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Q10(ii):
$CD$ and $GH$ are respectively the bisectors of $\angle ACB$ and $\angle EGF$ such that $D$ and $H$ lie on sides $AB$ and $FE$ of $\triangle ABC$ and $\triangle EFG$ respectively. If $\triangle ABC \sim \triangle FEG$, show that: (ii) $\triangle DCB \sim \triangle HGE$

Solution :

Given:

1. $\triangle ABC \sim \triangle FEG$.

2. $CD$ is the bisector of $\angle ACB$, where $D$ lies on $AB$.

3. $GH$ is the bisector of $\angle EGF$, where $H$ lies on $FE$.

To Prove:

$\triangle DCB \sim \triangle HGE$

A C B D F E G H

Step 1: Utilizing the property of similar triangles.

Since $\triangle ABC \sim \triangle FEG$, their corresponding angles are equal [By definition of similar triangles]:

$\angle A = \angle F$

$\angle ABC = \angle FEG$ (which can be written as $\angle DBC = \angle HGE$)

$\angle ACB = \angle FGE$

Step 2: Applying the angle bisector property.

We are given that $CD$ bisects $\angle ACB$ and $GH$ bisects $\angle FGE$.

Therefore, $\angle DCB = \frac{1}{2} \angle ACB$ [Since $CD$ is the bisector of $\angle ACB$].

And, $\angle HGE = \frac{1}{2} \angle FGE$ [Since $GH$ is the bisector of $\angle FGE$].

Step 3: Establishing equality of angles.

Since $\angle ACB = \angle FGE$ [From Step 1], it follows that:

$\frac{1}{2} \angle ACB = \frac{1}{2} \angle FGE$

$\angle DCB = \angle HGE$

Step 4: Proving similarity of $\triangle DCB$ and $\triangle HGE$.

In $\triangle DCB$ and $\triangle HGE$:

1. $\angle DBC = \angle HGE$ [Already established in Step 1 as $\angle ABC = \angle FEG$].

2. $\angle DCB = \angle HGE$ [Established in Step 3].

By the Angle-Angle (AA) similarity criterion, if two angles of one triangle are respectively equal to two angles of another triangle, then the two triangles are similar.

Therefore, $\triangle DCB \sim \triangle HGE$.

Final Answer: Since $\angle DBC = \angle HGE$ and $\angle DCB = \angle HGE$, by AA similarity criterion, $\triangle DCB \sim \triangle HGE$.


More Questions from Class 10 Mathematics Triangles EXERCISE 6.3


CBSE Solutions for Class 10 Mathematics Triangles


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