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BSc Tuition > BSc Tuition in Mumbai > BSc Tuition in Borivali West > Shreya G.

Shreya G. BSc Tuition trainer in Mumbai

Shreya G.

Biotechnologist

Borivali West, Mumbai, India - 400091.

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Overview

Shreya G. describes herself as Biotechnologist. She conducts classes in BSc Tuition, Class 10 Tuition and Class 6 Tuition. Shreya is located in Borivali West, Mumbai. Shreya takes at students Home. Shreya has completed Master of Science (M.Sc.) from Mumbai University in 2017. She is well versed in English, Marathi and Hindi.

Languages Spoken

English

Marathi

Hindi

Education

Mumbai University 2017

Master of Science (M.Sc.)

Address

Borivali West, Mumbai, India - 400091

Verified Info

Phone Verified

Email Verified

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Teaches

BSc Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

BSc Bio-Chemistry Subjects

Genetics & Genomics, Enzymology, Biomolecules, Biophysics, Proteins and Enzymes, Metabolism of Amino acids & Nucleotides, Cell Biology, Molecular Genetics, Immunology, Recombinant DNA Technology, Metabolism of Carbohydrates & Lipids

Type of class

Regular Classes

Class strength catered to

Group Classes, One on one/ Private Tutions

BSc Micro- Biology Subjects

Medical Microbiology, Introduction to Microbial World, Bacteriology, Genetics & Genomics, Cell Biology, Microbial Ecology, Immunology, Food and Dairy Microbiology, Recombinant DNA Technology and Biotechnology, Molecular Biology, Plant Pathology, Industrial Microbiology

Taught in School or College

No

BSc Branch

BSc Micro- Biology, BSc Bio-Chemistry

MSc Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Subject

Biology, Biotechnology, MicroBiology

Taught in School or College

No

Class 9 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

CBSE, ICSE, State

Subjects taught

Physics, Social Science, Hindi, Chemistry, Science, EVS, Geography, Biology

Taught in School or College

No

Class 10 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

CBSE, ICSE, State

Subjects taught

Social Science, EVS, Geography, Science, Biology, Chemistry, Physics, Hindi

Taught in School or College

No

Class 6 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

CBSE, State, ICSE

Subjects taught

Hindi, EVS, Social science, Science, Chemistry, Biology, Physics, Geography, History

Taught in School or College

No

Class 7 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

CBSE, State, ICSE

Subjects taught

Chemistry, Biology, Social science, History, Geography, Physics, EVS, Science, Hindi

Taught in School or College

No

Class 8 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

CBSE, State, ICSE

Subjects taught

Chemistry, History, Social science, Science, Hindi, Biology, Physics, Geography, EVS

Taught in School or College

No

Class I-V Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

State, ICSE, CBSE

Subjects taught

Hindi, Social Science, Science, Social studies, EVS

Taught in School or College

No

Upcoming Live Classes

Reviews

No Reviews yet!

FAQs

1. Do you have any prior teaching experience?

No

2. Which classes do you teach?

I teach BSc Tuition, Class 10 Tuition, Class 6 Tuition, Class 7 Tuition, Class 8 Tuition, Class 9 Tuition, Class I-V Tuition and MSc Tuition Classes.

3. Do you provide a demo class?

Yes, I provide a free demo class.

4. How many years of experience do you have?

I have been teaching for less than a year.

Book a Demo

Answers by Shreya G. (2)

Answered on 09/12/2017 Learn CBSE - Class 9/Mathematics +1

Solve : 55x + 52y = 217; 52x + 55y = 217

Firstly, from the first equation, find x. From eqn 1: x = 217 - 52y/55. Now, substitute this value of x in the first eqn. i.e. 52 X (217 - 52y)/55 = 217 Now, multiply both sides with the denominator 55. Therefore, the eqn is 52(217-52y) + 3025y=11935 Solve for y. y = 217/107 ... ...more
Firstly, from the first equation, find x. From eqn 1: x = 217 - 52y/55. Now, substitute this value of x in the first eqn. i.e. 52 X (217 - 52y)/55 = 217 Now, multiply both sides with the denominator 55. Therefore, the eqn is 52(217-52y) + 3025y=11935 Solve for y. y = 217/107 Now, substitute this value of y in the x = 217 - 52y/55 which was derived from the original eqn. Therefore x = 217 - 52(217/107) /55 which is x = 217/107. Therefore, x = y = 217/107
Answers 8 Comments
Dislike Bookmark

Answered on 09/12/2017 Learn CBSE - Class 9/Science +1

What is a colloidal solution ?

