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The size of isoelectronic species-F–, Ne andNa+is affected by (a) nuclear charge (Z) (b) valence principal quantum number (n) (c) electron-electron interaction in the outer orbitals (d) none of the factors because their size is the same

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a)nuclear charge (Z)
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Ans:a) nuclear charge
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(a) Nuclear Charge (Z) Because although all three elements have same number of electrons but inside nucleus the number of protons in unequal.In case of F- it is having only 9 proton and 10 electron so size will expand liitle.In case of Ne it has 10 proton and 10 electron but will have size smaller than...
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(a) Nuclear Charge (Z) Because although all three elements have same number of electrons but inside nucleus the number of protons in unequal.In case of F- it is having only 9 proton and 10 electron so size will expand liitle.In case of Ne it has 10 proton and 10 electron but will have size smaller than F-.In case of Na+ it will have 11 proton and 10 electron, it means nucleus is more positive than available electrons in orbitals and hence there will be shrinking of size of Na+. F-> Ne > Na+ Size order for these isoelectronic species. read less
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In case of iso electronic species size is inversly proportional to nuclear charge. Answer: a
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