If a right circular cone has radius 4 cm and slant height 5 cm then what is its volume?

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Ashish Jain

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apply pythagoras theorem (height of cone)^2 + 4^2=5^2 height of cone = 3 volume of cone = 1/3*22/7*r^2*height of cone volume of cone = 50.27 cm^3
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Given radius=4, slant height=5 of a right circular cone By Pythagoras theorem h=√=√(25-16)=√9=3 Volume of right circular cone is 1/3×π×r×r×h =1/3×π×4×4×3=16π
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Radius and slant height of cone are given ,now first we will find height of cone with the help of pythagores theorem. P2+b2=h2 P2+(4)2=(5)2 P2+16=25 P2=25-16 P2=9 P=sqr root of 9 P=3 Volume of cone =1/3*pi*r2*h Volume =1/3*22/7*16*3 On solving this Volume of cone =16*pi
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Given radius=4, slant height=5 By Pythagoras theorem height=3cm Now volume of the cube = 1/3×π×r×r×h=1/3×22/7×4×4×3=16π or 352/7=50.28 cubic cm
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Humble Mathematician

Volume of cone=V= 1/3 pi*r^2*h, but h can be found using Pythagoras theorem, 5^2=4^2+h^2, h=9^(1/2)=3, V= 1/3*pi*16*3=16pi.
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Maths Magic

h2=l2-r2 =25-16 =9 h=3 vol=1/3 pi r2h =1/3*22/7*4*4*3 =352/7 =50.28.
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