Solve : 55x + 52y = 217; 52x + 55y = 217

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Rohit Gupta

subtract two equations from each other, we get x=y and then substitute x=y in any of the equation we get values for x and y . x=1.972 ,y= 1.972
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Biotechnologist

Firstly, from the first equation, find x. From eqn 1: x = 217 - 52y/55. Now, substitute this value of x in the first eqn. i.e. 52 X (217 - 52y)/55 = 217 Now, multiply both sides with the denominator 55. Therefore, the eqn is 52(217-52y) + 3025y=11935 Solve for y. y = 217/107 ...
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Firstly, from the first equation, find x. From eqn 1: x = 217 - 52y/55. Now, substitute this value of x in the first eqn. i.e. 52 X (217 - 52y)/55 = 217 Now, multiply both sides with the denominator 55. Therefore, the eqn is 52(217-52y) + 3025y=11935 Solve for y. y = 217/107 Now, substitute this value of y in the x = 217 - 52y/55 which was derived from the original eqn. Therefore x = 217 - 52(217/107) /55 which is x = 217/107. Therefore, x = y = 217/107 read less
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Tutor

First of all this is a question of simultaneous equations. But it has a trick under its sleeve. The main thing is to identify that little twist in this question. The RHS of both the equations have the same number. So, if we subtract one equation from the other, we can express x in terms of y. Lets...
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First of all this is a question of simultaneous equations. But it has a trick under its sleeve. The main thing is to identify that little twist in this question. The RHS of both the equations have the same number. So, if we subtract one equation from the other, we can express x in terms of y. Lets do it... 55x + 52y - 52x - 55y = 217-217 3x - 3y = 0 x = y. Great!! We got x = y. So substituting x in place of y in 1st equation we can get the value of x. Therefore, 55x + 52x = 217 107x = 217 x = 217/107 = 2.028 Also, y = x So y = 2.028 Therefore, the solution is (2.028,2.028) read less
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Tutor

X=Y=217/107
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Trainer

=>55x+52y=217..........................(i) =>52x+55y=217..........................(ii) Adding equation (i) & (ii), We have 77 (x+y)=434 =>x+y=434/77..................(iii) Subtracting (ii) from (i), We have=>x-y=0-----------------------(iv) From equation (iii) & (iv), we have x=217/77 y=217...
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Tutor

2.02
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As the summation of both eqns are same, we can equate the equations 52x+55y = 55x+52y => 3y=3x ( same eqn can be achieved by subtracting both eqns) => x=y Now putting this in any eqn We get 55x + 52x=217 => 107x=217 => x =y=217/107
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Eco, Maths and Stats Tutor

subtract any one of the equations from another to get x=y. substitute this in any one of the equations to get x=y=2.03
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Related Questions

Given that HCF (161,345) = 23, find their LCM.
N¹ *N² = LCM * HCF 161 *345 =23 * N² N² =2415
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The mean of 10, 15, x, 5, 15 is 15. What is the value of x?
(10+15+x+5+15)/5=15 So 45 + x = 5*15 X=75-45=30
Rayyan
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How to learn math online?
Via skype you can teach everything online
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What needs to be done to score 100% in maths if my ward is scoring 95% in class IX CBSE?

 
It is not a big job to score 100 out of 100 in mathematics. A Good dedicated teacher and a real dedication can help you score 100%.
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Hi, I am Deepak, form Navy nagar, Mumbai. I want to teach math and science to class viii,viii,ix and x (english or hindi medium) both online or offline. can I get some student in Colaba?
Yes buddy definitely you will get students . For that you need to be quite patient and you need to have a look at the urban pro account frequently everyday because this is a compitative world someone else might get hired if you are not active .
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