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Q2.6:
In the button cells widely used in watches and other devices the following reaction takes place: (Zn(s) + Ag_{2}O(s) + H_{2}O(l ) \rightarrow Zn^{2+}(aq) + 2Ag(s) + 2OH^{-}(aq)) Determine (\Delta_{r}G^{o}) and (E^{o}) for the reaction.

Solution :

Step 1: Identification of Half-Cell Reactions and Standard Potentials

To determine the standard Gibbs energy change ($\Delta_{r}G^{o}$) and standard cell potential ($E^{o}_{cell}$), we must first analyze the redox components of the cell reaction:

  • Oxidation Half-Reaction (Anode): $Zn(s) \rightarrow Zn^{2+}(aq) + 2e^{-}$ ; $E^{o}_{ox} = 0.76\,V$
  • Reduction Half-Reaction (Cathode): $Ag_{2}O(s) + H_{2}O(l) + 2e^{-} \rightarrow 2Ag(s) + 2OH^{-}(aq)$ ; $E^{o}_{red} = 0.344\,V$

[Per Standard Electrode Potential Tables (IUPAC convention)]

Step 2: Calculation of Standard Cell Potential ($E^{o}_{cell}$)

The standard cell potential is the algebraic sum of the standard reduction potentials of the cathode and the anode:

$E^{o}_{cell} = E^{o}_{cathode} - E^{o}_{anode}$

$E^{o}_{cell} = 0.344\,V - (-0.76\,V)$

$E^{o}_{cell} = 0.344\,V + 0.76\,V = 1.104\,V$

Step 3: Determination of Gibbs Energy Change ($\Delta_{r}G^{o}$)

The relationship between the standard Gibbs energy and standard cell potential is governed by the Nernstian thermodynamic equation:

$\Delta_{r}G^{o} = -nFE^{o}_{cell}$

Where:

  • $n = 2$ (number of moles of electrons transferred in the balanced equation)
  • $F = 96487\,C\,mol^{-1}$ (Faraday's constant)
  • $E^{o}_{cell} = 1.104\,V$

Substituting the values:

$\Delta_{r}G^{o} = -(2\,mol\,e^{-}) \times (96487\,C\,mol^{-1}) \times (1.104\,J\,C^{-1})$

$\Delta_{r}G^{o} = -213043.584\,J\,mol^{-1}$

$\Delta_{r}G^{o} \approx -213.04\,kJ\,mol^{-1}$

Visual Representation of Cell Potential (Schematic)

Zn Anode Ag Cathode E° = 1.104 V

Summary of Data

Parameter Calculated Value
Standard Cell Potential ($E^{o}$) $1.104\,V$
Standard Gibbs Energy ($\Delta_{r}G^{o}$) $-213.04\,kJ\,mol^{-1}$

Final Solution: The standard cell potential $E^{o}$ is $1.104\,V$ and the standard Gibbs energy change $\Delta_{r}G^{o}$ is $-213.04\,kJ\,mol^{-1}$.


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