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Q9.20(i):
How would you convert the following compounds into benzene? (i) Ethyne

Solution :

Given Variables & Initial Setup

The objective is to synthesize benzene ($C_6H_6$) from ethyne ($C_2H_2$), also known as acetylene. This transformation involves the trimerization of alkynes, specifically a controlled polymerization process.

Step 1: Chemical Principle of Cyclotrimerization

The conversion of ethyne to benzene is achieved via cyclic polymerization. When ethyne gas is passed through a red-hot iron tube at elevated temperatures, three molecules of ethyne undergo a catalyzed cyclization reaction to form the aromatic ring of benzene.

Chemical Equation: $3C_2H_2 \xrightarrow{\text{Red-hot Fe tube, 873 K}} C_6H_6$ [Per the principle of Alkyne Cyclotrimerization]

Step 2: Reaction Mechanism Analysis

  • Reactant: Ethyne ($HC \equiv CH$)
  • Conditions: The temperature is maintained at approximately $873 \text{ K}$ ($600^{\circ}\text{C}$) to provide the activation energy required for the formation of the transition state.
  • Catalyst: Iron (Fe) acts as a heterogeneous catalyst to lower the activation energy for the [2+2+2] cycloaddition.
  • Product: Benzene ($C_6H_6$), a stable, planar, cyclic aromatic compound.

Visual Representation of the Reaction

3 (HC≡CH) Red-hot Fe, 873K C₆H₆

Step 3: Justification of Aromaticity

The conversion is thermodynamically favorable because it results in the formation of an aromatic system. Benzene satisfies Hückel’s Rule, $4n + 2$ $\pi$-electrons, where $n=1$, leading to a stabilization energy known as resonance energy. [Per Hückel's Rule of Aromaticity]

Property Ethyne Benzene
Hybridization $sp$ $sp^2$
Structure Linear Planar Hexagon
Bond Order 3 (C-C triple bond) 1.5 (Delocalized)

Final Solution: The conversion of ethyne to benzene is performed by passing ethyne gas through a red-hot iron tube at 873 K, resulting in the cyclic trimerization of three ethyne molecules into one molecule of benzene.


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