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# Find the product: (x – 3y) (x + 3y) (x2 + 9y2)

Teacher

The product of the first two terms is x^2 - 9y^2. The third term is x^2 + 9y^2 So the final product is x^4 - 81y^4

Tutor

x4-81y4

Mathematician

x^4-9y^4

Mathematician

x^4-81y^4

Trainer

(x-3y)(x+3y)(x2+9y2) =(x2-9y2)(x2+9y2) =(x4-81y4) (ans) Thank you.

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