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The volume of a right circular cone is 9856 cm3 . If the diameter of the base is 28 cm,
find
(i) height of the cone
(ii) slant height of the cone
(iii) curved surface area of the cone

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(i) Radius of cone = Let the height of the cone be h. Volume of cone = 9856 cm3 h = 48 cm Therefore, the height of the cone is 48 cm. (ii) Slant height (l) of cone Therefore, the slant height of the cone is 50 cm. (iii) CSA of cone = πrl = 2200 cm2 Therefore, the curved surface area of the cone...
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(i) Radius of cone = 

Let the height of the cone be h.

Volume of cone = 9856 cm3

h = 48 cm

Therefore, the height of the cone is 48 cm.

(ii) Slant height (l) of cone 

Therefore, the slant height of the cone is 50 cm.

(iii) CSA of cone = πrl

= 2200 cm2

Therefore, the curved surface area of the cone is 2200 cm2.

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48cm. 50cm. 2200cm sq
Comments

Professional in Adaptive Learning for 8-12th with 11 Yrs of Experience in Quality Teaching

1) height = 48 cm 2) slant height= 50 cm 3) curved surface area = 2200 sq cm
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Professional in Adaptive Learning for 8-12th with 11 Yrs of Experience in Quality Teaching

1) height = 48 cm 2) slant height= 50 cm 3) curved surface area = 2283.69sq m
Comments

Experienced Maths Teacher

(i)V = 1/3 * π* r*r*h 9856 = 1/3 *(22/7) *14*14*h h= (9856*3*7)/(22*14*14) =48 cm (ii) slant height l = √(r*r + h*h) = √ (196+2304) = √2500 = 50 cm (iii) curved surface area π*r*l = (22/7)*14*50 =2200 cm^2
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(i)V = 1/3 * π* r*r*h

9856 = 1/3 *(22/7) *14*14*h

h=  (9856*3*7)/(22*14*14)

=48 cm

(ii) slant height 

l = √(r*r + h*h) = √ (196+2304)

= √2500 = 50 cm

(iii) curved surface area

π*r*l = (22/7)*14*50

=2200 cm^2

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