A colloidal solution is a solution in which a material (which may be either a solid, liquid or a gas), is evenly dispersed throughout the liquid solvent. These differ from true solutions as the solutes in colloidal suspension do not dissolve completely in the solvent, but are found suspended. Based on... ...more
A colloidal solution is a solution in which a material (which may be either a solid, liquid or a gas), is evenly dispersed throughout the liquid solvent. These differ from true solutions as the solutes in colloidal suspension do not dissolve completely in the solvent, but are found suspended. Based on whether the solute is a solid, liquid or a gas, the colloidal solutions are classified as sols, emulsions or foams respectively.
Answers 6 Comments
Dislike Bookmark

Book a Demo

Teaches

BSc Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

BSc Bio-Chemistry Subjects

Genetics & Genomics, Enzymology, Biomolecules, Biophysics, Proteins and Enzymes, Metabolism of Amino acids & Nucleotides, Cell Biology, Molecular Genetics, Immunology, Recombinant DNA Technology, Metabolism of Carbohydrates & Lipids

Type of class

Regular Classes

Class strength catered to

Group Classes, One on one/ Private Tutions

BSc Micro- Biology Subjects

Medical Microbiology, Introduction to Microbial World, Bacteriology, Genetics & Genomics, Cell Biology, Microbial Ecology, Immunology, Food and Dairy Microbiology, Recombinant DNA Technology and Biotechnology, Molecular Biology, Plant Pathology, Industrial Microbiology

Taught in School or College

No

BSc Branch

BSc Micro- Biology, BSc Bio-Chemistry

MSc Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Subject

Biology, Biotechnology, MicroBiology

Taught in School or College

No

Class 9 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

CBSE, ICSE, State

Subjects taught

Physics, Social Science, Hindi, Chemistry, Science, EVS, Geography, Biology

Taught in School or College

No

Class 10 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

CBSE, ICSE, State

Subjects taught

Social Science, EVS, Geography, Science, Biology, Chemistry, Physics, Hindi

Taught in School or College

No

Class 6 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

CBSE, State, ICSE

Subjects taught

Hindi, EVS, Social science, Science, Chemistry, Biology, Physics, Geography, History

Taught in School or College

No

Class 7 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

CBSE, State, ICSE

Subjects taught

Chemistry, Biology, Social science, History, Geography, Physics, EVS, Science, Hindi

Taught in School or College

No

Class 8 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

CBSE, State, ICSE

Subjects taught

Chemistry, History, Social science, Science, Hindi, Biology, Physics, Geography, EVS

Taught in School or College

No

Class I-V Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

State, ICSE, CBSE

Subjects taught

Hindi, Social Science, Science, Social studies, EVS

Taught in School or College

No

Upcoming Live Classes

No Reviews yet!

Answers by Shreya G. (2)

Answered on 09/12/2017 Learn CBSE - Class 9/Mathematics +1

Solve : 55x + 52y = 217; 52x + 55y = 217

Firstly, from the first equation, find x. From eqn 1: x = 217 - 52y/55. Now, substitute this value of x in the first eqn. i.e. 52 X (217 - 52y)/55 = 217 Now, multiply both sides with the denominator 55. Therefore, the eqn is 52(217-52y) + 3025y=11935 Solve for y. y = 217/107 ... ...more
Firstly, from the first equation, find x. From eqn 1: x = 217 - 52y/55. Now, substitute this value of x in the first eqn. i.e. 52 X (217 - 52y)/55 = 217 Now, multiply both sides with the denominator 55. Therefore, the eqn is 52(217-52y) + 3025y=11935 Solve for y. y = 217/107 Now, substitute this value of y in the x = 217 - 52y/55 which was derived from the original eqn. Therefore x = 217 - 52(217/107) /55 which is x = 217/107. Therefore, x = y = 217/107
Answers 8 Comments
Dislike Bookmark

Answered on 09/12/2017 Learn CBSE - Class 9/Science +1

What is a colloidal solution ?

A colloidal solution is a solution in which a material (which may be either a solid, liquid or a gas), is evenly dispersed throughout the liquid solvent. These differ from true solutions as the solutes in colloidal suspension do not dissolve completely in the solvent, but are found suspended. Based on... ...more
A colloidal solution is a solution in which a material (which may be either a solid, liquid or a gas), is evenly dispersed throughout the liquid solvent. These differ from true solutions as the solutes in colloidal suspension do not dissolve completely in the solvent, but are found suspended. Based on whether the solute is a solid, liquid or a gas, the colloidal solutions are classified as sols, emulsions or foams respectively.
Answers 6 Comments
Dislike Bookmark

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Shreya G. describes herself as Biotechnologist. She conducts classes in BSc Tuition, Class 10 Tuition and Class 6 Tuition. Shreya is located in Borivali West, Mumbai. Shreya takes at students Home. Shreya has completed Master of Science (M.Sc.) from Mumbai University in 2017. She is well versed in English, Marathi and Hindi.

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