UrbanPro
true

Take Class 10 Tuition from the Best Tutors

  • Affordable fees
  • 1-1 or Group class
  • Flexible Timings
  • Verified Tutors

Learn Mathematics with Free Lessons & Tips

Ask a Question

Post a Lesson

All

All

Lessons

Discussion

Lesson Posted on 05 Jun Learn NCERT Solutions

Vertically opposite angles

T. Rakesh Singh

I am an experienced, qualified teacher and tutor with over 16 years of experience in teaching Maths and...

https://vz-3ad30922-ba4.b-cdn.net/fc3dfd8a-3e1b-4b86-b7b6-cc39c6511906/play_480p.mp4
Comments
Dislike Bookmark

Lesson Posted on 21 May Learn Mathematics

Area of shaded region

Sonal Gupta

Hello Learners! I am Sonal. I am MBA | B.ED having 15yrs of exp. as Math Educator. I am in ed-tech Industry...

https://vz-3ad30922-ba4.b-cdn.net/1fb3edf9-76e0-4f68-8feb-cba42f7adec1/play_480p.mp4
Comments
Dislike Bookmark

Lesson Posted on 29 Apr Learn Mathematics

Algebra Basics - The Product of algebraic expressions

Deeksha

I have approximately 3 years of experience of teaching Mathematics across different boards including...

https://vz-3ad30922-ba4.b-cdn.net/265ba1cb-3752-4f88-bbc9-d6a52bf72398/play_480p.mp4
Comments
Dislike Bookmark

Take Class 10 Tuition from the Best Tutors

  • Affordable fees
  • Flexible Timings
  • Choose between 1-1 and Group class
  • Verified Tutors

Lesson Posted on 21 Apr Learn Mathematics

Probability Brief Lesson plan

Abhishek Sharma

I am a civil engineer graduate currently teaching Mathematics in Cambridge board in Ahmedabad. My key...

Classes explore different scenarios using manipulatives to learn about the difference between independent and dependent probability. Learners experiment with colored chips to model the two types of probabilities. To test their understanding, individuals sort independent and dependent probabilities into... read more

Classes explore different scenarios using manipulatives to learn about the difference between independent and dependent probability. Learners experiment with colored chips to model the two types of probabilities. To test their understanding, individuals sort independent and dependent probabilities into like groups.

 

Real Life Context The following examples could be used to explore real life contexts.

Looking at statistics from the Census, questions like:

• How long will I live?

• Will I get married?

• How many children will I have? These questions can be answered with some degree of certainty based on population statistics. Life assurance companies work out how much to charge for their premiums based on tables of life expectancy. Why are some premiums cheaper than others?

 

The following examples could be used to explore misconceptions:

• What is the most difficult number to get when throwing a fair die?

• Random events should have outcomes which appear random; for example, in the lotto theory tells us that any of the six numbers is equally likely to turn up, yet more people choose randomly spaced numbers than numbers which form a pattern like 1,2,3,4,5,6 etc.

• The likelihood of 2 consecutive numbers appearing in any Lotto draw (which is > 50%) could easily be investigated by reference to a number of recent draws.

read less
Comments
Dislike Bookmark

Answered on 14 Jun Learn Constructions

Adithi S Bhatta

Engineering Student, with 94.5% in 10th Boards and 99th Percentile in JEE Mains

To divide a line segment of 7.6 cm into two parts in the ratio 5:8, the segment is divided into a total of 5+8=13 parts. The length of each part is 7.6 cm/13 ≈0.5846cm The length of the first part (5 parts) is 5×7.6 cm/13 ≈2.923cm The length of the second part (8 parts)... read more

To divide a line segment of 7.6 cm into two parts in the ratio 5:8, the segment is divided into a total of 5+8=13 parts.

The length of each part is 7.6 cm/13 ≈0.5846cm

 

  • The length of the first part (5 parts) is 5×7.6 cm/13 ≈2.923cm
  • The length of the second part (8 parts) is 8×7.6 cm/13 ≈4.677cm

Verifying the Sum:

2.923 cm+4.677 cm≈7.6 cm

 

read less
Answers 1 Comments
Dislike Bookmark

Answered on 14 Jun Learn Constructions

Adithi S Bhatta

Engineering Student, with 94.5% in 10th Boards and 99th Percentile in JEE Mains

I'll provide a step-by-step guide on how you can draw these triangles using basic geometry tools: Ruler Compass Pencil Protractor (optional for verifying angles) First Triangle (sides 5cm, 6cm, 7cm) Construction: Draw the Base (5 cm): Draw a horizontal line segment AB of length 5 cm. Draw an... read more

I'll provide a step-by-step guide on how you can draw these triangles using basic geometry tools:

  • Ruler
  • Compass
  • Pencil
  • Protractor (optional for verifying angles)

First Triangle (sides 5cm, 6cm, 7cm) Construction:

  1. Draw the Base (5 cm):

    • Draw a horizontal line segment AB of length 5 cm.
  2. Draw an Arc (6 cm):

    • Place the compass at point A.
    • Measure 6 cm on the compass.
    • Draw an arc above the line segment AB.
  3. Draw an Arc (7 cm):

    • Place the compass at point BBB.
    • Measure 7 cm on the compass.
    • Draw another arc intersecting the first arc.
  4.  Mark the Intersection (Point C):

    • Label the intersection point of the arcs as C.
  5. Complete the Triangle:

    • Draw line segments AC and BC to complete the triangle ABC.

Second Triangle (sides 4/5th of Frist Triangle) Construction:

1. Calculate the Scaled Sides: The sides of the scaled triangle are 4/5 of the corresponding sides of the first triangle.

