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Q2.17 (ii):

Using the standard electrode potentials, predict if the reaction between the following is feasible: (ii) (Ag^{+} (aq)) and Cu(s)

Solution :

Given Variables & Initial Setup

To determine the feasibility of the reaction between silver ions ($Ag^+$) and solid copper ($Cu$), we must analyze the standard reduction potentials ($E^\circ$) of the half-reactions involved. The reaction is feasible if the standard cell potential ($E^\circ_{cell}$) is positive [Per the Nernst Equation and Thermodynamic criterion $\Delta G^\circ = -nFE^\circ_{cell}$, where $\Delta G^\circ < 0$ implies spontaneity].

The half-reactions and their standard reduction potentials are:

  • Reduction half-reaction: $Ag^+(aq) + e^- \rightarrow Ag(s)$ ; $E^\circ_{Ag^+/Ag} = +0.80 \, V$
  • Oxidation half-reaction: $Cu(s) \rightarrow Cu^{2+}(aq) + 2e^-$ ; $E^\circ_{Cu^{2+}/Cu} = +0.34 \, V$

Step 1: Formulating the Balanced Redox Equation

To equate the number of electrons transferred, we multiply the reduction half-reaction by 2:

$2Ag^+(aq) + 2e^- \rightarrow 2Ag(s)$

$Cu(s) \rightarrow Cu^{2+}(aq) + 2e^-$

Net reaction: $2Ag^+(aq) + Cu(s) \rightarrow 2Ag(s) + Cu^{2+}(aq)$

Step 2: Calculation of Standard Cell Potential ($E^\circ_{cell}$)

The standard cell potential is calculated using the formula: $E^\circ_{cell} = E^\circ_{cathode} - E^\circ_{anode}$ [Per IUPAC Convention for electrochemical cells].

In this reaction:

  • Cathode: $Ag^+/Ag$ ($E^\circ = +0.80 \, V$)
  • Anode: $Cu^{2+}/Cu$ ($E^\circ = +0.34 \, V$)

$E^\circ_{cell} = (+0.80 \, V) - (+0.34 \, V)$

$E^\circ_{cell} = +0.46 \, V$

Step 3: Visual Representation of the Electrochemical Cell

Cu Ag Salt Bridge

Step 4: Conclusion on Feasibility

Since the calculated standard cell potential $E^\circ_{cell}$ is positive ($+0.46 \, V$), the Gibbs free energy change ($\Delta G^\circ = -nFE^\circ_{cell}$) will be negative. Therefore, the reaction is thermodynamically spontaneous [Per the Second Law of Thermodynamics].

Final Solution: Yes, the reaction is feasible because $E^\circ_{cell} = +0.46 \, V$, which indicates a spontaneous process.


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