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# The adjacent sides of a rectangle are 16 cm and 8 cm. Find the area of the rectangle.

Tutor

128cm^2

Highly Qualified Tutor

Length of the rectangle = 16 cm Breadth of the rectangle = 8 cm Area of rectangle = (l × b) = (16 × 8) = (128) Area of rectangle is 128

Length of the rectangle = 16 cm

Breadth of the rectangle = 8 cm

$\therefore$ Area of rectangle = (l × b)

= (16 × 8)

= (128)

$\therefore$ Area of rectangle is 128 $cm^{2}$

Tutor

Tutor

The area of a rectangle is equal to the multiplication of two sides i.e. Area = 16*8 sq-cm = 128 sq-cm.

Math Magician

Length of the rectangle = 16 cm Breadth of the rectangle = 8 cm Area of rectangle = (Length × Breadth) = (16 × 8) = 128 Area of rectangle is 128

Length of the rectangle = 16 cm

Breadth of the rectangle = 8 cm

$\therefore$ Area of rectangle = (Length × Breadth)

= (16 × 8)

= 128

$\therefore$ Area of rectangle is 128 $cm^{2}$

Teacher

Area = 16 x 8 = 128 sqm

Tutor

Area = (length*breath) = 16*8 = 128 cm^2.

Maths Tutor

Rectangular shape area= l×b =16×8 =128 cm^2.

Science Teacher

To find out the area of a rectangle you have to multiply its length with its breadth. Here, Length (L)=16 cm, and Breadth (B)=8 cm So area is, A = L*B = 16*8 = 128 sq. cm (Ans)

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