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Om Prakash conducts classes in Class 10 Tuition, Class 6 Tuition and Class 7 Tuition. Om is located in Mukherjee Nagar, Delhi. Om takes at students Home and Regular Classes- at his Home. He has 2 years of teaching experience . Om has completed Bachelor of Technology (B.Tech.) from Uptu. He is well versed in Hindi and English.

No

Hindi, English

Bachelor of Technology (B.Tech.) from Uptu .

Mukherjee Nagar, Delhi, India - 110009

Class 6 Tuition

Board

CBSE, ICSE, State

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Physics, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class Location

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

2

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"Given that HCF (161,345) = 23, find their LCM." in CBSE/Class 9/Mathematics, Tuition/Class IX-X Tuition

N1*N2=lcm*hcf

(161*345)/23=2415

Lcm=2415

1

| 0

"

What is the value of Sin360+Cos360?

" in CBSE/Class 9/Mathematics

0+1=1

0

| 0

"

The radius of a hemisphere is r. What is its volume?

" in CBSE/Class 9/Mathematics

2/3(πr^3)

0

| 0

"The mean of 100 observations is 50. If one of the observation which was 50 is replaced by 150 then what will be the resulting mean?" in CBSE/Class 9/Mathematics, Tuition/Class IX-X Tuition

Observed value diff =100

Mean of observed diff=100/100(no of observation)=1

So new mean =51

0

| 0

"The mean of 100 observations is 50. If one of the observation which was 50 is replaced by 150 then what will be the resulting mean?" in CBSE/Class 9/Mathematics, Tuition/Class IX-X Tuition

T. value=100*50=5000

Observation increased =150-50=100

New value= 5000+100=5100

New mean=5100/100=51

Alternate method

Increase in observed value =150-50=100

Mean of new observed= 100/100=1

So new mean = 50+1=51

0

| 0

Om Prakash

x Class 6 Tuition

Board

CBSE, ICSE, State

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Physics, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class Location

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

2

Class 7 Tuition

Board

CBSE, ICSE, State

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Physics, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class Location

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

2

Class 8 Tuition

Board

CBSE, ICSE, State

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Physics, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class Location

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

2

Class 9 Tuition

Board

CBSE, State, ICSE

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Physics, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class Location

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

2

Class 10 Tuition

Board

CBSE, State, ICSE

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Physics, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class Location

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

2

this is test message this is test message this is test message this is test message this is test message this is test message this is test message

No Reviews yet! Be the first one to Review

"Given that HCF (161,345) = 23, find their LCM." in CBSE/Class 9/Mathematics, Tuition/Class IX-X Tuition

N1*N2=lcm*hcf

(161*345)/23=2415

Lcm=2415

1

| 0

"

What is the value of Sin360+Cos360?

" in CBSE/Class 9/Mathematics

0+1=1

0

| 0

"

The radius of a hemisphere is r. What is its volume?

" in CBSE/Class 9/Mathematics

2/3(πr^3)

0

| 0

"The mean of 100 observations is 50. If one of the observation which was 50 is replaced by 150 then what will be the resulting mean?" in CBSE/Class 9/Mathematics, Tuition/Class IX-X Tuition

Observed value diff =100

Mean of observed diff=100/100(no of observation)=1

So new mean =51

0

| 0

T. value=100*50=5000

Observation increased =150-50=100

New value= 5000+100=5100

New mean=5100/100=51

Alternate method

Increase in observed value =150-50=100

Mean of new observed= 100/100=1

So new mean = 50+1=51

0

| 0

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