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Annu Class 6 Tuition trainer in Mormugao

Annu

locationImg Chicalim, Mormugao
2 yrs of Exp
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Maths Tutor

Student's home
Tutor's home
1 YEAR of teaching experience in Jaipur as a maths teacher and one year of experience in mumbai

Languages Spoken

English

Hindi

Education

Banasthali University 2015

Master of Science (M.Sc.)

Address

Chicalim, Mormugao, India - 403711

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Teaches

Class 6 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

2

Board

CBSE

Subjects taught

Science, Mathematics

Taught in School or College

Yes

Class 7 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

2

Board

CBSE

Subjects taught

Science, Mathematics

Taught in School or College

Yes

Class 8 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

2

Board

CBSE

Subjects taught

Mathematics, Science

Taught in School or College

Yes

Class 9 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

2

Board

CBSE

Subjects taught

Science, Mathematics

Taught in School or College

Yes

Class 10 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

2

Board

CBSE

Subjects taught

Science, Mathematics

Taught in School or College

Yes

Computer Classes

Class Location

Online class via Zoom

Student's Home

Tutor's Home

BCA Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Reviews

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Answers by Annu

Answered on 27/12/2017 Learn CBSE - Class 9/Mathematics +1

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Radius and slant height of cone are given ,now first we will find height of cone with the help of pythagores theorem. P2+b2=h2 P2+(4)2=(5)2 P2+16=25 P2=25-16 P2=9 P=sqr root of 9 P=3 Volume of cone =1/3*pi*r2*h Volume =1/3*22/7*16*3 On solving this Volume of cone =16*pi
Answers 6 Comments
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Answered on 21/12/2017 Learn CBSE - Class 10/Mathematics +1

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It will b 0 Since sin45=1/sqr root of 2 And cos45=1/sqr root of 2 Having the same value and if we perform operation Sin45-cos45 it will result into 0.
Answers 6 Comments
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Answered on 21/12/2017 Learn CBSE - Class 10/Mathematics +1

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Let p(x)= x2+5x+6 Now putting p (x)=0 X2+5x+6=0 X2+3x+2x+6=0 X (x+3)+2 (x+3)=0 (X+3)(x+2)=0 (X+3)=0,(x+2)=0 X=-3,x=-2 Therefor -3 and -2 are zeros of given polynomial p (x)and names alpha and beta Now we have to verify the cofficients of given polynomial Comapre p (x)=ax2+bx+c ;a=1,b=5,c=6 Now alpha... ...more
Let p(x)= x2+5x+6 Now putting p (x)=0 X2+5x+6=0 X2+3x+2x+6=0 X (x+3)+2 (x+3)=0 (X+3)(x+2)=0 (X+3)=0,(x+2)=0 X=-3,x=-2 Therefor -3 and -2 are zeros of given polynomial p (x)and names alpha and beta Now we have to verify the cofficients of given polynomial Comapre p (x)=ax2+bx+c ;a=1,b=5,c=6 Now alpha +beta= -b/a Alpha*beta=c/a For the verification of cofficients take both the scenario L.H.S alpha+beta and R.H.S -b/a -3 + - 2 -5/1 -5 -5 Hence L.H.S=R.H.S Now Again check for L.H.S alpha*beta R.H.S c/a -3 * -2 6/1 6 6 Hence L.H.S = R.H.S So the relationship between zeros and cofficients of given polynomial is verified.
Answers 5 Comments
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Teaches

Class 6 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

2

Board

CBSE

Subjects taught

Science, Mathematics

Taught in School or College

Yes

Class 7 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

2

Board

CBSE

Subjects taught

Science, Mathematics

Taught in School or College

Yes

Class 8 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

2

Board

CBSE

Subjects taught

Mathematics, Science

Taught in School or College

Yes

Class 9 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

2

Board

CBSE

Subjects taught

Science, Mathematics

Taught in School or College

Yes

Class 10 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

2

Board

CBSE

Subjects taught

Science, Mathematics

Taught in School or College

Yes

Computer Classes

Class Location

Online class via Zoom

Student's Home

Tutor's Home

BCA Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

No Reviews yet!

Answers by Annu

Answered on 27/12/2017 Learn CBSE - Class 9/Mathematics +1

Ask a Question

Post a Lesson

Radius and slant height of cone are given ,now first we will find height of cone with the help of pythagores theorem. P2+b2=h2 P2+(4)2=(5)2 P2+16=25 P2=25-16 P2=9 P=sqr root of 9 P=3 Volume of cone =1/3*pi*r2*h Volume =1/3*22/7*16*3 On solving this Volume of cone =16*pi
Answers 6 Comments
Dislike Bookmark

Answered on 21/12/2017 Learn CBSE - Class 10/Mathematics +1

Ask a Question

Post a Lesson

It will b 0 Since sin45=1/sqr root of 2 And cos45=1/sqr root of 2 Having the same value and if we perform operation Sin45-cos45 it will result into 0.
Answers 6 Comments
Dislike Bookmark

Answered on 21/12/2017 Learn CBSE - Class 10/Mathematics +1

Ask a Question

Post a Lesson

Let p(x)= x2+5x+6 Now putting p (x)=0 X2+5x+6=0 X2+3x+2x+6=0 X (x+3)+2 (x+3)=0 (X+3)(x+2)=0 (X+3)=0,(x+2)=0 X=-3,x=-2 Therefor -3 and -2 are zeros of given polynomial p (x)and names alpha and beta Now we have to verify the cofficients of given polynomial Comapre p (x)=ax2+bx+c ;a=1,b=5,c=6 Now alpha... ...more
Let p(x)= x2+5x+6 Now putting p (x)=0 X2+5x+6=0 X2+3x+2x+6=0 X (x+3)+2 (x+3)=0 (X+3)(x+2)=0 (X+3)=0,(x+2)=0 X=-3,x=-2 Therefor -3 and -2 are zeros of given polynomial p (x)and names alpha and beta Now we have to verify the cofficients of given polynomial Comapre p (x)=ax2+bx+c ;a=1,b=5,c=6 Now alpha +beta= -b/a Alpha*beta=c/a For the verification of cofficients take both the scenario L.H.S alpha+beta and R.H.S -b/a -3 + - 2 -5/1 -5 -5 Hence L.H.S=R.H.S Now Again check for L.H.S alpha*beta R.H.S c/a -3 * -2 6/1 6 6 Hence L.H.S = R.H.S So the relationship between zeros and cofficients of given polynomial is verified.
Answers 5 Comments
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