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Q9.21:
Write structures of all the alkenes which on hydrogenation give 2-methylbutane.

Solution :

Given Objective

Identify all possible alkene structural isomers that yield 2-methylbutane upon catalytic hydrogenation. Hydrogenation involves the addition of $H_2$ across a carbon-carbon double bond ($C=C$) in the presence of a metal catalyst ($Ni, Pd, or Pt$).

Step 1: Identifying the Target Alkane Structure

The product is 2-methylbutane ($C_5H_{12}$). The parent chain consists of four carbons with a methyl group at the second position: $CH_3-CH(CH_3)-CH_2-CH_3$.

Step 2: Theoretical Principle of Hydrogenation

Hydrogenation of an alkene of general formula $C_nH_{2n}$ produces the corresponding alkane $C_nH_{2n+2}$. The double bond in the alkene must be located between two carbons that remain connected in the final alkane. Thus, if a double bond is placed between any two adjacent carbon atoms in the carbon skeleton of 2-methylbutane, hydrogenation will result in the same saturated alkane.

Step 3: Determining Possible Double Bond Positions

We analyze the 2-methylbutane skeleton to identify unique positions for the $C=C$ bond:

C1-C2(methyl)-C3-C4 C1 C2 C3 C4

The distinct alkenes are generated by placing a double bond between adjacent carbons:

  • Position 1: Double bond between C1 and C2
    $CH_2=C(CH_3)-CH_2-CH_3$ (2-methylbut-1-ene)
  • Position 2: Double bond between C2 and C3
    $CH_3-C(CH_3)=CH-CH_3$ (2-methylbut-2-ene)
  • Position 3: Double bond between C3 and C4
    $CH_3-CH(CH_3)-CH=CH_2$ (3-methylbut-1-ene)

Step 4: Verification of Structures

Alkene Name Condensed Structural Formula Hydrogenation Product
2-methylbut-1-ene $CH_2=C(CH_3)CH_2CH_3$ 2-methylbutane
2-methylbut-2-ene $CH_3C(CH_3)=CHCH_3$ 2-methylbutane
3-methylbut-1-ene $CH_3CH(CH_3)CH=CH_2$ 2-methylbutane

Analytical Note

Per the Markovnikov rule's reverse application, the addition of hydrogen to these unsaturated systems [Hydrogenation Mechanism: Syn-addition of $H_2$ on the metal surface] uniformly saturates the backbone to yield the branched alkane 2-methylbutane.

Final Solution: The alkenes that yield 2-methylbutane upon hydrogenation are: 2-methylbut-1-ene, 2-methylbut-2-ene, and 3-methylbut-1-ene.


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