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Q2.15:
A solution of (Ni(NO_{3})_{2}) is electrolysed between platinum electrodes using a current of 5 amperes for 20 minutes. What mass of Ni is deposited at the cathode?

Solution :

Given Variables & Initial Setup

To determine the mass of Nickel ($Ni$) deposited, we employ Faraday's Laws of Electrolysis. The parameters provided are:

  • Current ($I$) = $5.0 \, A$
  • Time ($t$) = $20 \, \text{minutes} = 20 \times 60 \, s = 1200 \, s$
  • Electrolyte: $Ni(NO_3)_2$ (Nickel exists as $Ni^{2+}$)
  • Atomic Molar Mass of $Ni$ ($M$) = $58.7 \, g \cdot mol^{-1}$
  • Faraday's Constant ($F$) = $96487 \, C \cdot mol^{-1}$

Step 1: Determining the Half-Reaction

At the cathode, the reduction of nickel ions occurs according to the following half-cell reaction [Per the principle of reduction at the cathode]:

$Ni^{2+}(aq) + 2e^- \rightarrow Ni(s)$

From the stoichiometry of the reaction, $n = 2$ moles of electrons are required to deposit $1$ mole of $Ni(s)$.

Step 2: Calculating Total Charge ($Q$)

The total electric charge passed through the solution is calculated using the relationship between current and time [Per the definition of electric current $I = \frac{dQ}{dt}$]:

$Q = I \times t$

$Q = 5.0 \, A \times 1200 \, s = 6000 \, C$

Step 3: Calculating Moles of Electrons and Deposited Nickel

The number of moles of electrons ($n_e$) is calculated by dividing total charge by Faraday's constant:

$n_e = \frac{Q}{F} = \frac{6000 \, C}{96487 \, C \cdot mol^{-1}} \approx 0.062186 \, mol$

Since $2$ moles of $e^-$ are required per $1$ mole of $Ni$, the moles of $Ni$ deposited are:

$n_{Ni} = \frac{n_e}{2} = \frac{0.062186}{2} = 0.031093 \, mol$

Step 4: Calculating Mass of Deposited Nickel

The final mass ($m$) is derived by multiplying the moles of nickel by its molar mass [Using $m = n \times M$]:

$m = 0.031093 \, mol \times 58.7 \, g \cdot mol^{-1}$

$m \approx 1.825 \, g$

Visual Representation of Electrolytic Process

Anode Cathode Ni(NO₃)₂ Solution Ni²⁺ + 2e⁻ → Ni

Final Solution: The mass of Ni deposited at the cathode is approximately 1.825 grams.


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