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Sameer went on his bike from Delhi to Gurgaon at a speed of 60km/hr and came back at a speed of 40km/hr. What is his average speed for entire journey?

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To find the average speed, you need to know the formula of average speed. The avg speed 0= 2 d / (t1+ t2) = 2 v1.v2/(V1 + V2). Just substitute the value.
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(2×60×40)÷(60+40)=4800÷100=48km/hr
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Physics Teacher

(2×60×40)÷(60+40) =4800÷100 =48km/hr
1 Comments

(2×60×40)÷(40+60)=4800÷100=48km/hr
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Primary Teacher

average speed = 2x/{x/60 + x/40} = 2x/ {(2x + 3x)/120} = 120.2x/ 5x = 48 Km/hr.
Comments

Primary Teacher

average speed = 2x/{x/60 + x/40} = 2x/ {(2x + 3x)/120} = 120.2x/ 5x = 48 Km/hr.
Comments

Primary Teacher

average speed = 2x/{x/60 + x/40} = 2x/ {(2x + 3x)/120} = 120.2x/ 5x = 48 Km/hr.
Comments

Primary Teacher

average speed = 2x/{x/60 + x/40} = 2x/ {(2x + 3x)/120} = 120.2x/ 5x = 48 Km/hr.
Comments

Primary Teacher

average speed = 2x/{x/60 + x/40} = 2x/ {(2x + 3x)/120} = 120.2x/ 5x = 48 Km/hr.
Comments

Primary Teacher

average speed = 2x/{x/60 + x/40} = 2x/ {(2x + 3x)/120} = 120.2x/ 5x = 48 Km/hr.
Comments

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