Annu

Chicalim, Mormugao, India - 403711

# Annu

## Maths Tutor

Chicalim, Mormugao, India - 403711.

3.8

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## Overview

1 YEAR of teaching experience in Jaipur as a maths teacher and one year of experience in mumbai

English

Hindi

## Education

Banasthali University 2015

Master of Science (M.Sc.)

Chicalim, Mormugao, India - 403711

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## Demo Class

No

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## Class 6 Tuition Overview

Class 6 Tuition

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 6 Tuition

2

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

Yes

## Reviews

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Radius and slant height of cone are given ,now first we will find height of cone with the help of pythagores theorem. P2+b2=h2 P2+(4)2=(5)2 P2+16=25 P2=25-16 P2=9 P=sqr root of 9 P=3 Volume of cone =1/3*pi*r2*h Volume =1/3*22/7*16*3 On solving this Volume of cone =16*pi
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It will b 0 Since sin45=1/sqr root of 2 And cos45=1/sqr root of 2 Having the same value and if we perform operation Sin45-cos45 it will result into 0.
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Let p(x)= x2+5x+6 Now putting p (x)=0 X2+5x+6=0 X2+3x+2x+6=0 X (x+3)+2 (x+3)=0 (X+3)(x+2)=0 (X+3)=0,(x+2)=0 X=-3,x=-2 Therefor -3 and -2 are zeros of given polynomial p (x)and names alpha and beta Now we have to verify the cofficients of given polynomial Comapre p (x)=ax2+bx+c ;a=1,b=5,c=6 Now alpha... ...more
Let p(x)= x2+5x+6 Now putting p (x)=0 X2+5x+6=0 X2+3x+2x+6=0 X (x+3)+2 (x+3)=0 (X+3)(x+2)=0 (X+3)=0,(x+2)=0 X=-3,x=-2 Therefor -3 and -2 are zeros of given polynomial p (x)and names alpha and beta Now we have to verify the cofficients of given polynomial Comapre p (x)=ax2+bx+c ;a=1,b=5,c=6 Now alpha +beta= -b/a Alpha*beta=c/a For the verification of cofficients take both the scenario L.H.S alpha+beta and R.H.S -b/a -3 + - 2 -5/1 -5 -5 Hence L.H.S=R.H.S Now Again check for L.H.S alpha*beta R.H.S c/a -3 * -2 6/1 6 6 Hence L.H.S = R.H.S So the relationship between zeros and cofficients of given polynomial is verified.
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AnnuDirections

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Class 6 Tuition 3.8

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 6 Tuition

2

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

Yes

Class 7 Tuition 3.8

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 7 Tuition

2

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

Yes

Class 8 Tuition 3.8

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 8 Tuition

2

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

Yes

Class 9 Tuition 3.8

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 9 Tuition

2

Board

CBSE

CBSE Subjects taught

Science, Mathematics

Taught in School or College

Yes

Class 10 Tuition 3.8

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 10 Tuition

2

Board

CBSE

CBSE Subjects taught

Science, Mathematics

Taught in School or College

Yes

Computer Course classes 3.3

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

BCA Tuition 3.3

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

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No Reviews yet! Be the first one to Review

Radius and slant height of cone are given ,now first we will find height of cone with the help of pythagores theorem. P2+b2=h2 P2+(4)2=(5)2 P2+16=25 P2=25-16 P2=9 P=sqr root of 9 P=3 Volume of cone =1/3*pi*r2*h Volume =1/3*22/7*16*3 On solving this Volume of cone =16*pi
Dislike Bookmark

It will b 0 Since sin45=1/sqr root of 2 And cos45=1/sqr root of 2 Having the same value and if we perform operation Sin45-cos45 it will result into 0.
Dislike Bookmark

Let p(x)= x2+5x+6 Now putting p (x)=0 X2+5x+6=0 X2+3x+2x+6=0 X (x+3)+2 (x+3)=0 (X+3)(x+2)=0 (X+3)=0,(x+2)=0 X=-3,x=-2 Therefor -3 and -2 are zeros of given polynomial p (x)and names alpha and beta Now we have to verify the cofficients of given polynomial Comapre p (x)=ax2+bx+c ;a=1,b=5,c=6 Now alpha... ...more
Let p(x)= x2+5x+6 Now putting p (x)=0 X2+5x+6=0 X2+3x+2x+6=0 X (x+3)+2 (x+3)=0 (X+3)(x+2)=0 (X+3)=0,(x+2)=0 X=-3,x=-2 Therefor -3 and -2 are zeros of given polynomial p (x)and names alpha and beta Now we have to verify the cofficients of given polynomial Comapre p (x)=ax2+bx+c ;a=1,b=5,c=6 Now alpha +beta= -b/a Alpha*beta=c/a For the verification of cofficients take both the scenario L.H.S alpha+beta and R.H.S -b/a -3 + - 2 -5/1 -5 -5 Hence L.H.S=R.H.S Now Again check for L.H.S alpha*beta R.H.S c/a -3 * -2 6/1 6 6 Hence L.H.S = R.H.S So the relationship between zeros and cofficients of given polynomial is verified.
Dislike Bookmark

Annu describes herself as Maths Tutor. She conducts classes in BCA Tuition, Class 10 Tuition and Class 6 Tuition. Annu is located in Chicalim, Mormugao. Annu takes Regular Classes- at her Home. She has 2 years of teaching experience . Annu has completed Master of Science (M.Sc.) from Banasthali University in 2015. She is well versed in English and Hindi.

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