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Q9.8(i):
Write chemical equations for combustion reaction of the following hydrocarbons: (i) Butane

Solution :

Step 1: Chemical Formula and Theoretical Foundation

Butane is an alkane with the general formula $C_nH_{2n+2}$. For $n=4$, the molecular formula is $C_4H_{10}$. [Per the General Alkanes Formula]. Combustion is a high-temperature exothermic redox reaction between a fuel (the hydrocarbon) and an oxidant (atmospheric oxygen, $O_2$), resulting in the formation of carbon dioxide ($CO_2$) and water ($H_2O$).

Step 2: Unbalanced Skeletal Equation

The skeletal reaction is represented as:

$C_4H_{10}(g) + O_2(g) \rightarrow CO_2(g) + H_2O(l)$

Step 3: Balancing the Chemical Equation

To satisfy the Law of Conservation of Mass, we must balance the atoms on both sides of the equation.

  • Balance Carbon: There are $4$ carbon atoms in $C_4H_{10}$, so we require $4$ moles of $CO_2$.
    $C_4H_{10} + O_2 \rightarrow 4CO_2 + H_2O$
  • Balance Hydrogen: There are $10$ hydrogen atoms in $C_4H_{10}$, so we require $5$ moles of $H_2O$ (since $5 \times 2 = 10$).
    $C_4H_{10} + O_2 \rightarrow 4CO_2 + 5H_2O$
  • Balance Oxygen: Counting the right-hand side (RHS), we have $(4 \times 2) + (5 \times 1) = 8 + 5 = 13$ oxygen atoms. Since $O_2$ is diatomic, we require $\frac{13}{2}$ moles of $O_2$.
    $C_4H_{10} + \frac{13}{2}O_2 \rightarrow 4CO_2 + 5H_2O$

Step 4: Integer Coefficient Normalization

To represent the reaction using the smallest whole-number coefficients, multiply the entire equation by $2$ [By Convention for Stoichiometric Representation]:

$2C_4H_{10}(g) + 13O_2(g) \rightarrow 8CO_2(g) + 10H_2O(l)$

Visual Representation of Combustion Stoichiometry

2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O Stoichiometric Combustion of Butane

Final Solution: The balanced chemical equation for the combustion of butane is $2C_4H_{10}(g) + 13O_2(g) \rightarrow 8CO_2(g) + 10H_2O(l) + \text{Heat}$


More Questions from Class 11 Chemistry Hydrocarbons EXERCISES


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