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Class 9 Tuition > > Given that HCF (161,345) = 23, find their LCM.
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Given that HCF (161,345) = 23, find their LCM.

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CSAT Tutor, BPSC DI Tutor (Ex. Drishti IAS Senior Content Writer)

N¹ *N² = LCM * HCF 161 *345 =23 * N² N² =2415
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Maths Tutor

We know that lcm x hcf = product of the numbers Therefore, lcm=161*345/23=161*15=2415
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N1*N2=lcm*hcf (161*345)/23=2415 Lcm=2415
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Anyone can learn the subject in easiest way, if they have good tutor to guide.

HCF*LCM = product of 2 numbers.So here 161*345 = 23*LCM, on solving we get LCM = 2415
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LCM is 10.
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Maths Expert

HCF*LCM= No. 1 *No. 2 Let the LCM be x 23*x = 161*345. On solving we get x= 2415
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Tutor

LCM = (161*345)/23 = 2415.
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COMPUTER SOLUTION

161*345/23
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By using the formula HCF * LCM = Product of two numbers. Let the LCM be x 23 * x = 161 * 345 x = 161 * 345 / 23 = 2415 LCM of 161 and 345 is 2415
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Formula to Note: 1) Product of two numbers = Product of their H.C.F. and L.C.M Solution: ⇒ Given that two numbers ,let a=161 and b=345; ⇒ HCF(161,345) = 23 ⇒ By applying the above formula,we get following expression ⇒ a * b = HCF*LCM ⇒ 161*345 = 23 * LCM(161,345) ⇒ 55545...
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Formula to Note: 1) Product of two numbers = Product of their H.C.F. and L.C.M Solution: ⇒Given that two numbers ,let a=161 and b=345; ⇒ HCF(161,345) = 23 ⇒ By applying the above formula,we get following expression ⇒ a * b = HCF*LCM ⇒ 161*345 = 23 * LCM(161,345) ⇒ 55545 = 23 * LCM(161,345) ⇒ Rewriting the above the expression ⇒ 23 * LCM(161,345) = 55545 ⇒ LCM(161,345) = 55545/23 ⇒ LCM(161,345) = 2415 ⇒ There for LCM of 161, 345 is 2415. read less
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