Find the best tutors and institutes for Class 10 Tuition
Q8:
$E$ is a point on the side $AD$ produced of a parallelogram $ABCD$ and $BE$ intersects $CD$ at $F$. Show that $\triangle ABE \sim \triangle CFB$.
Solution :
Given: A parallelogram $ABCD$ where $E$ is a point on the side $AD$ produced. The line segment $BE$ intersects the side $CD$ at point $F$.
To Prove: $\triangle ABE \sim \triangle CFB$.
Step 1: Identifying the properties of the parallelogram $ABCD$.
In a parallelogram $ABCD$, opposite sides are parallel and opposite angles are equal. Therefore:
$AD \parallel BC$ [Definition of a parallelogram]
Since $E$ lies on the extension of $AD$, it follows that $AE \parallel BC$.
Also, $\angle A = \angle C$ [Opposite angles of a parallelogram are equal].
Step 2: Analyzing $\triangle ABE$ and $\triangle CFB$.
We compare the two triangles based on the Angle-Angle (AA) similarity criterion.
Consider $\angle A$ in $\triangle ABE$ and $\angle BCF$ in $\triangle CFB$.
Since $ABCD$ is a parallelogram, $\angle A = \angle BCD$ [Opposite angles of a parallelogram].
Note that $\angle BCF$ is the same as $\angle BCD$. Thus, $\angle A = \angle BCF$.
Step 3: Establishing the second pair of equal angles.
Consider the parallel lines $AE$ and $BC$ intersected by the transversal $BE$.
$\angle AEB = \angle CBF$ [Alternate interior angles are equal when two parallel lines are intersected by a transversal].
Note that $\angle AEB$ is the same as $\angle AEB$ in $\triangle ABE$, and $\angle CBF$ is the same as $\angle CBF$ in $\triangle CFB$.
Step 4: Applying the AA Similarity Criterion.
In $\triangle ABE$ and $\triangle CFB$:
1. $\angle A = \angle BCF$ [Proved in Step 2]
2. $\angle AEB = \angle CBF$ [Proved in Step 3]
Therefore, by the AA similarity criterion, $\triangle ABE \sim \triangle CFB$.
Final Answer: Since two angles of $\triangle ABE$ are equal to two angles of $\triangle CFB$, the triangles are similar by the AA similarity criterion: $\triangle ABE \sim \triangle CFB$.
More Questions from Class 10 Mathematics Triangles EXERCISE 6.3
- Q1(i): State which pairs of triangles in Fig. 6.34 are similar. Write the similarity criterion used by you for answering the question and also write the pairs of similar triangles in the symbolic form : (i)
- Q1(ii): State which pairs of triangles in Fig. 6.34 are similar. Write the similarity criterion used by you for answering the question and also write the pairs of similar triangles in the symbolic form : (ii)
- Q1(iii): State which pairs of triangles in Fig. 6.34 are similar. Write the similarity criterion used by you for answering the question and also write the pairs of similar triangles in the symbolic form : (iii)
- Q1(iv): State which pairs of triangles in Fig. 6.34 are similar. Write the similarity criterion used by you for answering the question and also write the pairs of similar triangles in the symbolic form : (iv)
- Q1(v): State which pairs of triangles in Fig. 6.34 are similar. Write the similarity criterion used by you for answering the question and also write the pairs of similar triangles in the symbolic form : (v)
- Q1(vi): State which pairs of triangles in Fig. 6.34 are similar. Write the similarity criterion used by you for answering the question and also write the pairs of similar triangles in the symbolic form : (vi)
- Q2: In Fig. 6.35, $\triangle ODC \sim \triangle OBA$, $\angle BOC = 125^{\circ}$ and $\angle CDO = 70^{\circ}$. Find $\angle DOC$, $\angle DCO$ and $\angle OAB$.
