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Q9.20(iii):
How would you convert the following compounds into benzene? (iii) Hexane

Solution :

Step 1: Theoretical Foundation of Aromatization

The conversion of an aliphatic alkane, specifically $n$-hexane ($C_6H_{14}$), into an aromatic hydrocarbon like benzene ($C_6H_6$) is achieved through a process known as dehydrocyclization or aromatization. This reaction involves the simultaneous removal of hydrogen atoms (dehydrogenation) and the formation of a six-membered ring (cyclization). [Per the principles of catalytic reforming in petrochemical industries].

Step 2: Reaction Conditions and Reagents

To facilitate the transformation of $n$-hexane to benzene, the alkane must be subjected to high temperatures and high pressures in the presence of metallic catalysts. The standard laboratory and industrial conditions are as follows:

  • Temperature: $773\text{ K}$ ($500^\circ\text{C}$)
  • Pressure: $10\text{--}20\text{ atm}$
  • Catalysts: Oxides of Vanadium ($V_2O_5$), Molybdenum ($Mo_2O_3$), or Chromium ($Cr_2O_3$) supported over Alumina ($Al_2O_3$).

Step 3: Chemical Equation and Mechanism

The reaction proceeds via the dehydrogenation of the hexane chain followed by cyclization to form cyclohexane, which is subsequently dehydrogenated to yield the fully aromatic benzene ring.

Chemical Equation: $CH_3-(CH_2)_4-CH_3 \xrightarrow[Cr_2O_3/Al_2O_3, 773K]{} C_6H_6 + 4H_2$

Step 4: Visual Representation of the Aromatization Process

CH₃ CH₃ → Cr₂O₃/Al₂O₃ 773K, 10-20 atm Benzene + 4H₂

Step 5: Analytical Summary

The process is thermodynamically favorable at elevated temperatures due to the significant increase in entropy caused by the liberation of four moles of hydrogen gas for every mole of benzene produced [Per the Gibbs Free Energy equation $\Delta G = \Delta H - T\Delta S$].

Reactant Product Process Classification
$n$-Hexane ($C_6H_{14}$) Benzene ($C_6H_6$) Dehydrocyclization

Final Solution: $n$-Hexane is converted to benzene by heating it to 773 K under 10-20 atm pressure in the presence of $Cr_2O_3$, $V_2O_5$, or $Mo_2O_3$ supported on alumina.


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