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Mona A. Class 10 trainer in Bangalore
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Overview

1. Have taught Mathematics in schools in Delhi and Indore.
2. Bachelor's degree in Mathematical Statistics from Lady Shri Ram college, Delhi
3. Masters degree in Operational Research, Delhi University.
4. PG diploma in Computer Science , NIIT, Delhi
5. Have given personalised coaching for class 12 and GRE as well.

Languages Spoken

Hindi Mother Tongue (Native)

English Proficient

Education

Lady Shri Ram College, Delhi University 1989

Bachelor of Arts (honours) Mathematical Statistics

Delhi University 1992

M.A. Operational Research

Address

Ashok Nagar, Bangalore, India - 560025

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Teaches

Class 10 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

20

Board

CBSE

CBSE Subjects taught

Mathematics

Experience in School or College

St. Xavier's school, Delhi Army Public School, Delhi Indore Public School, Delhi

Taught in School or College

Yes

Class 9 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

5

Board

CBSE

CBSE Subjects taught

Mathematics

Experience in School or College

St Xavier's school , Delhi Army Public School, Delhi Indore Public School, Indore

Taught in School or College

Yes

Class 8 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

20

Board

ICSE, CBSE

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

Experience in School or College

St Xavier's school Delhi Army Public School, Delhi Indore Public School, Indore

Taught in School or College

Yes

Teaching Experience in detail in Class 8 Tuition

Have taught in St Xavier's Delhi and Indore Public School, Indore.

Class 7 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

20

Board

ICSE, CBSE

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

Experience in School or College

St Xavier's school Delhi Army Public School, Delhi Indore Public School, Indore

Taught in School or College

Yes

Teaching Experience in detail in Class 7 Tuition

St Xavier's school Delhi Indore Public School Indore

Reviews (7)

4.7 out of 5 7 reviews

Mona A. https://p.urbanpro.com/tv-prod/member/photo/6798328-small.jpg Ashok Nagar
4.7057
Mona A.
H

Class 10 Tuition

"Mona mam is an amazing teacher who would explain what you expect detailedly . She have cleared all my doubts from the beginning. "

Mona A.
S

Class 10 Tuition

"Mona mam's explanation is very fluent and flexible in classes too. Very happy to take classes from her. "

Mona A.
R

Class 7 Tuition

"It's very nice and very happy to hire you for the course to my son. He is happy and still continuing the sessions. "

Mona A.
N

Class 7 Tuition

"Good experience with Ms Mona, My son enjoys the subject now and looks forward to the classes surprisingly. A very hardworking teacher. "

Reply by Mona

Am so happy that he looks forward to studying Maths. Thanks Neha

Have you attended any class with Mona?

FAQs

1. Which school boards of Class 10 do you teach for?

CBSE

2. Do you have any prior teaching experience?

Yes

3. Which classes do you teach?

I teach Class 10 Tuition, Class 7 Tuition, Class 8 Tuition and Class 9 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 20 years.

Answers by Mona (9)

Answered on 26/08/2019 Learn CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.7

V = (pi*r*r*h)/3 = (3.14*5*5*12)/3 = 3.14*100 =314 cu.cm
Answers 3 Comments
Dislike Bookmark

Answered on 13/08/2019 Learn CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.7

V = πr²h/3 1570 = 3.14*r²*15/3 1570 = 15.7r² r² = 100 r = 10 cm
Answers 6 Comments
Dislike Bookmark

Answered on 13/08/2019 Learn CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.7

V = πr²h/3 48π = 9πr²/3 = 3πr² 48/3 = 16 = r² r = 4 cm diameter = 2r = 8cm
Answers 4 Comments
Dislike Bookmark

Answered on 12/08/2019 Learn CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.7

V = (1/3)*π*r*r*h r =10.5/2= 5.25 V= (1/3)*(22/7)*5.25*5.25*3 = 86.625 m^3 Area of the canvas = curved surface of heap = π*r*l l = √(r*r+h*h) = √(36.5625) =6.046 m (approx) πrl = 3.14*5.25*6.046 = 99.668 m^2 ...more

V = (1/3)*π*r*r*h

r =10.5/2= 5.25

V= (1/3)*(22/7)*5.25*5.25*3

= 86.625 m^3

Area of the canvas = curved surface of heap = π*r*l

l = √(r*r+h*h) = √(36.5625)

=6.046 m (approx)

πrl = 3.14*5.25*6.046

= 99.668 m^2

 

Answers 4 Comments
Dislike Bookmark

Answered on 12/08/2019 Learn CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.7

(i)V = 1/3 * π* r*r*h 9856 = 1/3 *(22/7) *14*14*h h= (9856*3*7)/(22*14*14) =48 cm (ii) slant height l = √(r*r + h*h) = √ (196+2304) = √2500 = 50 cm (iii) curved surface area π*r*l = (22/7)*14*50 =2200 cm^2 ...more

(i)V = 1/3 * π* r*r*h

9856 = 1/3 *(22/7) *14*14*h

h=  (9856*3*7)/(22*14*14)