- Q3: Diagonals $AC$ and $BD$ of a trapezium $ABCD$ with $AB \parallel DC$ intersect each other at the point $O$. Using a similarity criterion for two triangles, show that $\frac{OA}{OC} = \frac{OB}{OD}$.
- Q4: In Fig. 6.36, $\frac{QR}{QS} = \frac{QT}{PR}$ and $\angle 1 = \angle 2$. Show that $\triangle PQS \sim \triangle TQR$.
- Q5: $S$ and $T$ are points on sides $PR$ and $QR$ of $\triangle PQR$ such that $\angle P = \angle RTS$. Show that $\triangle RPQ \sim \triangle RTS$.
- Q6: In Fig. 6.37, if $\triangle ABE \cong \triangle ACD$, show that $\triangle ADE \sim \triangle ABC$.
- Q7(i): In Fig. 6.38, altitudes $AD$ and $CE$ of $\triangle ABC$ intersect each other at the point $P$. Show that: (i) $\triangle AEP \sim \triangle CDP$
- Q7(ii): In Fig. 6.38, altitudes $AD$ and $CE$ of $\triangle ABC$ intersect each other at the point $P$. Show that: (ii) $\triangle ABD \sim \triangle CBE$
- Q7(iii): In Fig. 6.38, altitudes $AD$ and $CE$ of $\triangle ABC$ intersect each other at the point $P$. Show that: (iii) $\triangle AEP \sim \triangle ADB$
- Q7(iv): In Fig. 6.38, altitudes $AD$ and $CE$ of $\triangle ABC$ intersect each other at the point $P$. Show that: (iv) $\triangle PDC \sim \triangle BEC$
- Q9(i): In Fig. 6.39, $ABC$ and $AMP$ are two right triangles, right angled at $B$ and $M$ respectively. Prove that: (i) $\triangle ABC \sim \triangle AMP$
- Q9(ii): In Fig. 6.39, $ABC$ and $AMP$ are two right triangles, right angled at $B$ and $M$ respectively. Prove that: (ii) $\frac{CA}{PA} = \frac{BC}{MP}$
- Q10(i): $CD$ and $GH$ are respectively the bisectors of $\angle ACB$ and $\angle EGF$ such that $D$ and $H$ lie on sides $AB$ and $FE$ of $\triangle ABC$ and $\triangle EFG$ respectively. If $\triangle ABC \sim \triangle FEG$, show that: (i) $\frac{CD}{GH} = \frac{AC}{FG}$
- Q10(ii): $CD$ and $GH$ are respectively the bisectors of $\angle ACB$ and $\angle EGF$ such that $D$ and $H$ lie on sides $AB$ and $FE$ of $\triangle ABC$ and $\triangle EFG$ respectively. If $\triangle ABC \sim \triangle FEG$, show that: (ii) $\triangle DCB \sim \triangle HGE$
- Q10(iii): $CD$ and $GH$ are respectively the bisectors of $\angle ACB$ and $\angle EGF$ such that $D$ and $H$ lie on sides $AB$ and $FE$ of $\triangle ABC$ and $\triangle EFG$ respectively. If $\triangle ABC \sim \triangle FEG$, show that: (iii) $\triangle DCA \sim \triangle HGF$
- Q11: In Fig. 6.40, $E$ is a point on side $CB$ produced of an isosceles triangle $ABC$ with $AB = AC$. If $AD \perp BC$ and $EF \perp AC$, prove that $\triangle ABD \sim \triangle ECF$.
- Q12: Sides $AB$ and $BC$ and median $AD$ of a triangle $ABC$ are respectively proportional to sides $PQ$ and $QR$ and median $PM$ of $\triangle PQR$ (see Fig. 6.41). Show that $\triangle ABC \sim \triangle PQR$.
- Q13: $D$ is a point on the side $BC$ of a triangle $ABC$ such that $\angle ADC = \angle BAC$. Show that $CA^2 = CB \cdot CD$.
