Force of 16N and 12N are acting on a mass of 200kg in mutually perpendicular directions. Find the magnitude of the acceleration produced.

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Sujoy Das

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Resultant force F= sqrt (16^2+12^2) => F=20N So F=ma => a=F/m=20/200 => a=0.1 ms-2
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Total magnitude of Force is {(16)^2 + (12)^2}^1/2 = (256 + 144)^1/2=20 N Now,Force = Mass x Acceleration==>Acceleration = Force/Mass =20/200 = 0.1 m/sec^2
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16N and 12N are acting in mutually perpendicular direction. So resultant force = â??(16² + 12²) = â??256+144 = â??400 = 20N mass of body = 200 kg acceleration = net force/mass = 20/200 = 0.1 m/s².
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16N and 12N are acting in mutually perpendicular direction. So resultant force = â??(16² + 12²) = â??256+144 = â??400 = 20N mass of body = 200 kg acceleration = net force/mass = 20/200 = 0.1 m/s²
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Easy, Qualitative and Tricky Mathematician

Simple take resultant force of 16N and 12N and it will become 20N Then a= F/m so 20N / 200kg ==0.1 N/kg
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16N and 12N are acting in mutually perpendicular direction. So resultant force = â??(16² + 12²) = â??256+144 = â??400 = 20N
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SINGER CUM MATH MAGICIAN

16N and 12N are acting in mutually perpendicular direction. So resultant force = â??(16² + 12²) = â??(256+144) = â??400 = 20N
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Maths Teacher

F=ma , net force is 16-12=4N then 4N=200kg*a , so a=.002 m/s2
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16N and 12N are acting in mutually perpendicular direction. So resultant force = â??(16² + 12²) = â??256+144 = â??400 = 20N mass of body = 200 kg acceleration = net force/mass = 20/200 = 0.1 m/s2
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Resultant force F=sqrt (16^2+12^2) => F=20N So F=ma => a=F/m=20/200 => a=0.1ms-2
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