=48 cm

(ii) slant height 

l = √(r*r + h*h) = √ (196+2304)

= √2500 = 50 cm

(iii) curved surface area

π*r*l = (22/7)*14*50

=2200 cm^2

Answers 5 Comments
Dislike Bookmark

Teaches

Class 10 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

20

Board

CBSE

CBSE Subjects taught

Mathematics

Experience in School or College

St. Xavier's school, Delhi Army Public School, Delhi Indore Public School, Delhi

Taught in School or College

Yes

Class 9 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

5

Board

CBSE

CBSE Subjects taught

Mathematics

Experience in School or College

St Xavier's school , Delhi Army Public School, Delhi Indore Public School, Indore

Taught in School or College

Yes

Class 8 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

20

Board

ICSE, CBSE

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

Experience in School or College

St Xavier's school Delhi Army Public School, Delhi Indore Public School, Indore

Taught in School or College

Yes

Teaching Experience in detail in Class 8 Tuition

Have taught in St Xavier's Delhi and Indore Public School, Indore.

Class 7 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

20

Board

ICSE, CBSE

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

Experience in School or College

St Xavier's school Delhi Army Public School, Delhi Indore Public School, Indore

Taught in School or College

Yes

Teaching Experience in detail in Class 7 Tuition

St Xavier's school Delhi Indore Public School Indore

4.7 out of 5 7 reviews

Mona A.
H

Class 10 Tuition

"Mona mam is an amazing teacher who would explain what you expect detailedly . She have cleared all my doubts from the beginning. "

Mona A.
S

Class 10 Tuition

"Mona mam's explanation is very fluent and flexible in classes too. Very happy to take classes from her. "

Mona A.
R

Class 7 Tuition

"It's very nice and very happy to hire you for the course to my son. He is happy and still continuing the sessions. "

Mona A.
N

Class 7 Tuition

"Good experience with Ms Mona, My son enjoys the subject now and looks forward to the classes surprisingly. A very hardworking teacher. "

Reply by Mona

Am so happy that he looks forward to studying Maths. Thanks Neha

Load More
Have you attended any class with Mona?

Answers by Mona A. (9)

Answered on 26/08/2019 Learn CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.7

V = (pi*r*r*h)/3 = (3.14*5*5*12)/3 = 3.14*100 =314 cu.cm
Answers 3 Comments
Dislike Bookmark

Answered on 13/08/2019 Learn CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.7

V = πr²h/3 1570 = 3.14*r²*15/3 1570 = 15.7r² r² = 100 r = 10 cm
Answers 6 Comments
Dislike Bookmark

Answered on 13/08/2019 Learn CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.7

V = πr²h/3 48π = 9πr²/3 = 3πr² 48/3 = 16 = r² r = 4 cm diameter = 2r = 8cm
Answers 4 Comments
Dislike Bookmark

Answered on 12/08/2019 Learn CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.7

V = (1/3)*π*r*r*h r =10.5/2= 5.25 V= (1/3)*(22/7)*5.25*5.25*3 = 86.625 m^3 Area of the canvas = curved surface of heap = π*r*l l = √(r*r+h*h) = √(36.5625) =6.046 m (approx) πrl = 3.14*5.25*6.046 = 99.668 m^2 ...more

V = (1/3)*π*r*r*h

r =10.5/2= 5.25

V= (1/3)*(22/7)*5.25*5.25*3

= 86.625 m^3

Area of the canvas = curved surface of heap = π*r*l

l = √(r*r+h*h) = √(36.5625)

=6.046 m (approx)

πrl = 3.14*5.25*6.046

= 99.668 m^2

 

Answers 4 Comments
Dislike Bookmark

Answered on 12/08/2019 Learn CBSE/Class 9/Mathematics/Surface Area and Volumes/NCERT Solutions/Exercise 13.7

(i)V = 1/3 * π* r*r*h 9856 = 1/3 *(22/7) *14*14*h h= (9856*3*7)/(22*14*14) =48 cm (ii) slant height l = √(r*r + h*h) = √ (196+2304) = √2500 = 50 cm (iii) curved surface area π*r*l = (22/7)*14*50 =2200 cm^2 ...more

(i)V = 1/3 * π* r*r*h

9856 = 1/3 *(22/7) *14*14*h

h=  (9856*3*7)/(22*14*14)

=48 cm

(ii) slant height 

l = √(r*r + h*h) = √ (196+2304)

= √2500 = 50 cm

(iii) curved surface area

π*r*l = (22/7)*14*50

=2200 cm^2

Answers 5 Comments
Dislike Bookmark

Book a Demo

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Mona A. describes herself as Experienced Maths Teacher. She conducts classes in Class 10 Tuition, Class 7 Tuition and Class 8 Tuition. Mona is located in Ashok Nagar, Bangalore. Mona takes Online Classes- via online medium. She has 20 years of teaching experience . Mona has completed Bachelor of Arts (honours) Mathematical Statistics from Lady Shri Ram College, Delhi University in 1989 and M.A. Operational Research from Delhi University in 1992. She is well versed in English and Hindi. Mona has got 7 reviews till now with 100% positive feedback.

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