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Q1(ii):
Let $A = \begin{bmatrix} 2 & 4 \\ 3 & 2 \end{bmatrix}$, $B = \begin{bmatrix} 1 & 3 \\ -2 & 5 \end{bmatrix}$, $C = \begin{bmatrix} -2 & 5 \\ 3 & 4 \end{bmatrix}$. Find each of the following: (ii) $A – B$

Solution :

Step 1: Theoretical Foundation of Matrix Subtraction

The operation of subtracting two matrices, $A$ and $B$, is defined only when both matrices are of the same order (i.e., they have the same number of rows and columns). Given $A = [a_{ij}]$ and $B = [b_{ij}]$, the difference $A - B$ is a matrix $D = [d_{ij}]$ of the same order, where each element is defined by:
$d_{ij} = a_{ij} - b_{ij}$
[Per the definition of Matrix Subtraction for matrices of order $m \times n$].

Step 2: Identification of Given Matrices

Both matrices $A$ and $B$ are $2 \times 2$ square matrices:

$A = \begin{bmatrix} 2 & 4 \\ 3 & 2 \end{bmatrix}$

$B = \begin{bmatrix} 1 & 3 \\ -2 & 5 \end{bmatrix}$

Step 3: Execution of Element-wise Subtraction

To find $A - B$, subtract the corresponding entries of $B$ from $A$:

$A - B = \begin{bmatrix} 2 - (1) & 4 - (3) \\ 3 - (-2) & 2 - (5) \end{bmatrix}$

Step 4: Algebraic Simplification

Performing the arithmetic operations on each component:

  • Row 1, Col 1: $2 - 1 = 1$
  • Row 1, Col 2: $4 - 3 = 1$
  • Row 2, Col 1: $3 - (-2) = 3 + 2 = 5$
  • Row 2, Col 2: $2 - 5 = -3$

Visual Representation of Matrix Subtraction

A - B = 1 1 5 -3

Final Solution: $A - B = \begin{bmatrix} 1 & 1 \\ 5 & -3 \end{bmatrix}$


More Questions from Class 12 Mathematics Matrices EXERCISE 3.2


CBSE Solutions for Class 12 Mathematics Matrices


Chapters in CBSE - Class 12 Mathematics


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