Find the area of a right-angled triangle whose base is 12 cm and height is 5 cm.

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Eco, Maths and Stats Tutor

Area of a triangle is 1/2 * base * altitude = 1/2 * 12 * 5 = 30 cm^2
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30 cm^2
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Tutor

use formula 1/2 base*height
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A Professional Chartered Accountant

30
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30cm^2
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Trainer

1/2 * base * height = 1/2 *12*5 = 30 cm^2
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Tutor

Area of a right angled triangle is half of the product of base and height..so 1/2*12*5= 30 sq cm
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Mathematician

1/2* Base * height = 30 cm2
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Highly Qualified Tutor

Given: base = 12 cm and height = 5 cm To find: Area of triangle Solution: We know that, Area of a triangle= 1/2 × base × height So, Area of triangle = 1/2 × 12 × 5 = 30 sq.cm So, Area of triangle = 30 sq.cm
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Teacher

Area = half the base x altitude = 1/2 x 12 x 5 = 30 cm^2
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Related Questions

The angles of a triangle are arranged in ascending order of magnitude. If the difference between two consecutive angles is 10°, find all the three angles.
Let the any one of the angle of triangle be x then other two angle are x+10, x+20 According to Question, x + (x+10) + (x+20)=180 3x + 30 = 180 3x = 150 x = 50 Thus, angles would be 50, 60, and 70.
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Sradha
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Can a triangle have two obtuse angles? Give reason for your answer.
No, because the sum of three angles of a triangle is 180 degree & sum of any two obtuse angles is always more than 180 degree. So, it can not be possible that a triangle have two obtuse angles.
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Tanush
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What is Euclid’s second axiom?
Euclid second axiom states that any terminated straight line can be projected indefinitely.
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Sagar
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Given that HCF (161,345) = 23, find their LCM.
N¹ *N² = LCM * HCF 161 *345 =23 * N² N² =2415
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