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Q5:
$S$ and $T$ are points on sides $PR$ and $QR$ of $\triangle PQR$ such that $\angle P = \angle RTS$. Show that $\triangle RPQ \sim \triangle RTS$.

Solution :

Given: A triangle $\triangle PQR$ where $S$ is a point on side $PR$ and $T$ is a point on side $QR$. It is given that $\angle P = \angle RTS$.

To Prove: $\triangle RPQ \sim \triangle RTS$.

P Q R S T

Step 1: Identifying the triangles to be compared.
We are required to prove the similarity between $\triangle RPQ$ and $\triangle RTS$. Let us examine the vertices of these two triangles:

  • Triangle 1: $\triangle RPQ$
  • Triangle 2: $\triangle RTS$

Step 2: Analyzing the angles of the triangles.
To prove that two triangles are similar, we can use the Angle-Angle (AA) similarity criterion, which states that if two angles of one triangle are respectively equal to two angles of another triangle, then the two triangles are similar.

Consider $\triangle RPQ$ and $\triangle RTS$:
1. In $\triangle RPQ$, we have $\angle R$ (which is $\angle PRQ$).
2. In $\triangle RTS$, we have $\angle R$ (which is $\angle TRS$).
Since both triangles share the same vertex $R$, we can state: $\angle PRQ = \angle TRS$ [Common angle to both triangles]

Step 3: Utilizing the given information.
It is explicitly given in the problem statement that: $\angle P = \angle RTS$
In the context of our triangles: $\angle RPQ = \angle RTS$ [Given]

Step 4: Applying the AA Similarity Criterion.
We have established two correspondences between the angles of $\triangle RPQ$ and $\triangle RTS$:
1. $\angle R = \angle R$ [Common angle]
2. $\angle P = \angle RTS$ [Given]

By the Angle-Angle (AA) similarity criterion, if two angles of one triangle are equal to two angles of another triangle, the triangles are similar.
Therefore, $\triangle RPQ \sim \triangle RTS$.

Final Answer: Since $\angle R = \angle R$ (common) and $\angle P = \angle RTS$ (given), by the AA similarity criterion, $\triangle RPQ \sim \triangle RTS$.


More Questions from Class 10 Mathematics Triangles EXERCISE 6.3


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