https://www.urbanpro.com/mumbai/raj-aryan # Raj Aryan

## Trainer

## Overview

## Languages Spoken

## Education

## Address

## Verified Info

## Teaches

## Reviews

## FAQs

## Answers by Raj Aryan (10)

## Teaches

## Answers by Raj Aryan (10)

=>55x+52y=217..........................(i) =>52x+55y=217..........................(ii) Adding equation (i) & (ii), We have 77 (x+y)=434 =>x+y=434/77..................(iii) Subtracting (ii) from (i), We have=>x-y=0-----------------------(iv) From equation (iii) & (iv), we have x=217/77 y=217... Distance=360 KM Let speed be S time (t) =360/s Other Speed=S+5 Time=360/(S+5) As per question, 360/S-360(S+5)=48/60 =>x2+5x -2250 = 0=>(x+50)(x-45)=0 Speed = 45 km/hr as speed cannot be negative Let Consider c=m since a, b, c, d, e are in AP Therefore, b=m-d (Here d is common difference) a=m-2d d=m+d e=m+2d Now, Putting the values of a, b, c, d and e in the final equation, we have =(m-2d)-4(m-d)+6m-4(m+d)+(m+2d) =m-2d-4m+4d+6m-4m-4d+m+2d =0 Mean of the observation = 50 Number of observation =100 Total Value =50*100 =5000 Observation value removed = 50 Observation value added =150 Net observation Value =5000-50+150 =5100 New Mean = 5100/100 = 51

Marol Naka, Mumbai, India - 400059.

Referral Discount: Get ₹ 500 off when you make a payment to start classes. Get started by Booking a Demo.

Details verified of Raj Aryan✕

Identity

Education

Know how UrbanPro verifies Tutor details

Identity is verified based on matching the details uploaded by the Tutor with government databases.

I can teach each and every topics very easily and make it stronger for the students.

Hindi

English

Indian Institute of Management, Indore 2016

Integrated Diploma in Management

Marol Naka, Mumbai, India - 400059

Phone Verified

Email Verified

Facebook Verified

Report this Profile

✕

x

Is this listing inaccurate or duplicate? Any other problem?

Please tell us about the problem and we will fix it.

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

ICSE, CBSE

CBSE Subjects taught

Social Science, Science, Mathematics

ICSE Subjects taught

Chemistry, Mathematics, Physics

Taught in School or College

No

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

ICSE, CBSE

CBSE Subjects taught

Social Science, Science, Mathematics

ICSE Subjects taught

Chemistry, Mathematics, Physics

Taught in School or College

No

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

ICSE, CBSE

CBSE Subjects taught

Social Science, Science, Mathematics

ICSE Subjects taught

Chemistry, Mathematics, Physics

Taught in School or College

No

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

ICSE, CBSE

CBSE Subjects taught

Science, Mathematics

ICSE Subjects taught

Chemistry, Economic Application, Mathematics, Physics

Taught in School or College

No

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

ICSE, CBSE

CBSE Subjects taught

Science, Mathematics

ICSE Subjects taught

Chemistry, Economic Application, Mathematics, Physics

Taught in School or College

No

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

2

Board

CBSE

CBSE Subjects taught

Science, Mathematics

Taught in School or College

No

Microsoft Excel Training classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Microsoft Excel Training classes

2

Teaches following Excel features

Advanced Excel, Basic Excel

Marketing Training classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Marketing Training classes

2

Nursery-KG Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Subject

Mathematics

Taught in School or College

No

No Reviews yet!

1. Which school boards of Class 8 do you teach for?

ICSE, CBSE

2. Have you ever taught in any School or College?

No

3. Which classes do you teach?

I teach Class 10 Tuition, Class 6 Tuition, Class 7 Tuition, Class 8 Tuition, Class 9 Tuition, Class I-V Tuition, Marketing Training, Microsoft Excel Training and Nursery-KG Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for less than a year.