- Q14: Sides $AB$ and $AC$ and median $AD$ of a triangle $ABC$ are respectively proportional to sides $PQ$ and $PR$ and median $PM$ of another triangle $PQR$. Show that $\triangle ABC \sim \triangle PQR$.
- Q15: A vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower.
- Q16: If $AD$ and $PM$ are medians of triangles $ABC$ and $PQR$, respectively where $\triangle ABC \sim \triangle PQR$, prove that $\frac{AB}{PQ} = \frac{AD}{PM}$.
CBSE Solutions for Class 10 Mathematics Triangles
Chapters in CBSE - Class 10 Mathematics
Top Tutors who teach Triangles
An experienced educator with over 5 years of teaching experience, I have had the privilege of mentoring more than 100 students. My expertise spans foundational high school courses (9th–10th Science, 11th–12th Biology) as well as advanced engineering disciplines (B.Tech & M.Tech). I hold a B.Tech, M.Tech, and Ph.D. in Biotechnology, alongside a competitive GATE qualification. My approach focuses on building deep conceptual clarity and critical thinking, followed by structured problem-solving, regular assessments, and rigorous PYQ practice. This exam-focused strategy ensures students achieve outstanding performance in both board exams and competitive tests.
Honestly, my experience at TTN Classes – Vigyan Classes has been really good 😊. Dr. Apoorva Singh Ma’am teaches very well 📚 and explains every concept in a simple and easy-to-understand way. Her classes are informative, interactive, and enjoyable 😄. She is very friendly and supportive with students 🤝, clears doubts patiently, and always motivates us to do better 💯. She also gives career counselling and guidance🎯, which really helps students understand their options and make better decisions about their future. I also really enjoy the celebrations 🎉 we have on different occasions like birthdays 🎂, results 🏆, and other events.These moments make the classes more memorable and create a great bond between students and teachers ❤️. Overall, I genuinely enjoy studying at Vigyan Classes. Great teaching 👩🏫, career guidance 🎯, a friendly environment 😊, and lots of memorable moments 🎉. Definitely a great experience!
I am Mathematics teacher teaching in a reputed school.
10+ years of experience teaching Mathematics for Grades 10 to 12th • Consistent record of 100% academic results • Very friendly and supportive learning environment • Encourages students to ask questions freely and confidently • Strong focus on conceptual clarity and problem-solving skills • Helps students build confidence and excel in Mathematics • Fee Structure for One-to-One Classes: ₹700 per hour • Group Classes: ₹4,000 per month.
This is Debabrato Chatterjee, an Maths and Science tutor with more than fifteen years of experience. I have been and am teaching students of IB, IGCSE, CBSE, ICSE, and Maharastra State Boards. My teaching style is to learning from concepts and their application. Solving many papers and completing homework helps grasp the concepts. I teach students from grade VI to XII. Please let me know when you would like to schedule a demo.
I am an experienced Spoken English and Class VI-X subject tutor with two years of experience in teaching. Currently, I am pursuing my bachelor's degree in BA from Magadh University. I can teach students who are in State, International Baccalaureate, CBSE and ICSE Board. My students have improved a lot through my teaching, and I've received five reviews till now with 100% positive feedback. I always try to understand my students and help them overcome their fear of failure in specific subjects like math and science.
Find more Tutor for Triangles in your City
- Bangalore Mathematics Tutors
- Delhi Mathematics Tutors
- Chennai Mathematics Tutors
- Gurgaon Mathematics Tutors
- Noida Mathematics Tutors
- Hyderabad Mathematics Tutors
- Mumbai Mathematics Tutors
- Ghaziabad Mathematics Tutors
- Chandigarh Mathematics Tutors
- Pune Mathematics Tutors
- Jaipur Mathematics Tutors
- Surat Mathematics Tutors
Download free CBSE - Class 10 Mathematics Triangles EXERCISE 6.3 worksheets
Download Now