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# 3. The length of the minute hand of a clock is 14 cm. Find the area swept by the minute hand in 5 minutes.

PCM sream in 11 , Preparing for JEE

154/3 cm2 EXPLANATION:- Minute hand complete full circle in 1 hour. Angle swept by minute in 1 hour (60 min)=360o Angle swept by minute hand in 1 min=36060=6o Angle swept by minute hand in 5 min=6×5=30o θ=30o,r=14 cm Area swept by minute hand = Area of sector =θ360×πr2 ...

154/3 cm2

EXPLANATION:-

#### Minute hand complete full circle in 1 hour.

Angle swept by minute in 1 hour (60 min)=360o

Angle swept by minute hand in 1 min=36060=6o

Angle swept by minute hand in 5 min=6×5=30o

θ=30o,r=14 cm

Area swept by minute hand = Area of sector

=θ360×πr2

=30360×227×(14)2

=112×227×14×14

Area swept by minute hand =1543 cm2

To find the area swept by the minute hand in 5 minutes, we need to consider the area covered by the sector formed by the minute hand during that time.

To find the area swept by the minute hand in 5 minutes, we need to consider the area covered by the sector formed by the minute hand during that time.
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