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Find the product: (x – 3y) (x + 3y) (x2 + 9y2)

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Teacher

The product of the first two terms is x^2 - 9y^2. The third term is x^2 + 9y^2 So the final product is x^4 - 81y^4
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Tutor

x4-81y4
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Mathematician

x^4-9y^4
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Mathematician

x^4-81y^4
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Trainer

(x-3y)(x+3y)(x2+9y2) =(x2-9y2)(x2+9y2) =(x4-81y4) (ans) Thank you.
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