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Q9.7:
Propanal and pentan-3-one are the ozonolysis products of an alkene? What is the structural formula of the alkene?

Solution :

Step 1: Analyzing Ozonolysis Mechanisms

Ozonolysis is a chemical process involving the reaction of an alkene with ozone ($O_3$) followed by reductive workup (typically using $Zn/H_2O$). The reaction involves the cleavage of the $C=C$ double bond to form two carbonyl groups (aldehydes or ketones). The general reaction schema is:
$R_1R_2C=CR_3R_4 + O_3 \rightarrow \text{Ozonide} \xrightarrow{Zn/H_2O} R_1R_2C=O + R_3R_4C=O$

Step 2: Identifying the Carbonyl Fragments

The problem provides two products:

  • Propanal: $CH_3CH_2CHO$ (An aldehyde where the carbonyl carbon is bonded to an ethyl group and a hydrogen atom).
  • Pentan-3-one: $CH_3CH_2COCH_2CH_3$ (A ketone where the carbonyl carbon is bonded to two ethyl groups).
[Per the mechanism of ozonolysis, the oxygen atoms of the products originate from the ozone molecule, while the $C=O$ double bond replaces the original $C=C$ bond].

Step 3: Reconstructing the Alkene Structure

To determine the structure of the alkene, we remove the two oxygen atoms from the carbonyl products and join the two carbonyl carbons with a double bond.
Fragment 1: $CH_3CH_2CH=O$
Fragment 2: $O=C(CH_2CH_3)_2$
Joining the carbons: $CH_3CH_2CH=C(CH_2CH_3)_2$

Step 4: Structural Representation and IUPAC Nomenclature

The resulting structure is $CH_3CH_2CH=C(CH_2CH_3)_2$. Expanding this structure gives:
$CH_3-CH_2-CH=C(CH_2CH_3)-CH_2CH_3$
This molecule is 3-ethylpent-2-ene.

Step 5: Visual Representation

CH3CH2 C(CH2CH3)2 Alkene: 3-ethylpent-2-ene

Step 6: Verification

Reactant Cleavage Point Product 1 Product 2
$CH_3CH_2CH=C(CH_2CH_3)_2$ Across $C=C$ $CH_3CH_2CHO$ $CH_3CH_2COCH_2CH_3$

[By the Law of Conservation of Mass and the stoichiometric nature of ozonolysis, the fragments account for the entirety of the original carbon skeleton].

Final Solution: The alkene is 3-ethylpent-2-ene, with the structural formula $CH_3CH_2CH=C(CH_2CH_3)_2$.


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