Annu

Chicalim, Mormugao, India - 403711

Annu photo

Annu

Maths Tutor

Chicalim, Mormugao, India - 403711.

3.8

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Overview

1 YEAR of teaching experience in Jaipur as a maths teacher and one year of experience in mumbai

Languages Spoken

English

Hindi

Education

Banasthali University 2015

Master of Science (M.Sc.)

Address

Chicalim, Mormugao, India - 403711

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No

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Class 6 Tuition Overview

Class 6 Tuition

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 6 Tuition

2

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

Yes

Reviews

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Answers by Annu (3)

Answered on 27/12/2017 CBSE/Class 9/Mathematics Tuition/Class IX-X Tuition

Radius and slant height of cone are given ,now first we will find height of cone with the help of pythagores theorem. P2+b2=h2 P2+(4)2=(5)2 P2+16=25 P2=25-16 P2=9 P=sqr root of 9 P=3 Volume of cone =1/3*pi*r2*h Volume =1/3*22/7*16*3 On solving this Volume of cone =16*pi
Answers 6 Comments
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Answered on 21/12/2017 CBSE/Class 10/Mathematics Tuition/Class IX-X Tuition

It will b 0 Since sin45=1/sqr root of 2 And cos45=1/sqr root of 2 Having the same value and if we perform operation Sin45-cos45 it will result into 0.
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Answered on 21/12/2017 CBSE/Class 10/Mathematics Tuition/Class IX-X Tuition

Let p(x)= x2+5x+6 Now putting p (x)=0 X2+5x+6=0 X2+3x+2x+6=0 X (x+3)+2 (x+3)=0 (X+3)(x+2)=0 (X+3)=0,(x+2)=0 X=-3,x=-2 Therefor -3 and -2 are zeros of given polynomial p (x)and names alpha and beta Now we have to verify the cofficients of given polynomial Comapre p (x)=ax2+bx+c ;a=1,b=5,c=6 Now alpha... ...more
Let p(x)= x2+5x+6 Now putting p (x)=0 X2+5x+6=0 X2+3x+2x+6=0 X (x+3)+2 (x+3)=0 (X+3)(x+2)=0 (X+3)=0,(x+2)=0 X=-3,x=-2 Therefor -3 and -2 are zeros of given polynomial p (x)and names alpha and beta Now we have to verify the cofficients of given polynomial Comapre p (x)=ax2+bx+c ;a=1,b=5,c=6 Now alpha +beta= -b/a Alpha*beta=c/a For the verification of cofficients take both the scenario L.H.S alpha+beta and R.H.S -b/a -3 + - 2 -5/1 -5 -5 Hence L.H.S=R.H.S Now Again check for L.H.S alpha*beta R.H.S c/a -3 * -2 6/1 6 6 Hence L.H.S = R.H.S So the relationship between zeros and cofficients of given polynomial is verified.
Answers 5 Comments
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AnnuDirections

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Class 6 Tuition 3.8

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 6 Tuition

2

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

Yes

Class 7 Tuition 3.8

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 7 Tuition

2

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

Yes

Class 8 Tuition 3.8

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 8 Tuition

2

Board

CBSE

CBSE Subjects taught

Mathematics, Science

Taught in School or College

Yes

Class 9 Tuition 3.8

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 9 Tuition

2

Board

CBSE

CBSE Subjects taught

Science, Mathematics

Taught in School or College

Yes

Class 10 Tuition 3.8

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 10 Tuition

2

Board

CBSE

CBSE Subjects taught

Science, Mathematics

Taught in School or College

Yes

Computer Course classes 3.3

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

BCA Tuition 3.3

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

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No Reviews yet! Be the first one to Review

Answers by Annu (3)

Answered on 27/12/2017 CBSE/Class 9/Mathematics Tuition/Class IX-X Tuition

Radius and slant height of cone are given ,now first we will find height of cone with the help of pythagores theorem. P2+b2=h2 P2+(4)2=(5)2 P2+16=25 P2=25-16 P2=9 P=sqr root of 9 P=3 Volume of cone =1/3*pi*r2*h Volume =1/3*22/7*16*3 On solving this Volume of cone =16*pi
Answers 6 Comments
Dislike Bookmark

Answered on 21/12/2017 CBSE/Class 10/Mathematics Tuition/Class IX-X Tuition

It will b 0 Since sin45=1/sqr root of 2 And cos45=1/sqr root of 2 Having the same value and if we perform operation Sin45-cos45 it will result into 0.
Answers 6 Comments
Dislike Bookmark

Answered on 21/12/2017 CBSE/Class 10/Mathematics Tuition/Class IX-X Tuition

Let p(x)= x2+5x+6 Now putting p (x)=0 X2+5x+6=0 X2+3x+2x+6=0 X (x+3)+2 (x+3)=0 (X+3)(x+2)=0 (X+3)=0,(x+2)=0 X=-3,x=-2 Therefor -3 and -2 are zeros of given polynomial p (x)and names alpha and beta Now we have to verify the cofficients of given polynomial Comapre p (x)=ax2+bx+c ;a=1,b=5,c=6 Now alpha... ...more
Let p(x)= x2+5x+6 Now putting p (x)=0 X2+5x+6=0 X2+3x+2x+6=0 X (x+3)+2 (x+3)=0 (X+3)(x+2)=0 (X+3)=0,(x+2)=0 X=-3,x=-2 Therefor -3 and -2 are zeros of given polynomial p (x)and names alpha and beta Now we have to verify the cofficients of given polynomial Comapre p (x)=ax2+bx+c ;a=1,b=5,c=6 Now alpha +beta= -b/a Alpha*beta=c/a For the verification of cofficients take both the scenario L.H.S alpha+beta and R.H.S -b/a -3 + - 2 -5/1 -5 -5 Hence L.H.S=R.H.S Now Again check for L.H.S alpha*beta R.H.S c/a -3 * -2 6/1 6 6 Hence L.H.S = R.H.S So the relationship between zeros and cofficients of given polynomial is verified.
Answers 5 Comments
Dislike Bookmark

Annu describes herself as Maths Tutor. She conducts classes in BCA Tuition, Class 10 Tuition and Class 6 Tuition. Annu is located in Chicalim, Mormugao. Annu takes Regular Classes- at her Home. She has 2 years of teaching experience . Annu has completed Master of Science (M.Sc.) from Banasthali University in 2015. She is well versed in English and Hindi.

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