UrbanPro
Login Ask & Answer Success Stories Paid Courses Free Classes Tuition & Classes Fees Write a Review All Categories Help Center
Post your Learning Need Signup as a Tutor
✕

Popular Cities

Bangalore

Hyderabad

Delhi

Mumbai

Chennai

Pune

Kolkata

Gurgaon

Ahmedabad

Jaipur

Noida

✕
true

Engineering Diploma Tuition > Engineering Diploma Tuition in Belgaum > Afroz Ahmed

Afroz Ahmed Engineering Diploma Tuition trainer in Belgaum

Afroz Ahmed

Tutor

Kanabargi, Belgaum, India - 590016.

1 Student

Book a Demo
Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

Details verified of Afroz Ahmed✕

Identity

Education

Know how UrbanPro verifies Tutor details

Identity is verified based on matching the details uploaded by the Tutor with government databases.

Overview

I pursued my B.E in mechanical stream from Bangalore Institute Of Technology, Bangalore in 2015. For the past one year I have been taking home tuition for physics, maths and diploma engineering. Also, I work as an online tutor teaching Math and Physics to US students for the past 10 months. I am very passionate about teaching. I am very strong in maths n physics of PUC level.

My teaching strength is that I study every minute detail of the topic to be taught or you can say that I do a deep research about everything related to the topic before beginning the class.

Before taking a class, I prepare myself fully and get all the details about the topic to be taught. I myself question myself about the various topics and try to find its answers so that my students get a very clear idea and concept of that particular topic and thus I try to build the concepts of my students to great extent.

I am not any stereo-type tutor who study the topic and then blindly teach them to students without realizing that whether they are understanding it or not. I enjoy studying and thereby enjoy it more while teaching or more precisely sharing my knowledge with the students.

I assure you all that it will be a real fun in my company and surely you will get all your concepts clear by the end of the class.

Languages Spoken

Hindi

English

Education

VTU 2015

Bachelor of Engineering (B.E.)

Address

Kanabargi, Belgaum, India - 590016

Verified Info

Phone Verified

Email Verified

Report this Profile

✕
x

Is this listing inaccurate or duplicate? Any other problem?

Please tell us about the problem and we will fix it.

Please describe the problem that you see in this page.

Type the letters as shown below *

Please enter the letters as show below

Teaches

Engineering Diploma Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Engineering Diploma Branch

Mechanical Engineering Diploma, Automobile Engineering Diploma, Engineering Diploma 1st Year

Engineering Diploma Subject

Engineering Mathematics, Basic Math, Basic Physics, Engineering Mechanics, Computer Fundamentals

Mechanical Engineering Diploma Subject

Theory of Machines & Mechanisms, Strength of Materials, Fluid Mechanics and Machinery, Applied Mathematics, Thermal Engineering, Computer Programming

Automobile Engineering Diploma Subject

Applied Math, Computer Programming, Theory of Machines & Mechanisms, Strength of Materials

Type of class

Crash Course, Regular Classes

Class strength catered to

One on one/ Private Tutions, Group Classes

Taught in School or College

No

Class 11 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE

Subjects taught

Physics, English, Mathematics

Taught in School or College

No

Class 12 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE

Subjects taught

Physics, English, Mathematics

Taught in School or College

No

BTech Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in BTech Tuition

1

BTech Mechanical subjects

Operations Research, Turbomachines, Strength of Materials, Tribology, Automobile Engineering, Mechanics of Machines, Heat & Mass Transfer, Hydraulic and Pneumatic Control, Finite Element Analysis, Kinematics of Machinery, Computer Integrated Manufacturing, Energy Engineering and Management, Thermodynamics, Fluid Mechanics

BTech Branch

BTech 1st Year Engineering, BTech Mechanical Engineering

Type of class

Crash Course

Class strength catered to

One on one/ Private Tutions, Group Classes

Taught in School or College

No

BTech 1st Year subjects

Basic Mechanical Engineering, Computer science, Engineering Mathematics (M1), Engineering Physics, Advanced Mathematics (M2)

BCA Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in BCA Tuition

1

BCA Subject

Mathematics

Type of class

Crash Course

Class strength catered to

One on one/ Private Tutions, Group Classes

Taught in School or College

No

Class 9 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE, ICSE

Subjects taught

Physics, Computer Application, Science, Chemistry, English, Hindi, English Literature, Mathematics

Taught in School or College

No

Class 10 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE, ICSE

Subjects taught

Physics, Science, Mathematics, Computer Application, Chemistry, English Literature, English, Hindi

Taught in School or College

No

Quantitative Aptitude Coaching

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Teaching Experience in detail in Quantitative Aptitude Coaching

I got great interest in aptitude during my college campus placement time where you have to clear aptitude test to get into next round. So I started solving many apti questions and gradually became an expert in it.