Answered on 10/12/2017 Learn CBSE/Class 10/Mathematics

Let the zeros of given polynomial is m-d, m, and m+d. Here m and d are not zero. substituting the value of zeros in the polynomial, we have=>(m-d)^3-a(m-d)^2+b(m-d)-c=0 =>m^3-d^3-3m^2b+3md^2-a*(m^2+d^2-2*m*d)+b*m-b*d-c=0 =>m^3-d^3-3m^2b+3md^2-a*m^2-ad^2+2*a*m*d+b*m-b*d-c=0----------------(i) Similarily,... ...more

Let the zeros of given polynomial is m-d, m, and m+d. Here m and d are not zero. substituting the value of zeros in the polynomial, we have=>(m-d)^3-a(m-d)^2+b(m-d)-c=0 =>m^3-d^3-3m^2b+3md^2-a*(m^2+d^2-2*m*d)+b*m-b*d-c=0 =>m^3-d^3-3m^2b+3md^2-a*m^2-ad^2+2*a*m*d+b*m-b*d-c=0----------------(i) Similarily, we get a new equation by putting the (m+d), =>m^3+d^3+3m*d^2-a*m^2-a*d*d^2-2a*m*d+b*m+b*d-c=0---------------------(ii) Again, Putting the value of m in polynomial, we have m^3-a*m^2+b*m-c=0-----------------------------------------(iii) Adding equation (i) & (ii), we have=>2*m^3+6*m*d^2-2a*m^2-2a*d^2+2b*m-2*c=0 =>2*(3^3-a*m^2+b*m-c)+6m*d^2-2*a*d^2=0 =>6*m*d^2=2*a*d^2 =>m=a/3------------------------------(iv) Now, Putting the value of m in the polynomial, =>(a/3)^3-a*(a/3)^2+b*a/3-c=0 =>a^3/27-a^3/9+a*b/3-c=0 =>a^3-3*a^3+9*a*b-27*c=0 =>2*a^3-9*a*b+27*c=0 (Proved)

Like 0

Answers 5 Comments Answered on 09/12/2017 Learn CBSE/Class 9/Mathematics

=>55x+52y=217..........................(i) =>52x+55y=217..........................(ii) Adding equation (i) & (ii), We have 77 (x+y)=434 =>x+y=434/77..................(iii) Subtracting (ii) from (i), We have=>x-y=0-----------------------(iv) From equation (iii) & (iv), we have x=217/77 y=217...

Like 0

Answers 8 Comments Answered on 08/12/2017 Learn CBSE/Class 10/Mathematics

Distance=360 KM Let speed be S time (t) =360/s Other Speed=S+5 Time=360/(S+5) As per question, 360/S-360(S+5)=48/60 =>x2+5x -2250 = 0=>(x+50)(x-45)=0 Speed = 45 km/hr as speed cannot be negative

Like 0

Answers 11 Comments Answered on 08/12/2017 Learn CBSE/Class 10/Mathematics

Let Consider c=m since a, b, c, d, e are in AP Therefore, b=m-d (Here d is common difference) a=m-2d d=m+d e=m+2d Now, Putting the values of a, b, c, d and e in the final equation, we have =(m-2d)-4(m-d)+6m-4(m+d)+(m+2d) =m-2d-4m+4d+6m-4m-4d+m+2d =0

Like 0

Answers 11 Comments Answered on 08/12/2017 Learn CBSE/Class 9/Mathematics

Mean of the observation = 50 Number of observation =100 Total Value =50*100 =5000 Observation value removed = 50 Observation value added =150 Net observation Value =5000-50+150 =5100 New Mean = 5100/100 = 51

Like 0

Answers 49 Comments Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

ICSE, CBSE

CBSE Subjects taught

Social Science, Science, Mathematics

ICSE Subjects taught

Chemistry, Mathematics, Physics

Taught in School or College

No

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

ICSE, CBSE

CBSE Subjects taught

Social Science, Science, Mathematics

ICSE Subjects taught

Chemistry, Mathematics, Physics

Taught in School or College

No

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

ICSE, CBSE

CBSE Subjects taught

Social Science, Science, Mathematics

ICSE Subjects taught

Chemistry, Mathematics, Physics

Taught in School or College

No

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

ICSE, CBSE

CBSE Subjects taught

Science, Mathematics

ICSE Subjects taught

Chemistry, Economic Application, Mathematics, Physics

Taught in School or College

No

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

ICSE, CBSE

CBSE Subjects taught

Science, Mathematics

ICSE Subjects taught

Chemistry, Economic Application, Mathematics, Physics

Taught in School or College

No

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

2

Board

CBSE

CBSE Subjects taught

Science, Mathematics

Taught in School or College

No

Microsoft Excel Training classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Microsoft Excel Training classes

