The adjacent sides of a rectangle are 16 cm and 8 cm. Find the area of the rectangle.

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Length of the rectangle = 16 cm Breadth of the rectangle = 8 cm Area of rectangle = (l × b) = (16 × 8) = (128) Area of rectangle is 128
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Length of the rectangle = 16 cm Breadth of the rectangle = 8 cm Area of rectangle = (l × b) = (16 × 8) = (128) Area of rectangle is 128 read less
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Length=16c.m Breadth=8c.m Area =l*b=16*8=128cm sq
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JU-IITKGP & 10+ years experienced for boards, JEE,NEET,OLYMPIAD & 5-12

Given, Length=16 cm Breadth=8cm So, Area=length × breadth =16×8=128 square cm
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128cm^2
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Maths Teacher for Competitive Exams like SSC,BANKING, RAILWAY (With 5 years of experience)

Given, Length=16 cm Breadth=8cm So, Area=length × breadth =16×8=128 square cm
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Area =l*b=16*8=128
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Area of rectangle = l*b =16*8 =128cm^2
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Area of a rectanle =l×b SO 16×8=128
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here length is 16cm and breadth is 8cm now area of rectangle = (l*b) = (16*8) = 128 thank you
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Area of a rectangle is length×breadth Area of a rectangle=16×8=128cm^2
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