Reviews

No Reviews yet!

FAQs

1. Which Engineering Diploma branches do you tutor for?

Mechanical Engineering Diploma, Automobile Engineering Diploma and Engineering Diploma 1st Year

2. Do you have any prior teaching experience?

No

3. Which classes do you teach?

I teach BCA Tuition, BTech Tuition, Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 9 Tuition, Engineering Diploma Tuition and Quantitative Aptitude Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for less than a year.

Book a Demo

Answers by Afroz Ahmed (8)

Answered on 09/12/2017 +1

Solve : 55x + 52y = 217; 52x + 55y = 217

First of all this is a question of simultaneous equations. But it has a trick under its sleeve. The main thing is to identify that little twist in this question. The RHS of both the equations have the same number. So, if we subtract one equation from the other, we can express x in terms of y. Lets... ...more
First of all this is a question of simultaneous equations. But it has a trick under its sleeve. The main thing is to identify that little twist in this question. The RHS of both the equations have the same number. So, if we subtract one equation from the other, we can express x in terms of y. Lets do it... 55x + 52y - 52x - 55y = 217-217 3x - 3y = 0 x = y. Great!! We got x = y. So substituting x in place of y in 1st equation we can get the value of x. Therefore, 55x + 52x = 217 107x = 217 x = 217/107 = 2.028 Also, y = x So y = 2.028 Therefore, the solution is (2.028,2.028)
Answers 8 Comments
Dislike Bookmark

Answered on 06/12/2017 +1

If sin A=1/2, then find the value of cos A.

Use the trigonometric identity sin^2 A + cos^2 A = 1 Express the given in terms of cos A. So, cos A = sqrt(1-sin^2 A) sin A = 1/2 sin^2 A = (1/2)^2 = 1/4 So, cos A = sqrt(1 - 1/4) = sqrt(3/4) = sqrt(3)/ 2 Therefore, cos A = sqrt(3)/2
Answers 43 Comments
Dislike Bookmark

Answered on 06/12/2017 +1

Factorise: (a – b)3 + (b – c)3 + (c – a)3

First factorize (a-b)^3 , (b-c)^3 and (c-a)^3 separately and then add them together to get the final result. (a-b)^3 = a^3 - b^3 - 3a^2b + 3ab^2 ................(1) (b-c)^3 = b^3 - c^3 - 3b^2c + 3bc^2 .................(2) (c-a)^3 = c^3 - a^3 - 3ac^2 + 3 a^2c ... ...more
First factorize (a-b)^3 , (b-c)^3 and (c-a)^3 separately and then add them together to get the final result. (a-b)^3 = a^3 - b^3 - 3a^2b + 3ab^2 ................(1) (b-c)^3 = b^3 - c^3 - 3b^2c + 3bc^2 .................(2) (c-a)^3 = c^3 - a^3 - 3ac^2 + 3 a^2c ..................(3) Now add (1), (2) and (3). This gives, a^3 - b^3 - 3a^2b + 3ab^2 + b^3 - c^3 - 3b^2c + 3bc^2 + c^3 - a^3 - 3ac^2 + 3 a^2c = -3a^2b + 3ab^2 - 3b^2c + 3bc^2 - 3ac^2 + 3 a^2c
Answers 15 Comments
Dislike Bookmark

Answered on 17/11/2017

What is Newton's second law?

Newton's second law of motion states that the force applied on an object is directly proportional to the rate of change of its momentum in the direction of the applied force. Momentum of an object is equal to the product of its mass and velocity. If the mass of the object is constant, then the force... ...more
Newton's second law of motion states that the force applied on an object is directly proportional to the rate of change of its momentum in the direction of the applied force. Momentum of an object is equal to the product of its mass and velocity. If the mass of the object is constant, then the force applied is equal to the acceleration of the object. Acceleration is defined as the rate of change of velocity.
Answers 206 Comments
Dislike Bookmark

Answered on 17/09/2016 +1 Language/Hindi Language/Hindi Speaking

How to learn Hindi in 3 weeks?

