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Class 11 Tuition > Learn Physics > State and explain Newton's law of cooling.
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State and explain Newton's law of cooling.

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Newton’s Law of Cooling states that the rate of temperature of the body is proportional to the difference between the temperature of the body and that of the surrounding medium. It is a reasonably accurate approximation in some circumstances. More precisely, let T denote the temperature of an object...
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Newton’s Law of Cooling states that the rate of temperature of the body is proportional to the difference between the temperature of the body and that of the surrounding medium. It is a reasonably accurate approximation in some circumstances. More precisely, let T denote the temperature of an object and Tο the ambient temperature. if t denotes time, then Newton's law states that dT/dt = -k(T-Tο) where k is a positive constant. Thus, if the object temperature is much higher than its surroundings, then T-Tο is large and positive, so dTdT/dt is large and negative, so the object cools quickly. If the object temperature is only slightly higher than its surroundings, then T-Tο is small positive, and the object cools slowly. So a cup of coffee will cool more quickly if you put it in the refrigerator! read less
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Newton’s Law of Cooling states that the rate of change of temperature of a body is proportional to the difference between the temperature of the body and that of the surrounding medium. It is a reasonably accurate approximation in some circumstances. More precisely, let T denote the temperature...
read more
Newton’s Law of Cooling states that the rate of change of temperature of a body is proportional to the difference between the temperature of the body and that of the surrounding medium. It is a reasonably accurate approximation in some circumstances. More precisely, let T denote the temperature of an object and Tο the ambient temperature. if t denotes time, then Newton's law states that dT/dt = -k(T-Tο) where k is a positive constant. Thus, if the object temperature is much higher than its surroundings, then T-Tο is large and positive, so dTdT/dt is large and negative, so the object cools quickly. If the object temperature is only slightly higher than its surroundings, then T-Tο is small positive, and the object cools slowly. So a cup of coffee will cool more quickly if you put it in the refrigerator! read less
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It states that rate of cooling of a body is proportional to the excess temperature of body over surroundings. dQ/dt= -K(T2-T1) where T1 is temperature of surroundings T2 is temperature of body. It is our observation that cloths get dry early when outside temperature is more than in winter. ...
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It states that rate of cooling of a body is proportional to the excess temperature of body over surroundings. dQ/dt= -K(T2-T1) where T1 is temperature of surroundings T2 is temperature of body. It is our observation that cloths get dry early when outside temperature is more than in winter. Heat lost by body is -msdT2 when temperature falls by small amount T2 in small time dt. m mass of body s is specific heat capacity.T2 is temp of body. Rate of loss of heat dQ/dt=msdT2/dt read less
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Related Questions

An elevator weighs 3000kg. What is its acceleration when the in the tension supporting cable is 33000N. Given that g = 9.8m/s2.
M = 3000 kg g = 9.8 m/s² T = 33000 a = ? Ma = Mg - T 3000 * a = 3000 * 9.8 - 33000 3000a = 29400 - 33000 3000a = - 3600 a = - 1.2 m/s².
Vishal

Does Newton's 2nd law of motion contain the 1st law as a special case?
Yes, as per newton's second law, F=ma. Hence, if F=0, then a=0, which is nothing but the essence of the first law, which states that everybody continues to be in its state of rest or of its uniform motion...
Souradeep
A lift is accelerated upward. Will the apparent weight of a person inside the lift increase, decrease or remain the same relative to its real weight? If the lift is going with uniform speed, then?
Thd apparent weight of the person will increase. When in uniform speed then acceleration is zero, so no change in weight.
Shubham
Force of 16N and 12N are acting on a mass of 200kg in mutually perpendicular directions. Find the magnitude of the acceleration produced.
Resultant force F= sqrt (16^2+12^2) => F=20N So F=ma => a=F/m=20/200 => a=0.1 ms-2
Abhishek
derivation of v2/r=ac
Below sheets has elaborate details of centripetal acceleration:
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