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Q9:
Find $x$ and $y$, if $2\begin{bmatrix} 1 & 3 \\ 0 & x \end{bmatrix} + \begin{bmatrix} y & 0 \\ 1 & 2 \end{bmatrix} = \begin{bmatrix} 5 & 6 \\ 1 & 8 \end{bmatrix}$

Solution :

Step 1: Scalar Multiplication of the First Matrix

Given the equation: $2\begin{bmatrix} 1 & 3 \\ 0 & x \end{bmatrix} + \begin{bmatrix} y & 0 \\ 1 & 2 \end{bmatrix} = \begin{bmatrix} 5 & 6 \\ 1 & 8 \end{bmatrix}$

Apply scalar multiplication [Per the Scalar Multiplication Property of Matrices, where $k[A_{ij}] = [k \cdot A_{ij}]$]:

$2 \times \begin{bmatrix} 1 & 3 \\ 0 & x \end{bmatrix} = \begin{bmatrix} 2(1) & 2(3) \\ 2(0) & 2(x) \end{bmatrix} = \begin{bmatrix} 2 & 6 \\ 0 & 2x \end{bmatrix}$

Step 2: Matrix Addition

Add the two matrices on the left-hand side [Per the definition of Matrix Addition, where $[A_{ij}] + [B_{ij}] = [A_{ij} + B_{ij}]$]:

$\begin{bmatrix} 2 & 6 \\ 0 & 2x \end{bmatrix} + \begin{bmatrix} y & 0 \\ 1 & 2 \end{bmatrix} = \begin{bmatrix} 2 + y & 6 + 0 \\ 0 + 1 & 2x + 2 \end{bmatrix} = \begin{bmatrix} 2 + y & 6 \\ 1 & 2x + 2 \end{bmatrix}$

Step 3: Equating Corresponding Elements

Set the resulting matrix equal to the matrix on the right-hand side:

$\begin{bmatrix} 2 + y & 6 \\ 1 & 2x + 2 \end{bmatrix} = \begin{bmatrix} 5 & 6 \\ 1 & 8 \end{bmatrix}$

By the Principle of Equality of Matrices, we equate corresponding elements:

  • For position $(1,1)$: $2 + y = 5$
  • For position $(2,2)$: $2x + 2 = 8$

Step 4: Solving for Variables

Solving for $y$:

$2 + y = 5$

$y = 5 - 2$ [By Subtraction Property of Equality]

$y = 3$


Solving for $x$:

$2x + 2 = 8$

$2x = 8 - 2$ [By Subtraction Property of Equality]

$2x = 6$

$x = \frac{6}{2}$ [By Division Property of Equality]

$x = 3$

2 6 0 6 + 3 0 1 2 = Result

Final Solution: $x = 3, y = 3$


More Questions from Class 12 Mathematics Matrices EXERCISE 3.2


CBSE Solutions for Class 12 Mathematics Matrices


Chapters in CBSE - Class 12 Mathematics


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