1. Learn the grammar part. 2. Try to learn some words in Hindi which we use in our daily life. 3. Now try to frame small sentences in Hindi using the words and the grammar. By this way u will definitely enjoy learning Hindi and 3 weeks will be enough to learn basic Hindi language. If u need my help... ...more
1. Learn the grammar part. 2. Try to learn some words in Hindi which we use in our daily life. 3. Now try to frame small sentences in Hindi using the words and the grammar. By this way u will definitely enjoy learning Hindi and 3 weeks will be enough to learn basic Hindi language. If u need my help I am always there for u..
Answers 67 Comments
Dislike Bookmark

Book a Demo

View All

Teaches

Engineering Diploma Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Engineering Diploma Branch

Mechanical Engineering Diploma, Automobile Engineering Diploma, Engineering Diploma 1st Year

Engineering Diploma Subject

Engineering Mathematics, Basic Math, Basic Physics, Engineering Mechanics, Computer Fundamentals

Mechanical Engineering Diploma Subject

Theory of Machines & Mechanisms, Strength of Materials, Fluid Mechanics and Machinery, Applied Mathematics, Thermal Engineering, Computer Programming

Automobile Engineering Diploma Subject

Applied Math, Computer Programming, Theory of Machines & Mechanisms, Strength of Materials

Type of class

Crash Course, Regular Classes

Class strength catered to

One on one/ Private Tutions, Group Classes

Taught in School or College

No

Class 11 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE

Subjects taught

Physics, English, Mathematics

Taught in School or College

No

Class 12 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE

Subjects taught

Physics, English, Mathematics

Taught in School or College

No

BTech Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in BTech Tuition

1

BTech Mechanical subjects

Operations Research, Turbomachines, Strength of Materials, Tribology, Automobile Engineering, Mechanics of Machines, Heat & Mass Transfer, Hydraulic and Pneumatic Control, Finite Element Analysis, Kinematics of Machinery, Computer Integrated Manufacturing, Energy Engineering and Management, Thermodynamics, Fluid Mechanics

BTech Branch

BTech 1st Year Engineering, BTech Mechanical Engineering

Type of class

Crash Course

Class strength catered to

One on one/ Private Tutions, Group Classes

Taught in School or College

No

BTech 1st Year subjects

Basic Mechanical Engineering, Computer science, Engineering Mathematics (M1), Engineering Physics, Advanced Mathematics (M2)

BCA Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in BCA Tuition

1

BCA Subject

Mathematics

Type of class

Crash Course

Class strength catered to

One on one/ Private Tutions, Group Classes

Taught in School or College

No

Class 9 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE, ICSE

Subjects taught

Physics, Computer Application, Science, Chemistry, English, Hindi, English Literature, Mathematics

Taught in School or College

No

Class 10 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE, ICSE

Subjects taught

Physics, Science, Mathematics, Computer Application, Chemistry, English Literature, English, Hindi

Taught in School or College

No

Quantitative Aptitude Coaching

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Teaching Experience in detail in Quantitative Aptitude Coaching

I got great interest in aptitude during my college campus placement time where you have to clear aptitude test to get into next round. So I started solving many apti questions and gradually became an expert in it.

No Reviews yet!

Answers by Afroz Ahmed (8)

Answered on 09/12/2017 +1

Solve : 55x + 52y = 217; 52x + 55y = 217

First of all this is a question of simultaneous equations. But it has a trick under its sleeve. The main thing is to identify that little twist in this question. The RHS of both the equations have the same number. So, if we subtract one equation from the other, we can express x in terms of y. Lets... ...more
First of all this is a question of simultaneous equations. But it has a trick under its sleeve. The main thing is to identify that little twist in this question. The RHS of both the equations have the same number. So, if we subtract one equation from the other, we can express x in terms of y. Lets do it... 55x + 52y - 52x - 55y = 217-217 3x - 3y = 0 x = y. Great!! We got x = y. So substituting x in place of y in 1st equation we can get the value of x. Therefore, 55x + 52x = 217 107x = 217 x = 217/107 = 2.028 Also, y = x So y = 2.028 Therefore, the solution is (2.028,2.028)
Answers 8 Comments
Dislike Bookmark

Answered on 06/12/2017 +1

If sin A=1/2, then find the value of cos A.