2

Teaches following Excel features

Advanced Excel, Basic Excel

Marketing Training classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Marketing Training classes

2

Nursery-KG Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Subject

Mathematics

Taught in School or College

No

No Reviews yet!

Answered on 10/12/2017 Learn CBSE/Class 10/Mathematics

Let the zeros of given polynomial is m-d, m, and m+d. Here m and d are not zero. substituting the value of zeros in the polynomial, we have=>(m-d)^3-a(m-d)^2+b(m-d)-c=0 =>m^3-d^3-3m^2b+3md^2-a*(m^2+d^2-2*m*d)+b*m-b*d-c=0 =>m^3-d^3-3m^2b+3md^2-a*m^2-ad^2+2*a*m*d+b*m-b*d-c=0----------------(i) Similarily,... ...more

Let the zeros of given polynomial is m-d, m, and m+d. Here m and d are not zero. substituting the value of zeros in the polynomial, we have=>(m-d)^3-a(m-d)^2+b(m-d)-c=0 =>m^3-d^3-3m^2b+3md^2-a*(m^2+d^2-2*m*d)+b*m-b*d-c=0 =>m^3-d^3-3m^2b+3md^2-a*m^2-ad^2+2*a*m*d+b*m-b*d-c=0----------------(i) Similarily, we get a new equation by putting the (m+d), =>m^3+d^3+3m*d^2-a*m^2-a*d*d^2-2a*m*d+b*m+b*d-c=0---------------------(ii) Again, Putting the value of m in polynomial, we have m^3-a*m^2+b*m-c=0-----------------------------------------(iii) Adding equation (i) & (ii), we have=>2*m^3+6*m*d^2-2a*m^2-2a*d^2+2b*m-2*c=0 =>2*(3^3-a*m^2+b*m-c)+6m*d^2-2*a*d^2=0 =>6*m*d^2=2*a*d^2 =>m=a/3------------------------------(iv) Now, Putting the value of m in the polynomial, =>(a/3)^3-a*(a/3)^2+b*a/3-c=0 =>a^3/27-a^3/9+a*b/3-c=0 =>a^3-3*a^3+9*a*b-27*c=0 =>2*a^3-9*a*b+27*c=0 (Proved)

Like 0

Answers 5 Comments Answered on 09/12/2017 Learn CBSE/Class 9/Mathematics

Like 0

Answers 8 Comments Answered on 08/12/2017 Learn CBSE/Class 10/Mathematics

Like 0

Answers 11 Comments Answered on 08/12/2017 Learn CBSE/Class 10/Mathematics

Like 0

Answers 11 Comments Answered on 08/12/2017 Learn CBSE/Class 9/Mathematics

Like 0

Answers 49 Comments Load More

Share this Profile

Also have a look at

- Class 6 Tuition
- Class 7 Tuition
- Class 8 Tuition
- Class 9 Tuition
- Class 10 Tuition
- Class I-V Tuition
- Microsoft Excel Training classes
- Marketing Training classes
- Nursery-KG Tuition
- Chemistry Tuition classes
- Science Tuition classes
- Math Tutors
- Physics Tutors
- Chemistry Tutors
- Home Tutors
- Mathematics Tuition
- CBSE Tuition classes
- Private Tutors
- Tuition Tutor
- Home Tuition
- Private Tuitions
- Online Tutors
- ICSE Tuition classes
- Advanced Excel Training
- MS Excel Course
- Home Tutor for Class 9
- Home Tutor for Class 10

Reply to 's review

Enter your reply*

Your reply has been successfully submitted.

✕

Certified

The Certified badge indicates that the Tutor has received good amount of positive feedback from Students.