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Given that HCF (161,345) = 23, find their LCM.

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N¹ *N² = LCM * HCF 161 *345 =23 * N² N² =2415

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We know that lcm x hcf = product of the numbers Therefore, lcm=161*345/23=161*15=2415

N1*N2=lcm*hcf (161*345)/23=2415 Lcm=2415

HCF*LCM = product of 2 numbers.So here 161*345 = 23*LCM, on solving we get LCM = 2415

hcf * lcm = a * b. hence lcm = (161 * 345)/23=2415.

LCM is 10.

Maths Expert

HCF*LCM= No. 1 *No. 2 Let the LCM be x 23*x = 161*345. On solving we get x= 2415


LCM = (161*345)/23 = 2415.



By using the formula HCF * LCM = Product of two numbers. Let the LCM be x 23 * x = 161 * 345 x = 161 * 345 / 23 = 2415 LCM of 161 and 345 is 2415

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