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Q9.8(iii):
Write chemical equations for combustion reaction of the following hydrocarbons: (iii) Hexyne

Solution :

Step 1: Determining the Molecular Formula

Hexyne is an alkyne with the general formula $C_nH_{2n-2}$. For "hex" (where $n=6$):

$C_6H_{2(6)-2} = C_6H_{10}$

[Per IUPAC nomenclature and homologous series rules for alkynes].

Step 2: Defining the Combustion Reaction

Complete combustion of a hydrocarbon requires oxygen ($O_2$) to produce carbon dioxide ($CO_2$) and water ($H_2O$). The unbalanced chemical equation is:

$C_6H_{10} + O_2 \rightarrow CO_2 + H_2O$

Step 3: Balancing the Chemical Equation

To balance the equation, we follow the principle of Conservation of Mass [Per the Law of Conservation of Mass]:

  • Carbon (C): 6 atoms on the left require $6CO_2$ on the right.
  • Hydrogen (H): 10 atoms on the left require $5H_2O$ on the right (since $5 \times 2 = 10$).
  • Oxygen (O): On the right, we have $(6 \times 2) + (5 \times 1) = 17$ oxygen atoms. To obtain 17 atoms from $O_2$, we require $\frac{17}{2}$ molecules of $O_2$.

The balanced equation is:

$C_6H_{10} + \frac{17}{2}O_2 \rightarrow 6CO_2 + 5H_2O$

Step 4: Converting to Integer Coefficients

To eliminate the fraction, multiply the entire equation by 2:

$2C_6H_{10} + 17O_2 \rightarrow 12CO_2 + 10H_2O$

Visual Representation of Stoichiometry

2 C₆H₁₀ + 17 O₂ 12 CO₂ + 10 H₂O Reaction: Complete Combustion of Hexyne

Data Summary Table

Species Coefficient Atomic Contribution
$C_6H_{10}$ 2 12 C, 20 H
$O_2$ 17 34 O
$CO_2$ 12 12 C, 24 O
$H_2O$ 10 20 H, 10 O

Final Solution: The balanced combustion reaction for hexyne is 2C_6H_{10} + 17O_2 \rightarrow 12CO_2 + 10H_2O


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