Show that x = 2 and y = 1 satisfy the linear equation 2x 3y = 7.

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Salman Ahmad Siddiqui

CSAT Tutor, BPSC DI Tutor (Ex. Drishti IAS Senior Content Writer)

2x + 3y=7 Put 2 in place of x and 1 in place of y. 2*2+ 3*1=4+3=7
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Given, 2x+3y=7. Put the value of x and y in the above equation. 2(2) + 3(1) = 7 4+3=7 7=7
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Yes, it satisfy the equation 2x+3y = 7 putting x=2, y= 1, 2(2) + 3(1) = 4 + 3 = 7
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The equation gets satisfied when we put x=2 and y=1 in 2x + 3y = 7,2(2) + 3(1) = 7.
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According to question there is no + sign between 2x 3y. If we assume presences of + sign then it satisfy. Otherwise not.
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Home Tutor

2x + 3y=7. Therefore, put 2 in place of x and 1 in place of y. then the linear equation will be satisfied, 2*2+ 3*1=4+3=7.
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Spoken English trainer and french trainer with 4 years of experience.

the equation gets satisfied if u put X=2 and Y=1 for the given equation 2x+3y=7. so 2(2)+3(1)=7 4+3=7 LHS=RHS HENCE SATISFIED
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Teacher

On the LHS, if we put the value of x as 2 and y as 1; we will get the equation as 2(2) + 3(1), which after solving comes to 4 + 3, which is equal to RHS i.e. 7. Hence the value of x = 2 and y = 1 satisfy the given equation.
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Maths Expert

Given, 2x+3y=7. Put the value of x and y in the above equation. 2(2) + 3(1) = 7 4+3=7 7=7
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Math Magacian

Whenever we have to check whether the given points are roots of the given linear equation, we have to put their values in their respective variables and if the given values satisfy the equation, they are the roots. Satisfy means ur must get LHS =RHS after putting values.
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