  • 4/5×5 cm=4cm
  • 4/5×6 cm=4.8cm
  • 4/5×7 cm=5.6 cm

2Measure and Draw the Scaled Sides:

  1. Draw the Base (4 cm):
    Draw a horizontal line segment DE of length 4 cm.

  2. Draw an Arc (4.8 cm):

    • Place the compass at point D.
    • Measure 4.8 cm on the compass.
    • Draw an arc above the line segment DE.
  3. Draw an Arc (5.6 cm):

    • Place the compass at point E.
    • Measure 5.6 cm on the compass.
    • Draw another arc intersecting the first arc.
  4. Mark the Intersection (Point F):

    • Label the intersection point of the arcs as F.
  5. Complete the Triangle:

    • Draw line segments DF and EF to complete the triangle DEF.

 

read less
Answers 1 Comments
Dislike Bookmark

Take Class 10 Tuition from the Best Tutors

  • Affordable fees
  • Flexible Timings
  • Choose between 1-1 and Group class
  • Verified Tutors

Answered on 16 May Learn Constructions

Pranjal B.

To construct a triangle Δ���ΔABC with ��=6AB=6 cm, ∠�=30∘∠A=30∘, and ∠�=60∘∠B=60∘, follow these steps: Draw a line segment ��AB of length 6 cm. At point �A, construct an angle of 30∘30∘. At point �B, construct an angle of 60∘60∘. Label the intersection of the... read more

To construct a triangle Δ���ΔABC with ��=6AB=6 cm, ∠�=30∘∠A=30∘, and ∠�=60∘∠B=60∘, follow these steps:

  1. Draw a line segment ��AB of length 6 cm.
  2. At point �A, construct an angle of 30∘30∘.
  3. At point �B, construct an angle of 60∘60∘.
  4. Label the intersection of the two constructed angles as �C.
  5. Connect points �A and �C, as well as points �B and �C.

To construct a similar triangle Δ��′�′ΔAB′C′ with base ��′=8AB′=8 cm, follow these steps:

  1. Extend ��AB to the right to create ��′AB′ of length 8 cm.
  2. At point �A, construct an angle of 30∘30∘.
  3. At point �′B′, construct an angle of 60∘60∘.
  4. Label the intersection of the two constructed angles as �′C′.
  5. Connect points �A and �′C′, as well as points �′B′ and �′C′.

Both triangles will be similar because they have corresponding angles of the same measure.

 
 
 
 
read less
Answers 2 Comments
Dislike Bookmark

Answered on 29 Apr Learn Areas related to circles

Aniruddha Singh

PCM sream in 11 , Preparing for JEE

154/3 cm2 EXPLANATION:- Minute hand complete full circle in 1 hour. Angle swept by minute in 1 hour (60 min)=360o Angle swept by minute hand in 1 min=36060=6o Angle swept by minute hand in 5 min=6×5=30o θ=30o,r=14 cm Area swept by minute hand = Area of sector =θ360×πr2 ... read more

154/3 cm2

EXPLANATION:-

Minute hand complete full circle in 1 hour.

 
Angle swept by minute in 1 hour (60 min)=360o
 
Angle swept by minute hand in 1 min=36060=6o
 
Angle swept by minute hand in 5 min=6×5=30o
 
θ=30o,r=14 cm
 
Area swept by minute hand = Area of sector
 
=θ360×πr2
 
=30360×227×(14)2
 
=112×227×14×14
 
Area swept by minute hand =1543 cm2
read less
Answers 2 Comments
Dislike Bookmark

Answered on 29 Apr Learn Areas related to circles

Aniruddha Singh

PCM sream in 11 , Preparing for JEE

Let the radius of the circle is =r cm Circumference of the circle =22 cm ⇒2πr=22 2×227×r=22 r=72 cm Area of the quadrant =πr24 =227×14×72×72 =778 cm2 read more
Let the radius of the circle is =r cm
 
Circumference of the circle =22 cm
 
2πr=22
 
2×227×r=22
 
r=72 cm
 
Area of the quadrant =πr24
 
=227×14×72×72
 
=778 cm2
read less
Answers 2 Comments
Dislike Bookmark

Take Class 10 Tuition from the Best Tutors

  • Affordable fees
  • Flexible Timings
  • Choose between 1-1 and Group class
  • Verified Tutors

Answered on 19 Apr Learn Probability

Sadika

To find the probability of getting a number less than 3 when a die is thrown once, we need to determine the total number of favorable outcomes (rolling a number less than 3) and divide it by the total number of possible outcomes (rolling any number on the die). Given: The die has 6 faces numbered 1... read more

To find the probability of getting a number less than 3 when a die is thrown once, we need to determine the total number of favorable outcomes (rolling a number less than 3) and divide it by the total number of possible outcomes (rolling any number on the die).

Given:

  • The die has 6 faces numbered 1 through 6.
  1. Total number of possible outcomes: There are 6 possible outcomes when rolling a die.

  2. Number of favorable outcomes (rolling a number less than 3): There are 2 favorable outcomes: rolling a 1 or rolling a 2.

Now, let's calculate the probability of getting a number less than 3:

read less
Answers 1 Comments
Dislike Bookmark

About UrbanPro

UrbanPro.com helps you to connect with the best Class 10 Tuition in India. Post Your Requirement today and get connected.

Overview

Questions 1.6 k

Lessons 189

Total Shares  

+ Follow 117,479 Followers

You can also Learn

Top Contributors

Connect with Expert Tutors & Institutes for Mathematics

x

Ask a Question

Please enter your Question

Please select a Tag

X

Looking for Class 10 Tuition Classes?

The best tutors for Class 10 Tuition Classes are on UrbanPro

  • Select the best Tutor
  • Book & Attend a Free Demo
  • Pay and start Learning

Take Class 10 Tuition with the Best Tutors

The best Tutors for Class 10 Tuition Classes are on UrbanPro

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more