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Q6:

In Fig. 6.37, if $\triangle ABE \cong \triangle ACD$, show that $\triangle ADE \sim \triangle ABC$.

Solution :

Given: $\triangle ABE \cong \triangle ACD$.

To Prove: $\triangle ADE \sim \triangle ABC$.

Visual Representation:

A B C D E

Step 1: Analyze the given congruence.

We are given that $\triangle ABE \cong \triangle ACD$. By the property of Congruent Triangles (CPCT - Corresponding Parts of Congruent Triangles), the corresponding sides and angles are equal.

Therefore, $AB = AC$ --- (Equation 1)

And, $AE = AD$ --- (Equation 2)

Step 2: Formulate ratios from the equations.

From Equation 1, we can write: $\frac{AB}{AC} = 1$

From Equation 2, we can write: $\frac{AD}{AE} = 1$

Equating the two, we get: $\frac{AB}{AC} = \frac{AD}{AE}$

By rearranging the terms to align with the sides of $\triangle ADE$ and $\triangle ABC$, we get:

$\frac{AD}{AB} = \frac{AE}{AC}$ --- (Equation 3)

Step 3: Identify the common angle.

In $\triangle ADE$ and $\triangle ABC$, consider the angle at vertex $A$:

$\angle DAE = \angle BAC$ (Common angle to both triangles)

Step 4: Apply the SAS Similarity Criterion.

The SAS (Side-Angle-Side) Similarity Criterion states that if one angle of a triangle is equal to one angle of the other triangle and the sides including these angles are proportional, then the two triangles are similar.

From Equation 3, we have the ratio of the sides: $\frac{AD}{AB} = \frac{AE}{AC}$.

From Step 3, we have the included angle: $\angle DAE = \angle BAC$.

Therefore, by SAS similarity criterion:

$\triangle ADE \sim \triangle ABC$

Final Answer: Since the ratio of the corresponding sides is equal and the included angle is common, $\triangle ADE \sim \triangle ABC$ is proved.


More Questions from Class 10 Mathematics Triangles EXERCISE 6.3


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