Use the trigonometric identity sin^2 A + cos^2 A = 1 Express the given in terms of cos A. So, cos A = sqrt(1-sin^2 A) sin A = 1/2 sin^2 A = (1/2)^2 = 1/4 So, cos A = sqrt(1 - 1/4) = sqrt(3/4) = sqrt(3)/ 2 Therefore, cos A = sqrt(3)/2
Answers 43 Comments
Dislike Bookmark

Answered on 06/12/2017 +1

Factorise: (a – b)3 + (b – c)3 + (c – a)3

First factorize (a-b)^3 , (b-c)^3 and (c-a)^3 separately and then add them together to get the final result. (a-b)^3 = a^3 - b^3 - 3a^2b + 3ab^2 ................(1) (b-c)^3 = b^3 - c^3 - 3b^2c + 3bc^2 .................(2) (c-a)^3 = c^3 - a^3 - 3ac^2 + 3 a^2c ... ...more
First factorize (a-b)^3 , (b-c)^3 and (c-a)^3 separately and then add them together to get the final result. (a-b)^3 = a^3 - b^3 - 3a^2b + 3ab^2 ................(1) (b-c)^3 = b^3 - c^3 - 3b^2c + 3bc^2 .................(2) (c-a)^3 = c^3 - a^3 - 3ac^2 + 3 a^2c ..................(3) Now add (1), (2) and (3). This gives, a^3 - b^3 - 3a^2b + 3ab^2 + b^3 - c^3 - 3b^2c + 3bc^2 + c^3 - a^3 - 3ac^2 + 3 a^2c = -3a^2b + 3ab^2 - 3b^2c + 3bc^2 - 3ac^2 + 3 a^2c
Answers 15 Comments
Dislike Bookmark

Answered on 17/11/2017

What is Newton's second law?

Newton's second law of motion states that the force applied on an object is directly proportional to the rate of change of its momentum in the direction of the applied force. Momentum of an object is equal to the product of its mass and velocity. If the mass of the object is constant, then the force... ...more
Newton's second law of motion states that the force applied on an object is directly proportional to the rate of change of its momentum in the direction of the applied force. Momentum of an object is equal to the product of its mass and velocity. If the mass of the object is constant, then the force applied is equal to the acceleration of the object. Acceleration is defined as the rate of change of velocity.
Answers 206 Comments
Dislike Bookmark

Answered on 17/09/2016 +1 Language/Hindi Language/Hindi Speaking

How to learn Hindi in 3 weeks?

1. Learn the grammar part. 2. Try to learn some words in Hindi which we use in our daily life. 3. Now try to frame small sentences in Hindi using the words and the grammar. By this way u will definitely enjoy learning Hindi and 3 weeks will be enough to learn basic Hindi language. If u need my help... ...more
1. Learn the grammar part. 2. Try to learn some words in Hindi which we use in our daily life. 3. Now try to frame small sentences in Hindi using the words and the grammar. By this way u will definitely enjoy learning Hindi and 3 weeks will be enough to learn basic Hindi language. If u need my help I am always there for u..
Answers 67 Comments
Dislike Bookmark

Book a Demo

Load More

Afroz Ahmed describes himself as Tutor. He conducts classes in BCA Tuition, BTech Tuition and Class 10 Tuition. Afroz Ahmed is located in Kanabargi, Belgaum. Afroz Ahmed takes Regular Classes- at his Home and Online Classes- via online medium. He has 1 years of teaching experience . Afroz Ahmed has completed Bachelor of Engineering (B.E.) from VTU in 2015. He is well versed in Hindi and English.

X

Share this Profile

Recommended Profiles

Praveen Kumar

Praveen Kumar photo Vihar Road, Mumbai

Umesh Chandra

Umesh Chandra photo Artoni, Agra

Thinq

Thinq photo Attingal, Thiruvananthapuram

Shradha A.

Shradha A. photo Sanganer Kalyanpura, Jaipur

Anita Chande photo

Anita Chande

Anita Chande photo Bopal, Ahmedabad

Arzu

Arzu photo Sector 7, Sonipat

Also have a look at

Learn More

NCERT Solutions for Class 9 CBSE Class 10 Syllabus NCERT Class 10 Solutions NCERT Solutions For Class 11 NCERT Class 12 Solutions CBSE Syllabus for Class 12 NCERT Solutions for Class 9 Maths NCERT Solutions for Class 9 Science Chapter 1 - Matter In Our Surroundings Chapter 2 - Is Matter Around Us Pure?

Reply to 's review

Enter your reply*

1500/1500

Please enter your reply

Your reply should contain a minimum of 10 characters

Your reply has been successfully submitted.

✕

Certified

The Certified badge indicates that the Tutor has received good amount of positive feedback from Students.

✕

Different batches available for this Course

Book a Free Demo

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more

ThinkVidya Learning Pvt Ltd © 2010-2025 All Rights Reserved