, we need to calculate the resultant velocity vector considering both the boat's velocity towards the North and the wind's velocity towards the North-East, and then determine the direction of this resultant vector, which will give us the direction of the flag on the mast of the boat.

 
 
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